小编Rah*_*ani的帖子

2016-09-17 15:16:04.386085 appDemo[2371:94976] [] __nwlog_err_simulate_crash simulate crash already simulated **"nw_socket_set_common_sockopts setsockopt SO_NOAPNFALLBK failed: [42] Protocol not available"**
2016-09-17 15:16:04.386676 appDemo[2371:94976] [] nw_socket_set_common_sockopts setsockopt SO_NOAPNFALLBK failed: [42] Protocol not available, dumping backtrace:
        [x86_64] libnetcore-856.1.8
    0   libsystem_network.dylib             0x0000000112dc780e __nw_create_backtrace_string + 123
    1   libnetwork.dylib                    0x0000000113bfa194 nw_socket_add_input_handler + 3002
    2   libnetwork.dylib                    0x0000000113bd7db8 nw_endpoint_flow_attach_protocols + 3768
    3   libnetwork.dylib                    0x0000000113bd6dd5 nw_endpoint_flow_setup_socket + 563
    4   libnetwork.dylib                    0x0000000113bd5b34 -[NWConcrete_nw_endpoint_flow startWithHandler:] + 2612
    5   libnetwork.dylib                    0x0000000113bf0d11 nw_endpoint_handler_path_change + 1261
    6   libnetwork.dylib                    0x0000000113bf0740 nw_endpoint_handler_start + 570
    7   libdispatch.dylib                   0x0000000112b44980 _dispatch_call_block_and_release …

2016-10-05 13:36:21.383340 MyApp[1867:72704] 0x60000015e350 Copy matching assets reply: XPC_TYPE_DICTIONARY  <dictionary: 0x60000015e350> { count = 1, transaction: 0, voucher = 0x0, contents =
    "Result" => <int64: 0x600000226fe0>: 29
}
2016-10-05 13:36:21.385076 MyApp[1867:72704] 0x608000556420 Daemon configuration query reply: XPC_TYPE_DICTIONARY  <dictionary: 0x608000556420> { count = 2, transaction: 0, voucher = 0x0, contents =
    "Dictionary" => <dictionary: 0x6080005566e0> { count = 1, transaction: 0, voucher = 0x0, contents =
        "ServerURL" => <dictionary: 0x608000556790> { count = 3, transaction: 0, voucher = 0x0, contents = …

我的应用使用openURL打开Goog​​le地图应用.它适用于iOS 9,但不适用于iOS 10.

我知道这个方法在iOS 10上已被弃用,并且有一个新的参数更多.但是,我在任何地方都看到它仍然可以工作,并且更改为新方法只会阻止xCode中的警告.我还想支持iOS 9及更低版本.

有帮助吗？

谢谢.

在iOS 10中,不要打开设置网址:

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]];

问题是什么？

我有一个导航控制器,用于我的父视图控制器以及我的子视图控制器.子视图控制器进入另外两个视图控制器,即"UserLoginViewController"和"RegisterVC".我希望UserLogin中的子视图按钮执行Button操作,该操作又执行涉及父视图控制器及其导航控制器的segue.

这是我使用的代码:

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
        if segue.identifier == Constants.embedSegue {
            let childViewController = segue.destinationViewController as! UserLoginViewController
            childViewController.delegate = self
        }
    }

从parentVC调用UserLoginVC.

我得到一个错误说

无法将'UINavigationController'类型的值(0x109aa7860)转换为'Storey_Keeper.UserLoginViewController'(0x10645b810).

救命？