小编Har*_*had的帖子

我正在使用 highcharts 生成图表，问题是，highcharts 正在工具提示的边框和内容之间生成空间，并且饼图的标签在生成的空间之间可见。\n任何人都可以解决我的问题。

请检查以下示例。

$(function () {\r\n    var chart;\r\n    $(document).ready(function () {\r\n        chart = new Highcharts.Chart({\r\n            chart: {\r\n                renderTo: \'graf1\',\r\n                plotBackgroundColor: null,\r\n                plotBorderWidth: null,\r\n                plotShadow: false\r\n            },\r\n\r\n            title: {\r\n                margin: 40,\r\n                text: \'Pod\xc3\xadl v\xc5\xa1ech pot\xc5\x99eb\'\r\n            },\r\n            tooltip: {\r\n                borderWidth: 1,\r\n                backgroundColor: "rgba(255,255,255,0)",\r\n                borderRadius: 0,\r\n                shadow: false,\r\n                useHTML: true,\r\n                percentageDecimals: 2,\r\n                backgroundColor: "rgba(255,255,255,1)",\r\n                formatter: function () {\r\n                    return \'<div class="tooltop">\'+this.point.name + \'<br />\' + \'<b>\' + Highcharts.numberFormat(this.y).replace(",", " ") + \' K\xc4\x8d [\' + …

我正在尝试使用MySQLi Query获取数据.请检查我的SQL查询,我在If条件上收到错误.我添加旁边的错误

如果条件

当它显示到控制台时

<?php
    $id = $_GET['id'];
    include("../include/connection_string.php");


    $sql = mysqli_query($db, "SELECT pages, main_id FROM dhms_index_table where main_id='"+$id+"'");

    if(mysqli_num_rows($sql)){ // Showing error here " Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result"
        $data = array();
        while($row = mysqli_fetch_array($sql)){
            $data[] = array(
                'pages' => $row['pages'],
                'main_ID' => $row['main_id']
            );
        }
        header('Content-type: application/json');
        echo json_encode($data);
    }
    ?>

connections_string.php

$server = 'localhost'; 
$username ="root"; 
$passwd =''; 
$Dbase = 'og_dhms'; 
$db = @mysqli_connect($server,$username,$passwd) 
        or die("Could not connect database"); 
@mysqli_select_db($db, $Dbase) 
        or die("Could not …