小编Kwi*_*ski的帖子

我尝试做脚本:

#!/bin/bash
IP='192.168.1.1'
fping -c1 -t300 $IP 2>/dev/null 1>/dev/null
if [ "$?" = 0 ]
then
    echo "Host found"
else
    echo "Host not found"
fi

我把它转过来:

pi@raspberrypi ~ $ sh /home/pi/sh/test.sh

/home/pi/sh/test.sh: 9: /home/pi/sh/test.sh: Syntax error: "fi" unexpected (expecting "then")

问题出在哪儿？

我正在尝试编写一个将在后台播放广播的脚本

#!/bin/sh

for (( i = 80 ; i <= 101; i++ )) 
 do 
  amixer cset numid=1 i$% sleep 60;
done 

但我有问题:

alarmclock-vol.sh: 3: alarmclock-vol.sh: Syntax error: Bad for loop variable

我有这样的事情:

public class MainActivity extends AppCompatActivity {

private WebView mWebView;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    mWebView = (WebView) findViewById(R.id.activity_main_webview);

    WebSettings webSettings = mWebView.getSettings();
    webSettings.setJavaScriptEnabled(true);

    mWebView.loadUrl("http://kwiatkowski.co/");

    mWebView.setWebViewClient(new WebViewClient());
}

@Override
public void onBackPressed() {
    if(mWebView.canGoBack()) {
        mWebView.goBack();
    } else {
        super.onBackPressed();
    }
}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    getMenuInflater().inflate(R.menu.menu_main, menu);
    return true;
}

@Override
public boolean onOptionsItemSelected(MenuItem item) {
    int id = item.getItemId();

    if (id == R.id.action_settings) {
        return true;
    }

    return super.onOptionsItemSelected(item);
}

}

一切只在目标网站上运行的将是动态内容和图表.如何在恢复时让应用程序重新加载页面,或者我将进入应用程序？