小编Ric*_*lev的帖子

这是我的代码

import os,sys
import Image
import matplotlib.pyplot as plt
from matplotlib.pyplot import *
from matplotlib.font_manager import FontProperties

jpgfile = Image.open("t002.jpg")

# Set up the figure and axes.
fig = plt.figure(figsize=(18,10))  # ...or whatever size you want.
ax = fig.add_subplot(111)
ax.legend(fontsize=18)
# Draw things.
plt.imshow(jpgfile)  # Unlike plot and scatter, not a method on ax.
ax.set_xlabel('normalized resistivities')
ax.set_ylabel('normalized velocities')
ax.set_xticks([]); ax.set_yticks([])

# Save and show.
plt.savefig("fig.jpg")
plt.show()

但

/usr/local/lib/python2.7/dist-packages/matplotlib/axes/_axes.py:519: UserWarning: No labelled objects found. Use label='...' kwarg on individual plots

我应该如何设置标签？

我正在使用教程point.com示例.

int  var[MAX] = {10, 100, 200};
int  *ptr;

// let us have address of the last element in pointer.
ptr = &var[MAX-1];
for (int i = MAX; i > 0; i--)
{
    cout << "Address of var[" << i << "] = ";
    cout << ptr << endl;

    cout << "Value of var[" << i << "] = ";
    cout << *ptr << endl;

    // point to the previous location
    ptr--;
}
return 0;

那么,&var[MAX - 1] 为什么不 …

#include<iostream>
#include<fstream>
using namespace std;

class Integer {
public:
    int val;
    Integer(int val = 0) {
        this->val = val;
    }
    void setVal(int val) {
        this->val = val;
    }
};

int main()
{
    int val;
    Integer i;
    i.setVal(8);
    cout << val << endl;
}

当我执行我的代码时,我得到了0.我是C++的新手,我不明白this.有人可以详细说明这个问题吗？

我想将浮点数列表转换为整数.我的代码

import math

data1 = [line.strip() for line in open("/home/milenko/Distr70_linux/Projects/Tutorial_Ex3/myex/base.txt", 'r')]
print type(data1)
data1c = [int(math.floor(i)) for i in data1]

print data1c[0]

我应该改变什么？文件很大,只有几行

1.200000e+03
1.200000e+03
1.200000e+03
1.200000e+03
1.200000e+03
1.200000e+03
1.200000e+03
1.200000e+03

with open('index.txt','r') as f:

    a = [int(x) for x in f.readline().split()] 
    array = []
    for line in f: 
        array.append([int(x) for x in line.split()])

print array[0]
print array[1]
print array[2]
print array[3]
print array[4]

输入文件

0
0
100
200
1
101
201
2
102
202
3
103

当我运行我的代码

[0]
[100]
[200]
[1]
[101]

刚刚0出现.

我正在努力解决这些概念。例如，我有这个视图函数

def post_detail(request, year, month, day, post):
    post = get_object_or_404(Post, slug=post,status='published',p__year=year,p__month=month,p__day=day,status='published',)
    return render(request,'blog/post/detail.html',{'post': post})

据我了解，函数将请求对象作为参数、模板路径和变量来呈现给定的模板。直到现在还可以。但是现在来了模板上下文处理器和幕后的魔法。来自djangoproject

该TEMPLATE_CONTEXT_PROCESSORS设置是一个可调用元组 - 称为上下文处理器 - 将请求对象作为参数并返回要合并到上下文中的项目字典

他们实际上在做什么？他们将在模板中公开数据，输入数据是否有任何限制？

过滤功能

function filter(array,test) {
    let passed = [];
    for (let element of array){
        if (test(element)) {
            passed.push(element);
        }
    }
    return passed;
}

大批

a = [{name: 'John', sport : 'football'},
    {name: 'Sergio', sport : 'football'},
    {name: 'John', sport : 'basketball'},
    {name: 'Jova', sport : 'football'},
    {name: 'Jon', sport : 'basketball'},
    {name: 'Lemmi', sport : 'football'},
    {name: 'Josh', sport : 'football'},
]

当我运行我的代码时

console.log(filter(a, i => i.name['Lemmi']));

我有

[]

如何编辑行以获取

sport: 'football'

输出？

我想规范化(在0和1之间缩放值)矢量速度.

normalized v(i)=v(i)-vmin/(vmax-vmin)

我的代码

#include <iostream>
#include <iterator>
#include <fstream>
#include <vector>
#include <algorithm>

using namespace std;

int main(){
vector<double> velocity;
vector<double> results;
double vLower, vUpper, v1;

ifstream inputFile1("/home/milenko/gust/vel.dat");

if (inputFile1) {        
    double value;

    while ( inputFile1 >> value ) {
        velocity.push_back(value);
    }
}

vLower = *min_element(velocity.begin(), velocity.end());
vUpper = *max_element(velocity.begin(), velocity.end());

v1 = vUpper-vLower;
transform(velocity.begin(), velocity.end(), velocity.begin(), [vLower](double i) -> double { return i - vLower; });
transform (velocity.begin(), velocity.end(), v1, results, divides<double>());
for (auto c : results) { …

我的csh脚本

#!/bin/csh
# C-schell script to increase the boundingbox....

echo '%\!PS-Adobe-3.0 EPSF-3.0'
echo '%%BoundingBox: 0 0 1100 1100'
tail +3 $argv[1]

叫这里

csh bbox.csh plt >! plt_P1.ps

但是我有

csh -f bbox.csh plt
tail: cannot open ‘+3’ for reading: No such file or directory

该怎么tail办？编写代码的人使用Darwin,我在Ubuntu 14.04上.

这是我的代码

#!/usr/bin/R

c1 <-c(60,199,102,134,81,95,135,151,102,112,211,120)
barplot(c1, main="number of points per cluster", 
    color="dark blue")

但警告信息说

警告消息:1:在plot.window(xlim,ylim,log = log,...)中:
"color"不是图形参数

我的形象

我还想在x轴上从1到12编号.