小编brf*_*fox的帖子

我试图动态地在Django中构建一个查询.我有很多我想构建查询的模型,但我不想编写模型的名称,我想将其作为字符串传递.

from django.db.models.query import QuerySet
a_works = QuerySet(model_A)
a_doesnt_work = QuerySet("model_A")  # I want this to work, too

a_works.filter(pk=23)   # no error
a_doesnt_work.filter(pk=23)   # error: AttributeError: 'str' object has no attribute '_meta'

# then I am dynamically filtering different fields, which works fine with a_works
kwargs = { "%s__%s" % (field, oper) : val }
results = a_works.filter( **kwargs )

有没有办法让动态模型选择工作？