小编Zod*_*ddo的帖子

我正在更改数据库中的约束,我需要删除其中的一些约束.我知道对于单个约束,命令如下:

ALTER TABLE tblApplication DROP CONSTRAINT constraint1_name;

但是,当我尝试

ALTER TABLE tblApplication DROP (
  CONSTRAINT constraint1_name,
  CONSTRAINT constraint2_name,
  CONSTRAINT constraint3_name
);

它不起作用,我需要这样做:

ALTER TABLE tblApplication DROP CONSTRAINT constraint1_name;
ALTER TABLE tblApplication DROP CONSTRAINT constraint2_name;
ALTER TABLE tblApplication DROP CONSTRAINT constraint3_name;

有没有办法在单个命令中删除多个约束？我想避免重复ALTER TABLE tblApplication,就像ADD命令一样:

ALTER TABLE tblApplication ADD (
  CONSTRAINT contraint1_name FOREIGN KEY ... ENABLE,
  CONSTRAINT contraint2_name FOREIGN KEY ... ENABLE,
  CONSTRAINT contraint3_name FOREIGN KEY ... ENABLE
);

考虑外部 (npm) 模块extmod在其声明文件中公开以下接口：

interface Options {
  somevar?: string;
  suboptions?: {
    somesubvar?: string;
  };
}

如何通过模块增强somesubvar2在内部添加属性？suboptions

我在文件中尝试了以下操作extmod.d.ts：

declare module 'extmod' {
  interface Options {
    suboptions?: {
      somesubvar2?: string;
    };
  }
}

但它会引发以下错误：

error TS2687: All declarations of 'suboptions' must have identical modifiers.

error TS2717: Subsequent property declarations must have the same type.  Property 'suboptions' must be of type '<SNIP>', but here has type '{ somesubvar2: string; }'.