小编asi*_*man的帖子

我正在向指针传递一个更新它的函数.但是,当函数返回指针时,它返回到函数调用之前的值.

这是我的代码:

#include <stdio.h>
#include <stdlib.h>

static void func(char *pSrc) {
    int x;
    for ( x = 0; x < 10; x++ ) {
        *pSrc++;
    }

    printf("Pointer Within Function: %p\n", pSrc  );
}

int main(void) {

    char *pSrc = "Good morning Dr. Chandra. This is Hal. I am ready for my first lesson.";

    printf("Pointer Value Before Function: %p\n", pSrc  );

    func(pSrc);

    printf("Pointer Value After Function: %p\n", pSrc  );

    return EXIT_SUCCESS;
}

这是输出

Pointer Value Before Function: 0x100403050
Pointer Within Function: …