小编Dre*_*208的帖子

以前曾经问过,我做了所有建议的评论,但似乎都没有.我有一个问题的组合.让wallaby.js使用我的项目并在运行时找出错误ng test.

Can't bind to 'routerLink' since it isn't a known property of 'a'. ("<header id="header">                                                                                         <h1 id="logo">                                                                                                                                                                    <a [ERROR ->][routerLink]="['/home']"></a>                                                                                                        
                </h1>
        "): AppComponent@2:5
        Can't bind to 'routerLink' since it isn't a known property of 'a'. ("
                <div id="menu">
                        <a [ERROR ->][routerLink]="['/home']" class="btn">Home</a>
                        <a [routerLink]="['/about']" class="btn">About</a>
                        "): AppComponent@6:5
        Can't bind to 'routerLink' since it isn't a known property of 'a'. ("
                <div id="menu">
                        <a [routerLink]="['/home']" class="btn">Home</a>
                        <a [ERROR ->][routerLink]="['/about']" class="btn">About</a>
                        <a [routerLink]="['/experiments']" class="btn">Expe"): AppComponent@7:5
        Can't bind to 'routerLink' …

下面的代码只工作了一次，现在突然没有显示兴趣点（POI）。我在两台不同的机器上尝试过，但得到了相同的行为。这就是让我困惑的地方，是代码还是我的模拟器设置。

我清理了项目，确保我有自定义的模拟器。我确实现在突然打印了经度和纬度，它也没有在控制台中打印。

导入 UIKit 导入 MapKit 导入 CoreLocation

类 MapViewController: UIViewController, CLLocationManagerDelegate {

@IBOutlet var map: MKMapView!

var manager:CLLocationManager!
var latitude:Double = 0.0
var longitude:Double = 0.0
var location:Double = 0.0

override func viewDidLoad() {
    super.viewDidLoad()
    print("init")
    manager = CLLocationManager()
    manager.delegate = self
    manager.desiredAccuracy - kCLLocationAccuracyBest
    manager.requestWhenInUseAuthorization()
}

func locationManager(manager: CLLocationManager, didUpdateLocations locations: [CLLocation]) {

    print("test test test")

    let userLocation:CLLocation = locations[0]
    self.latitude = userLocation.coordinate.latitude
    self.longitude = userLocation.coordinate.longitude

    let request = MKLocalSearchRequest()
    request.naturalLanguageQuery = "Army Recruiting"

    request.region = MKCoordinateRegionMakeWithDistance(userLocation.coordinate, 1600, …

我收到以下错误：

java.lang.IllegalArgumentException: org.hibernate.QueryException: unexpected char:

 SELECT NEW com.classes.applicant.ApplicantEntry(app.indSsn, app.indivName, app.indAddrLocTx,app.indAddrCityNm,app.indAdrStateAb,app.indAddrZipCd, app.phoneNr,app.workPhoneNr) FROM TApplicant app WHERE app.indSsn = :ssn

类构造函数是正确的：

public ApplicantEntry(String indSsn, String indivName, String indAddrLocTx, String indAddrCityNm, String indAdrStateAb, String indAddrZipCd,
                                 String phoneNr, String workPhoneNr) {
        this.indSsn = indSsn;
        this.indivName = indivName;
        this.indAddrLocTx = indAddrLocTx;
        this.indAddrCityNm = indAddrCityNm;
        this.indAdrStateAb = indAdrStateAb;
        this.indAddrZipCd = indAddrZipCd;
        this.phoneNr = phoneNr;
        this.workPhoneNr = workPhoneNr;

    }

和实体：

@Entity
@Table(name = "T_APPLICANT", schema = "APP")
public class TApplicant implements Serializable, Applicant {
    private static final …

我有这个错误超过一天,我不知道为什么.

app.module

import {NgModule} from "@angular/core";
import {BrowserModule} from "@angular/platform-browser";
import {AppComponent} from "./app.component";
import {FormsModule} from "@angular/forms";
import {LoginComponent} from "./Login/login";
import {LoginService} from "./Login/login.service";

@NgModule({
    imports: [BrowserModule, FormsModule],

    declarations: [AppComponent,
        LoginComponent],

    providers:[LoginService],

    bootstrap: [AppComponent]
})
export class AppModule {

}

app.component.ts

import { Component } from '@angular/core';

@Component({
    selector: 'my-app',
    template: '<login></login>'
})
export class AppComponent {

}

login.model.ts

export class LoginModel{

    private userName: string;
    private password: string;

    constructor(userName: string='', password: string=''){
        this.userName = userName;
        this.password = password; …

运行时出现以下错误

kubectl create -f pod.yaml

错误

Error from server (BadRequest): error when creating "pod.yaml": Pod in 
version "ratings:v1" cannot be handled as a Pod: no kind "Pod" is 
registered for version "ratings:v1"

minikube已启动并正在运行，我什至试图将其更改为，kind: Deployment但又出现了另一个错误：

error: unable to recognize "pod.yaml": no matches for /, Kind=Deployment

yaml：

apiVersion: apps/v1
kind: Deployment
metadata:
  name: customer-ratings
  labels:
    app: product-ratings-vue
spec:
  replicas: 1
  selector:
    matchLabels:
      app: product-ratings-vue
  template:
    metadata:
      labels:
        app: product-ratings-vue 
    spec:
      containers: 
      - name: api-service
        image: api-service
        ports:
          - containerPort: 8080 …

我正在尝试运行具有如下参数的 bash 脚本：

./test.sh param1 param2

bash文件

param1=$1
param2=$2

echo $param1
echo $param2

但是它不起作用，但如果参数不存在，它将起作用。

cmd, _ := exec.Command("/bin/sh", fmt.Sprintf("./test.sh %s %s","test1","test2")).Output()

但是，如果我更改 bash 脚本以执行其他操作而不将任何内容传递给它，那么它就可以工作。

cmd, _ := exec.Command("/bin/sh", "./test.sh").Output()

如何使用 Go 将参数传递到 bash 文件中？

我有一个名为Users的界面,我正在尝试初始化对象,如下所示:

constructor(private _http: Http) {  }

  getUsers(): Observable<User[]> {
        return this._http.get(this._url)
            .map((response: Response) => response.json())

            .do(data => console.log("User data" + JSON.stringify(data)))
            .catch(this.handleError);
    }

    private handleError(error: Response) {
        console.log(error);
        return Observable.throw(error.json().error || 'Internal Server error');
    } 

但是我收到以下错误.

The type argument for type parameter 'T' cannot be inferred from the 
usage. Consider specifying the type arguments explicitly. Type 
argument candidate 'Response' is not a valid type argument because it 
is not a supertype of candidate 'Response'. Types of property 'type' 
are incompatible. …

我运行以下命令，当我检查 Pod 是否正在运行时，我收到以下错误：

无法拉取映像“tomcat”：rpc 错误：代码 = Unknown desc = 清单列表条目中没有与 linux/amd64 匹配的清单

kubectl run tomcat --image=tomcat --port 8080

和

无法拉取映像“ngnix”：rpc 错误：代码 = 未知 desc = 来自守护程序的错误响应：ngnix 的拉取访问被拒绝，存储库不存在或可能需要“docker 登录”

kubectl run nginx3 --image ngnix --port 80

我在 git 中看到了一篇关于如何在私有存储库导致问题但不是公开问题时完成此操作的帖子。有没有人遇到过这个问题？

我有一个查询,它插入一个格式的日期year month day,但我一直得到同样的错误说ORA-01843: not a valid month.看oracle文档看起来我是正确的,这令人困惑.希望得到额外的一双眼睛.

  to_timestamp('2018-07-02 08:03:24.466381 AM', 'RR-MON-DD HH.MI.SSXFF AM')

和

to_timestamp('2115-07-21 00:00:00.0 AM', 'RR-MON-DD HH.MI.SSXFF AM')

我正在使用 tailwind 和 typescript 制作一个演示 Vue.js 3 应用程序。每当我运行该应用程序时，我都会收到错误消息：

This relative module was not found:

* ./src/main.js in multi (webpack)-dev-server/client?https://192.168.2.102:8090&sockPath=/sockjs-node (webpack)/hot/dev-server.js ./src/main.js

主要.ts

import { createApp } from 'vue';
import App from './App.vue'
import router from './router'
import './styles/app.css';

createApp(App)
    .use(router)
    .mount('#app');

应用程序.vue

<template>
    <div class="justify-center flex bg-yellow-300 items-center h-screen">
        <div class="text-4xl">
            {{ hello }} 
        </div>
    </div>
</template>

<script lang="ts">
import {Vue} from "vue-property-decorator";

export default class App extends Vue {

    hello = 'Hello world'

}
</script>

vue.config.js

module.exports = { …

这是我正在使用的路径的片段：

<link rel="stylesheet" type="text/templates.css" href="../templates/css/superfish.css" th:href="@{../templates/css/superfish.css}"/>
<link rel="stylesheet" type="text/templates.css" href="../templates/css/style.css" th:href="@{../templates/css/style.css}"/>
<link rel="stylesheet" type="text/templates.css" href="../templates/css/nivo-slider.css" th:href="@{../templates/css/nivo-slider.css}"/>
<link rel="stylesheet" type="text/templates.css" href="../templates/css/jquery.qtip.min.css" th:href="@{../templates/css/jquery.qtip.min.css}"/>
<link rel="stylesheet" type="text/templates.css" href="../templates/css/jquery-ui.css" th:href="@{../templates/css/jquery-ui.css}"/>
<link rel="stylesheet" type="text/templates.css" href="../templates/css/jquery.fancybox.css" th:href="@{../templates/css/jquery.fancybox.css}"/>
<link rel="stylesheet" type="text/templates.css" href="../templates/css/jquery.fancybox-buttons.css" th:href="@{../templates/css/jquery.fancybox-buttons.css}"/>

控制器：

 @RequestMapping(value="/", method= RequestMethod.GET)
    public String contactForm(@Valid @ModelAttribute("contact") Contact contact, BindingResult bindingResult,
                              HttpServletRequest request, Model model, Device device) throws IOException {

        System.out.println("Inside controller-----------------");

主要方法：

@SpringBootApplication
@ComponentScan("com.stidham")
public class StidhamFinancialApplication extends SpringBootServletInitializer {

    @Override
    protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
        return application.sources(StidhamFinancialApplication.class);
    }

    public static void …

我正在尝试使用 spring-boot 解析一个简单的 index.html 文件。如果我输入 localhost:8080/index.html 它会解决，否则我会得到白色错误页面。

我把它贴在 GIT 上；这是一个非常简单的应用程序：Git Hub Link

问题似乎是模型：

表格型号：

@Entity
@Table(name="applicant")
public class FormModel {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private int id;
    private String name;
    @Email
    private String email;
    @Size(min=2, max=200)
    private String description;

    public String getName() {
        return name;
    }

    @Required
    public void setName(String name) {
        this.name = name;
    }

    public String getEmail() {
        return email;
    }

    @Required
    public void setEmail(String email) {
        this.email = email;
    }

    public String getDescription() {
        return description; …