小编Har*_*pal的帖子

I'm currently attempting to set a Cookie header with the following HTTPInterceptor:

@Injectable()
export class TokenInterceptor implements HttpInterceptor {
  constructor(private cookieService: CookieService ) {}

  intercept(request: HttpRequest<any>, next: HttpHandler): Observable<HttpEvent<any>> {
    request = request.clone({
      setHeaders: {
        'Cookie': 'session=' + this.cookieService.get('session'),
        'withCredentials': 'true',
      }
    });
    return next.handle(request);
  }

}

When attempting to set the Cookie I get the following error:

Refused to set unsafe header "Cookie"

I'm making the request to a local Flask API.

I have attempted to manually set …

我有一个results.txt看起来像这样的文件:

[["12 - 22 - 30 - 31 - 34 - 39 - 36"],
["13 - 21 - 28 - 37 - 39 - 45 - 6"],
["2 - 22 - 32 - 33 - 37 - 45 - 11"],
["3 - 5 - 11 - 16 - 41 - 48 - 32"],
["2 - 3 - 14 - 29 - 35 - 42 12"],
["14 - 30 - 31 - 36 - 44 - 47 26"]]

我想用'","'替换results.txt文件中的" …

我试图创建一些列表,具体取决于我的header_count中的数字.下面的代码应该生成3个列表,但我得到语法错误.

header_count = 4
for i in range(1, header_count):
    header_%s = [] % i

我在R中生成了以下图表:

在Y轴上,我有蛋白质名称以及以.pdb结尾的文件名.如何在一行上生成蛋白质名称,在下一行中创建文件名？

我使用以下命令生成图:

library(lattice) <br>
data <- read.table("~/Documents/R/test.txt", header=F, sep="\t") <br>
dotplot(V1~V2, xlim=c(0, 2.5), xlab="RMSD Distribution", data=data)

示例输入文件如下所示:

Serum Amyloid P Pentamer: 1sac.pdb  0.7125  <br>
Serum Amyloid P Pentamer: 1sac.pdb  0.7917  <br>
Serum Amyloid P Pentamer: 1sac.pdb  0.7819  <br>
Serum Amyloid P Pentamer: 1sac.pdb  0.7762  <br>
Serum Amyloid P Pentamer: 1sac.pdb  1.0233  <br>
Serum Amyloid P Pentamer: 1sac.pdb  0.6896  <br>

不显示值和文件之间的选项卡.

当我在下面运行我的代码时,我得到了一个:ValueError: invalid literal for int() with base 10: '0.977759164126'但我不知道为什么

file_open = open("A1_B1_1000.txt", "r")
file_write = open ("average.txt", "w")

line = file_open.readlines()
list_of_lines = []
length = len(list_of_lines[0])
total = 0


for i in line:
    values = i.split('\t')
    list_of_lines.append(values)

count = 0
for j in list_of_lines:
    count +=1

for k in range(0,count):
    print k
    list_of_lines[k].remove('\n')



for o in range(0,count):
    for p in range(0,length):
        print list_of_lines[p][o]
        number = int(list_of_lines[p][o])    
        total + number
    average = total/count
    print average

我的文本文件如下:

0.977759164126 0.977759164126 …

我使用以下代码来组合两个文本文件:

def combine_acpd_ccs(self, ccs_file, acps_file, out_file):

    with open(ccs_file, 'r') as in_file1:
        with open(acps_file, 'r') as in_file2:
            with open(out_file, 'w') as out1:
                out1.write('PDB\tPA\tEHSS\tACPS\n')
                for line in in_file1:
                    segs = line.split()
                    for i in in_file2:
                        sse_score = i.split()
                        #print line
                        #print segs
                        if segs[0][:-4] == sse_score[0]:
                            out1.write(segs[0][:-4]+'\t'+segs[1]+'\t'+segs[2]+'\t'+sse_score[1]+'\n')

示例数据如下所示:

ccs_file:

1b0o.pdb    1399.0  1772.0
1b8e.pdb    1397.0  1764.0

acps_file:

1b0o    0.000756946316066
1b8e    8.40662008775
1b0o    6.25931529116

我期待我的表现如下:

PDB PA  EHSS    ACPS
1b0o    1399.0  1772.0  0.000756946316066
1b0o    1399.0  1772.0  6.25931529116
1b8e    1397.0  1764.0 8.40662008775

但是我的代码只生成了我预期输出的前两行.如果我segs在第二个 …

我有一个atoms.out执行某些功能的fortran 文件.我在python中调用fortran文件:

values = subprocess.Popen(["./atoms.out", "./%s.klj" % test1, "./%s.out" % test1], stdout = subprocess.PIPE)

我看过Python PP,但我认为这不是我要找的,因为它为一个作业使用了n个CPU.

fortran文件进行的计算不是独立的,不能用于 python pp

所以我的问题是如何将一些作业提交给许多不同的CPU,例如我有:7个文件,我希望在4个CPU上运行.

因此,每项工作分配如下:

File1 -> CPU1
File2 -> CPU2
File3 -> CPU3
File4 -> CPU4

然后,当一个作业在CPU上完成时,它将替换为剩余的3个要运行的文件.说File1在完成CPU1它被更换File5,所以作业的分配将是这样的:

File5 -> CPU1
File2 -> CPU2
File3 -> CPU3
File4 -> CPU4

等等,直到它完成了对7个文件运行fortran文件.