如果我有矩阵x=[x(1) x(2) x(3) ... x(n-1) x(n],那么diff(x)就给 [x(2)-x(1) x(3)-x(2) ... x(n)-x(n-1)].是否有这样的添加功能,结果会是[x(1)+x(2) x(2)+x(3) ... x(n-1)+x(n)]什么？
x=[x(1) x(2) x(3) ... x(n-1) x(n]
diff(x)
[x(2)-x(1) x(3)-x(2) ... x(n)-x(n-1)]
[x(1)+x(2) x(2)+x(3) ... x(n-1)+x(n)]
matlab
matlab ×1