我已经制作了以下bash脚本,以便从名为的特定文件中导出值params.env:
#!/bin/bash
SOURCE="${BASH_SOURCE[0]}"
while [ -h "$SOURCE" ]; do # resolve $SOURCE until the file is no longer a symlink
DIR="$( cd -P "$( dirname "$SOURCE" )" && pwd )"
SOURCE="$(readlink "$SOURCE")"
[[ $SOURCE != /* ]] && SOURCE="$DIR/$SOURCE" # if $SOURCE was a relative symlink, we need to resolve it relative to the path where the symlink file was located
done
SOURCE=$(dirname ${SOURCE})
export $(cat "${SOURCE}/../params.env" | xargs)
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该params.env具有的值:
Param1=param1
Param2="Space separated value"
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但是它成功导出了Param1,但它无法导出Param2.
你知道如何解决这个问题吗?
为了了解有关python的更多信息,我制作了以下简单脚本:
#!/usr/bin/env python
# coding=utf-8
# -*- Mode: python; c-basic-offset: 4 -*-
from sqlalchemy import *
from sqlalchemy.orm import sessionmaker
from sqlalchemy.orm import mapper
db=create_engine('postgresql://somepassword:someuser@127.0.0.1/hello')
db.echo = False
metadata = MetaData(db)
people=Table('people',metadata,autoload=True)
class People(object):
pass
people_mapper=mapper(People,people)
db_session=sessionmaker()
db_session.configure(bind=db)
lewis_hamilton=People()
lewis_hamilton.name='Lewis'
lewis_hamilton.surname='Hamilton'
lewis_hamilton.age=44
db_session.save(lewis_hamilton)
db_session.flush()
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我使用下表将"Lewis Hamilton"插入(直接来自psql):
Table "public.people"
Column | Type | Modifiers
---------+-----------------------+-----------------------------------------------------
id | integer | not null default nextval('people_id_seq'::regclass)
name | character varying(60) |
surname | character varying(60) |
age | smallint |
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但是当我运行脚本时,我收到以下错误:
sqlalchemy.exc.ArgumentError:Mapper Mapper | …
在使用tinymce https://github.com/pc-magas/tinymce_demo的示例演示中,我尝试通过https://www.tinymce.com/docs/api/tinymce/tinymce中提供的api更改tinymce的内容。 editorcommands/在我的例子中,我希望当单击“hello”按钮时将“Hello”字符串插入编辑器的内容中。
尝试执行此操作的代码是(https://github.com/pc-magas/tinymce_demo/blob/master/src/MyEditor.js):
import React, { Component } from 'react';
import TinyMCE from 'react-tinymce';
/**
* Basic Editor
*/
class MyEditor extends Component {
constructor(props) {
super(props)
this.state={text:''}
this.tinyMCE=null;
}
onTextChange(e) {
this.setState({text:e.target.getContent()})
}
doStuffWhenFileChanges(event) {
event.preventDefault();
console.log(this.tinyMCE);
this.tinyMCE.context.execCommand('mceInsertContent', false ,"Hello");
}
render(){
return (
<div>
<TinyMCE
ref = { (el)=>{ this.tinyMCE=el; } }
content = ""
config = {{
plugins: 'link image code paste autolink media autoresize',
toolbar: 'undo redo | bold …Run Code Online (Sandbox Code Playgroud) 我有以下 phpUnit 功能测试:
namespace Tests\AppBundle\Controller;
/**
* @testtype Functional
*/
class DefaultControllerTest extends BasicHttpController
{
/**
* {@inheritdoc}
*/
public function setUp()
{
$client = static::createClient();
$container = $client->getContainer();
$doctrine = $container->get('doctrine');
$entityManager = $doctrine->getManager();
$fixture = new YourFixture();
$fixture->load($entityManager);
}
/**
* {@inheritdoc}
*/
public function tearDown()
{
//Database is being destroyed here....
}
public function testIndex()
{
$client = static::createClient();
$crawler = $client->request('GET', '/');
$response=$client->getResponse();
$this->assertEquals(302, $response->getStatusCode());
$this->assertEquals('/login',$response->headers->get('Location'));
//@todo Create Dummy Users
$this->checkPanelAfterSucessfullLogin($crawler); //How I can create some …Run Code Online (Sandbox Code Playgroud) 我正在为 Moodle 创建一个自定义块,当我尝试将其添加到页面中时,显示如下:
\n\n\n\n而不是指定的名称。
\n\n该version.php文件有这些:
$plugin->component = \'block_userlist\';\n$plugin->version = 2019050316;\n$plugin->requires = 2018120300;\nRun Code Online (Sandbox Code Playgroud)\n\n该块定义为:
\n\ndefined(\'MOODLE_INTERNAL\') || die();\n\nclass block_userlist extends block_base {\n public function init() {\n $this->title = get_string(\'userlist\', \'block_userlist\');\n }\n // The PHP tag and the curly bracket for the class definition \n // will only be closed after there is another function added in the next section.\n\n public function get_content() {\n global $DB;\n\n // if ($this->content !== null) {\n // return $this->content;\n …Run Code Online (Sandbox Code Playgroud) 正如 Laravel 官方文档所述,我执行了以下命令:
namespace App\Console\Commands;
use App\Model\Report;
use Illuminate\Console\Command;
use Exception;
class ExportAnualReport extends Command
{
/**
* @var string
*/
protected $description = "Print Anual Report";
/**
* @var string
*/
protected $signature = "report:anual";
public function __construct()
{
parent::__construct();
}
public function handle(Report $report): int
{
//@todo Implement Upload
try {
$reportData = $report->getAnualReport();
$this->table($reportData['headers'], $reportData['data']);
return 0;
} catch (Exception $e) {
$this->error($e->getMessage());
return 1;
}
}
}
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但我已经遵循了 Laravel 的方法和建议,而不是这个问题中使用的方法 ,并且利用依赖注入来将我的模型作为服务插入。
所以我同时认为对它进行单元测试是一个好主意: …
我有一个具有字段的实体Users:
/**
* @ORM\Column(type="boolean", options={"default"=false})
*/
private $activated;
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在我的数据库上,这是一个not_null值。我希望这个(映射的)字段能够接受空值。
当我查看symfony时,public/index.php我遇到了以下代码片段:
$env = $_SERVER['APP_ENV'] ?? 'dev';
$debug = (bool) ($_SERVER['APP_DEBUG'] ?? ('prod' !== $env));
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因此我执行了以下搜索:
但我仍然无法弄清楚算子??实际意味着什么.你能告诉我关于这个运算符/语法的信息吗?