我正在使用maven来构建我的项目.它早先成功编译.当我这样做时,它已经开始出错了mvn clean install.
[ERROR] classpath error: unable to find org.aspectj.lang.JoinPoint (check that aspectjrt.jar is in your classpath)
下面是我的pom.xml
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.guavus</groupId>
<artifactId>Exporter</artifactId>
<version>atlas2.1</version>
<packaging>jar</packaging>
<name>Exporter</name>
<url>http://maven.apache.org</url>
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<aspectj.version>1.6.10</aspectj.version>
<org.springframework.version>3.0.5.RELEASE</org.springframework.version>
</properties>
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-site-plugin</artifactId>
<version>3.0-beta-2</version>
<configuration>
<reportPlugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-javadoc-plugin</artifactId>
<version>2.7</version>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-jxr-plugin</artifactId>
<version>2.1</version>
<configuration>
<aggregate>true</aggregate>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-surefire-report-plugin</artifactId>
<version>2.6</version>
</plugin>
<plugin>
<groupId>org.codehaus.mojo</groupId>
<artifactId>cobertura-maven-plugin</artifactId>
<version>2.4</version>
<configuration>
<formats>
<format>xml</format>
<format>html</format>
</formats>
</configuration>
</plugin>
<!--
plugin> <groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-checkstyle-plugin</artifactId>
<version>2.6</version> </plugin …As far as I am aware, in order to use the maven-release-plugin, you have to drop in an scm section into your POM file. E.g.:
<scm>
<connection>scm:hg:ssh://hg@bitbucket.org/my_account/my_project</connection>
<developerConnection>scm:hg:ssh://hg@bitbucket.org/my_account/my_project</developerConnection>
<url>ssh://hg@bitbucket.org/my_account/my_project</url>
<tag>HEAD</tag>
</scm>
I understand this data is used to determine what to tag and where to push changes. But isn't this information already available if you have the code cloned/checked-out? I'm struggling a bit with the concept that I need to tell maven what code it needs to tag when it …
如何在Java中执行此转换？
目前,我正在做:
public static String formatDate(String strDateToFormat) {
try {
SimpleDateFormat sdfSource = new SimpleDateFormat("EEEE, MMMM DD, YYYY");
Date date = sdfSource.parse(strDateToFormat);
SimpleDateFormat sdfDestination = new SimpleDateFormat("yyyy-MM-dd");
return sdfDestination.format(date);
} catch (ParseException pe) {
System.err.println("Parse Exception : " + pe);
}
return null;
}
但是,这会导致格式不正确.它给了我以下输出:
Friday, February 1, 2013 > 2013-01-04
Thursday, January 31, 2013 > 2013-01-03
我曾经写过一个synchronized像以下一样的块:
synchronized(foobar) {
// do something
}
但是,最近我看到有人写道:
synchronized(foobar) {
// do something
foobar.notifyAll();
}
有foobar.notifyAll();必要吗？如果我省略它会怎么样？
我想在java中生成一个160位的素数.我知道我必须循环遍历所有160位数字,对于任何数字n,我都必须检查它们是否可以被任何质数小于sqroot(n)或者通过任何素数测试整除Miller-Rabin test.我的问题是:
有没有特定的库可以做到这一点？
有没有其他(更好)的方法来做到这一点？
我希望maven-pmd-plugin包含我指定的规则集并排除一些规则(特别是UselessParentheses)
就像在文档中描述的那样,我将以下内容放在pmd.xml中,该pmd.xml是所有模块的父级:
<reporting>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-pmd-plugin</artifactId>
<version>3.0</version>
<configuration>
<rulesets>
<ruleset>/home/ubuntu/ruleset.xml</ruleset>
</rulesets>
</configuration>
</plugin>
</plugins>
</reporting>
并准备了一个自定义规则集,如下所示:
<!-- We'll use the entire rulesets -->
<rule ref="rulesets/java/basic.xml"/>
<rule ref="rulesets/java/imports.xml"/>
<rule ref="rulesets/java/codesize.xml"/>
<rule ref="rulesets/java/design.xml"/>
<rule ref="rulesets/java/strings.xml"/>
<rule ref="rulesets/java/unusedcode.xml"/>
<!-- We want everything from this except some -->
<rule ref="rulesets/java/unnecessary.xml">
<exclude name="UselessParentheses"/>
</rule>
作为主要部分.
然而,当我跑步时,我mvn clean jxr:jxr pmd:check在报告中有"UselessParentheses".而且,用-Xshow来运行它
[DEBUG] Preparing ruleset: java-basic
[DEBUG] Before: java-basic After: java-basic.xml
[DEBUG] The resource 'rulesets/java/basic.xml' was found as jar:file:/home/ubuntu/.m2/repository/net/sourceforge/pmd/pmd/5.0.2/pmd-5.0.2.jar!/rulesets/java/basic.xml.
[DEBUG] Preparing …我有一个Maven项目mjbean只有一个依赖项:TestA.这是mjbean的pom.xml:
<groupId>com.mbean</groupId>
<artifactId>mjbean</artifactId>
<version>0.0.1-SNAPSHOT</version>
<packaging>bundle</packaging>
<build>
<defaultGoal>install</defaultGoal>
<plugins>
<plugin>
<groupId>org.apache.felix</groupId>
<artifactId>maven-bundle-plugin</artifactId>
<extensions>true</extensions>
<configuration>
<instructions>
<Main-Class>com.mbean.Main</Main-Class>
<Embed-Dependency>*;scope=compile|runtime</Embed-Dependency>
<Embed-Transitive>true</Embed-Transitive>
<Bundle-SymbolicName>${project.artifactId}</Bundle-SymbolicName>
<Import-Package>*</Import-Package>
</instructions>
</configuration>
</plugin>
</plugins>
</build>
<name>mjbean</name>
<url>http://maven.apache.org</url>
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
</properties>
<dependencies>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>3.8.1</version>
<scope>test</scope>
</dependency>
<dependency>
<groupId>com.testa</groupId>
<artifactId>TestA</artifactId>
<version>1.0.0-SNAPSHOT</version>
</dependency>
</dependencies>
主要课程非常简单:
package com.mbean;
import com.testa.Testcl;
public class Main {
public static void main(String[] args) {
Testcl tcl = new Testcl();
tcl.testmethod();
}
}
我<Main-Class>com.mbean.Main</Main-Class>在maven-bundle-plugin中指定了主类.它与Eclipse运行良好.然后我使用Eclipse在目标文件夹中生成目标包.当我尝试在命令行中运行它时java -jar mjbean-0.0.1-SNAPSHOT.jar,我收到此错误:
Exception in thread "main" java.lang.NoClassDefFoundError: com/testa/Testcl
at com.mbean.Main.main(Main.java:12) …我曾尝试使用此代码将 ZIP 文件转换为字节数组：
private static byte[] readZipFile(String zipFnm)
// read in fnm, returning it as a single string
{
FileInputStream fileInputStream=null;
File file = new File(zipFnm);
byte[] bFile = new byte[(int) file.length()];
try{
//convert file into array of bytes
fileInputStream = new FileInputStream(zipFnm);
fileInputStream.read(bFile);
fileInputStream.close();
}catch(Exception e){
e.printStackTrace();
}
return bFile;
}
以及用于将字节数组转换回 ZIP 的代码，通过调用 writeByteToZip(fnm + ".zip");
private static String writeByteToZip(String outFnm)
{
try {
FileOutputStream fileOuputStream = new FileOutputStream(outFnm);
fileOuputStream.write(bFile);
fileOuputStream.close();
} catch ( IOException iox ){
iox.printStackTrace(); …我在使用 javac 编译器编译的 maven 项目中遇到了一些与 java8 相关的代码，但在 Eclipse 中给出了编译错误（我认为 ECJ 编译器不同于 javac）。
我在 Eclipse-Luna 中导入它：Import => Maven => Existsing Maven Project
作为快速修复，有没有办法让 Eclipse 在 maven 项目中使用 javac（从而禁用 ECJ 编译器）？
编辑：添加编译器差异的最小 poc 示例。
此代码使用javac 编译，但 List 初始化在 Eclipse 中给出错误：“此表达式的目标类型必须是功能接口”
package test;
import static java.util.Arrays.asList;
import java.util.List;
public class Test01 {
private static final List<MyInterface> items = asList(() -> "123", () -> "456");
public void test01() {
System.out.println("Hello");
}
public interface MyInterface {
String value();
}
}
如果添加类型转换，错误就会消失：
private …我正在使用IntelliJ IDEA.我尝试了它附带的"检查代码"功能,我想修复一个叫做"入口点"的东西.这与我的枚举和主要方法有关.我想知道入口点是什么以及如何解决该错误.