小编Eug*_* G.的帖子

我在ViewController中有全局观察者,并且需要一些不同的观察者来获取特定值,如下所示.一次值改变后是否可以删除观察者？

var ref = Firebase(url: "https://<FIREBASE-APP>.firebaseio.com/")

let handle = ref.observeEventType(.Value, withBlock: { snapshot in

    //Here VALUE Changes to NEW_VALUE
    if snapshot.value as! String == NEW_VALUE {

        //IS IT POSSIBLE TO REMOVE HANDLE HERE????
        ...something here
    }

})

//NOT HERE
...ref.removeObserverWithHandle(handle)

我最近在 macOS Sierra for iOS 上从这里编译了一个 WebRTC.framework 。用现有 xcode 项目中的新框架替换旧框架，视频变得非常慢，并出现以下错误：

(RTCLogging.mm:31): (RTCCameraVideoCapturer.m:207 - [RTCCameraVideoCapturer captureOutput:didDropSampleBuffer:fromConnection:]): Dropped sample buffer.

(frame_buffer2.cc:208): A frame about to be decoded is out of the configured delay bounds (16067 > 10000). Resetting the video jitter buffer.

有什么想法会导致问题吗？

谢谢。

我刚开始玩Quickblox.我创建了3个用户,无法从数据库中获取任何用户.任何想法,将不胜感激.(frameworkVersion 2.6.4)

 [QBRequest logInWithUserLogin: self.loginTextField.text password:self.passwordTextField.text successBlock:^(QBResponse * _Nonnull response, QBUUser* _Nullable user) {

        NSLog(@"+++LOGGED IN:%@", response);


        //Getting all users
        QBGeneralResponsePage *page = [QBGeneralResponsePage responsePageWithCurrentPage:1 perPage:100];
        [QBRequest usersForPage:page successBlock:^(QBResponse *response, QBGeneralResponsePage *pageInformation, NSArray *users) {
         NSLog(@"+++GOT %lu Users",(unsigned long)users.count);
       } errorBlock:^(QBResponse *response) {
                 NSLog(@"---NO Users:%@",response.error);
        }];




    } errorBlock:^(QBResponse * _Nonnull response) {
        NSLog(@"NOT --- LOGGED IN:%@", response.error);
      }];

控制台输出:

  +++LOGGED IN:[QBResponse], status: 202 
  ---NO Users:
   Error reasons:{
     errors =     {
       base =         (
          Forbidden
        );
     };
   }