我的代码
$order[$j][0]="Euclidean Geomethiyil Kodpagugal";
$order[$j][1]=$q16;
$j++;
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隐藏的领域 -
<input type="hidden" name="hdnTotal" value="<?php echo $gtot; ?>">
<input type="hidden" name="hdnOrder" value="<?php echo $order; ?>">
<input type="submit" value="Place Order">
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hdnTotal价值即将出现在下一页但hdnOrder不是.print($_POST['hdnOrder'])仅Array在屏幕上打印.
我得到了一些推特更新的代码 -
function twitit() {
global $wp_query;
$thePostName = $wp_query->post->post_name;
echo '<div id="twitit"><a href="http://twitter.com/home?status=Currently reading '.$thePostName.' : '.get_permalink($post->ID).'" title="Click to send this page to Twitter!" target="_blank">Share on Twitter</a></div>';
}
function widget_twitit($args) {
extract($args);
echo $before_widget;
echo $before_title;
echo $after_title;
twitit();
echo $after_widget;
}
function twitit_init() {
register_sidebar_widget(__('Twit It'), 'widget_twitit');
}
add_action("plugins_loaded", "twitit_init"); //line 30
?>
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致命错误:在第30行的C:\ xampp\htdocs\shizin\twitter.php中调用未定义的函数add_action()
我的代码 -
$things = mysql_real_escape_string(implode(',', $_POST['things']),$link);
$q = "INSERT INTO tblslider(src) VALUES ('".$things."')";
print_r($q);
$result = $mysqli->query($q) or die(mysqli_error($mysqli));
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但是我的查询正在生成,
INSERT INTO tblslider(src) VALUES ('4368122.jpg,5440051.jpg,1047428.jpg') 但应该是
INSERT INTO tblslider(src) VALUES ('4368122.jpg'),('5440051.jpg'),('1047428.jpg')因为它将它作为一个记录而不是三个.