我看到了这篇很棒的文章:http://pdimov.com/cpp2/simple_cxx11_metaprogramming.html
在以下代码中:
template<class A, template<class...> class B> struct mp_rename_impl;
template<template<class...> class C, class... T, template<class...> class B>
struct mp_rename_impl<C<T...>, B>
{
using type = B<T...>;
};
template<class A, template<class...> class B>
using mp_rename = typename mp_rename_impl<A, B>::type;
//...
mp_rename<mp_list<int, float, void*>, std::tuple>; // -> std::tuple<int, float, void*>
// T... will be deduced as int, float, void*
为什么C被推导为mp_list(而不是mp_list <int,float,void*>)和T ...作为int,float,void*？
我认为诀窍是模板特化部分: struct mp_rename_impl <C <T ...>,B>,但我很难理解为什么