小编Tim*_*çin的帖子

我有这样的枚举和财产.

        public enum Type
        {
            Hourly = 1,
            Salary = 2,
            None = 3
        };


        public string EmployeeType
        {
            get
            {
                string type;
                switch (employeeType)
                {
                    case Type.Hourly:
                        type = "Hourly Employee";
                        break;
                    case Type.Salary:
                        type = "Salary Employee";
                        break;
                    default:
                        type = "None";
                        break;
                }
                return type;
            }

            // **EDIT:**
            // Now I am trying to parse the string as enum Type.
            // But Constructor still waits a string to set EmployeeType.
            set
            {
                employeeType = (Type)Enum.Parse(typeof(Type), value);
            } …

我的数据库中有以下表格,我无法更改或修改.我保持Log表格简单但LogDetail与我的数据库中的相同.

记录表

 Id  User Department Service     Method

 21  John Sales      UserService GetUser

LogDetail表

Id LogRef ParamName  ParamValue

30 21     FirstName  Adam
31 21     LastName   Smith     
32 21     Age        35
33 21     Gender     M

现在,我正在使用以下查询来搜索谁(Adam,Smith,35,M)

SELECT 
L.*, D1.ParamName, D2.ParamName, D3.ParamName, D4.ParamName
FROM Log as L
INNER JOIN LogDetail as D1 on L.Id = D1.LogRef
INNER JOIN LogDetail as D2 on L.Id = D2.LogRef
INNER JOIN LogDetail as D3 on L.Id = D3.LogRef
INNER JOIN LogDetail as D4 …

我对 SQL SERVER 功能有一个简单的问题charindex。

DECLARE @VAR1 varchar
SET @VAR1 = 'abcdef'
PRINT CHARINDEX('c', @VAR1)

上面的语句应该打印3但打印0。为什么？

    // Hideously slow program! Can you spot the object creation?
    Long sum = 0L;
    for (long i = 0; i < Integer.MAX_VALUE; i++) {
        sum += i;
    }
    end = System.currentTimeMillis();
    System.out.println("Long sum took: " + (end - start) + " milliseconds");

    long sum2 = 0L;
    for (long i = 0; i < Integer.MAX_VALUE; i++) {
        sum2 += i;
    }
    end = System.currentTimeMillis();
    System.out.println("long sum took: " + (end - start) + " milliseconds");

嗨,我正在阅读有效的Java,并且Item 6:Avoid creating unnecessary objects …