我知道已经有很多关于这个主题的疑问，我已经尝试了每一步，但仍然无法解决问题。
这是代码：
render() {
const {sContainer, sSearchBar} = styles;
if (this.props.InviteState.objectForDeleteList){
this.updateList(this.props.InviteState.objectForDeleteList);
}
return (
<View style={styles.mainContainer}>
<CustomNavBar
onBackPress={() => this.props.navigation.goBack()}
/>
<View
style={sContainer}
>
<ScrollView keyboardShouldPersistTaps="always">
<TextInput
underlineColorAndroid={'transparent'}
placeholder={'Search'}
placeholderTextColor={'white'}
selectionColor={Color.colorPrimaryDark}
style={sSearchBar}
onChangeText={(searchTerm) => this.setState({searchTerm})}
/>
</ScrollView>
{this.renderInviteUserList()}
</View>
</View>
);
}
renderInviteUserList() {
if (this.props.InviteState.inviteUsers.length > 0) {
return (
<SearchableFlatlist
searchProperty={'fullName'}
searchTerm={this.state.searchTerm}
data={this.props.InviteState.inviteUsers}
containerStyle={styles.listStyle}
renderItem={({item}) => this.renderItem(item)}
keyExtractor={(item) => item.id}
/>
);
}
return (
<View style={styles.emptyListContainer}>
<Text style={styles.noUserFoundText}>
{this.props.InviteState.noInviteUserFound}
</Text>
</View>
);
}
renderItem(item) {
return …我想创建一个按钮,当按下按钮时会改变尺寸(稍微小一点),然后再次释放按钮后,尺寸应该变回正常尺寸.我使用Scale xml来实现这一目标,但它重新定位了自己如果我不释放按钮.
按钮在这里我指的是imageview.
这是我的源代码: -
imgSpin = (ImageView) findViewById(R.id.iv_spins);
imgSpin.setOnTouchListener(new View.OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
imgSpin.startAnimation(mAnimation);
spinslot();
break;
case MotionEvent.ACTION_UP:
imgSpin.clearAnimation();
imgSpin.setEnabled(false);
break;
}
return true;
}
});
我的规模Xml: -
<scale xmlns:android="http://schemas.android.com/apk/res/android"
android:duration="200"
android:fromXScale=".8"
android:fromYScale=".8"
android:pivotX="50%"
android:pivotY="50%"
android:toXScale="1.0"
android:toYScale="1.0" >
</scale>
我的XML: -
<LinearLayout
android:id="@+id/layout_status"
android:layout_width="match_parent"
android:layout_height="0dp"
android:layout_weight=".2"
android:orientation="horizontal" >
<View
android:layout_width="0dp"
android:layout_height="wrap_content"
android:layout_weight=".5" />
<ImageView
android:layout_width="0dp"
android:layout_height="wrap_content"
android:layout_weight="2.1"
android:background="@drawable/bootser" />
<LinearLayout
android:layout_width="0dp"
android:layout_height="wrap_content"
android:layout_weight="2.5"
android:background="@drawable/bet_bg"
android:gravity="center_vertical"
android:orientation="horizontal"
android:weightSum="1" > …我正在尝试开发这个拍照的简单应用程序.一切都好.唯一的东西我在预览的中心有一个固定大小的椭圆形 imageview.图像的捕获工作正常,但问题是我想捕捉图像并自动裁剪它位于椭圆形imageview内.我不想要整个图像要保存,我只想要形状内部的图像部分.现在,我不知道该怎么办.花了几个小时在Google上寻求解决方案后,我决定放弃并来到这里.我不知道如何才能得到形状内部的那部分图像(那固定的椭圆形图像).
这是我的代码: -
public class MainActivity extends Activity implements SurfaceHolder.Callback {
Camera camera;
SurfaceView surfaceView;
SurfaceHolder surfaceHolder;
boolean cameraview = false;
LayoutInflater inflater = null;
private ImageView ImgContainer;
private Button btn;
private ImageView mIvCaptureImage;
FrameLayout frameLayout;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
setRequestedOrientation(ActivityInfo.SCREEN_ORIENTATION_PORTRAIT);
getWindow().setFormat(PixelFormat.UNKNOWN);
frameLayout = (FrameLayout) findViewById(R.id.view);
surfaceView = (SurfaceView) findViewById(R.id.camera_preview);
ImgContainer = (ImageView) findViewById(R.id.Img_container);
surfaceHolder = surfaceView.getHolder();
surfaceHolder.addCallback(this);
surfaceHolder.setType(SurfaceHolder.SURFACE_TYPE_PUSH_BUFFERS);
// GuideBox box = new GuideBox(MainActivity.this); …android image android-custom-view android-camera android-imageview
我在我的android应用程序中使用quickblox.我能够注册,登录用户,甚至添加自定义对象并从quick-blox服务器检索它们,但在聊天列表屏幕中,我的计数出错了.
我对未读计数有疑问
这是我的代码流程: -
public class ConversationFragment extends Fragment implements Observer, DialogsManager.ManagingDialogsCallbacks {
ConversationViewModel conversationViewModel;
FragmentConversationBinding binding;
QBChatDialogMessageListener allDialogsMessagesListener;
SystemMessagesListener systemMessagesListener;
QBSystemMessagesManager systemMessagesManager;
QBIncomingMessagesManager incomingMessagesManager;
private DialogsManager dialogsManager;
public ConversationFragment() {
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
binding = DataBindingUtil.inflate(inflater, R.layout.fragment_conversation, container, false);
getActivity().getWindow().setBackgroundDrawableResource(R.drawable.bg_img);
View view = binding.getRoot();
systemMessagesListener = new SystemMessagesListener();
dialogsManager = new DialogsManager();
return view;
}
private void setUpModel() {
Bundle mBundle = getArguments();
if (mBundle != null) {
conversationViewModel = …我是新来的，并试图自己学习，我在将用户从嵌套的 stck 导航器屏幕导航回根屏幕时遇到了问题。
这是我的一些课程：-
index.android.js :-
import React, { Component } from 'react';
import {
AppRegistry,
StyleSheet,
Text,
StatusBar,
View
} from 'react-native';
import {LoginStack} from './login/loginregisterrouter';
import {StackNavigator } from 'react-navigation';
class reactNavigationSample extends Component {
render(){
return (
<LoginStack/>
);
}
}
AppRegistry.registerComponent('MssReactDemo', () => reactNavigationSample);
登录注册路由器：-
import React from 'react';
import {StackNavigator } from 'react-navigation';
import LoginScreen from './LoginScreen';
import RegisterScreen from './RegisterScreen';
import NavigationContainer from './navigationContainer';
export const LoginStack = StackNavigator({
LoginScreen: {
screen: LoginScreen, …