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我有一个 SOAPHandler。我需要捕获响应的请求

public class SOAPLoggingHandler implements SOAPHandler<SOAPMessageContext> {

    @Override
    public boolean handleFault(SOAPMessageContext context) {
        writeMessageLogging(context);
        return true;
    }
    public boolean handleMessage(SOAPMessageContext context) {
        writeMessageLogging(context);
        return true;
    }

    private void writeMessageLogging(SOAPMessageContext smc) {
        Boolean outboundProperty = (Boolean) smc
                .get(MessageContext.MESSAGE_OUTBOUND_PROPERTY);

        if (logger.isDebugEnabled()) {
            if (outboundProperty.booleanValue()) {
                logger.debug("Request message");
            } else {
                logger.debug("Response message:");
            }
        }
        SOAPMessage message = smc.getMessage();
        ByteArrayOutputStream out=null;
        try {
            if (!outboundProperty.booleanValue()) {
                String requestXML="Request of the Response, is possible?";
            }
                out = new ByteArrayOutputStream();
             message.writeTo(out);
             String strMsg = …

我有一个脚本：

newerthan="2016-02-08"
olderthan="2016-04-29"
find / -type f -name "*" -newermt "$newerthan" ! -newermt "$olderthan" -ls

该列表文件：

16481    0 -r--r--r--   1 root     root         4096 Mar 16 11:41 /sys/module/sunrpc/srcversion
 16482    0 -r--r--r--   1 root     root         4096 Mar 13 04:42 /sys/module/sunrpc/initstate
 16483    0 -r--r--r--   1 root     root         4096 Mar 16 11:41 /sys/module/sunrpc/refcnt
 16485    0 -r--r--r--   1 root     root         4096 Mar 17 11:41 /sys/module/sunrpc/sections/.note.gnu.build-id
 16486    0 -r--r--r--   1 root     root         4096 Mar 12 11:41 /sys/module/sunrpc/sections/.text

是否可以按日期、结果排序？