声明:
(definitions != null && definitions.Where(key => key.asset_id != null &&
key.asset_id == item).FirstOrDefault() != null
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投掷:
集合被修改,枚举操作可能无法执行
如何解决这个问题?
if (definitions != null
&& definitions
.Where(key => key.asset_id != null && key.asset_id == item)
.FirstOrDefault() != null)
{
CurrentDuration = definitions
.Where(key => key.asset_id != null && key.asset_id == item)
.FirstOrDefault().duration;
}
Run Code Online (Sandbox Code Playgroud) 如何启用内容可见性?为什么它不可见?
<div class="header"></div>
<div class="categories"></div>
<div class="content"></div>
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CSS样式:
body {
margin: 0;
padding: 0;
}
.header {
padding-top: 0;
margin-top: 0;
height: 160px;
background: #666;
}
.categories {
position: absolute;
height: 100%;
width: 20%;
background: #b6fd40;
}
.content {
height: 100%;
width: 100%;
background: gray;
}
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小提琴.
例如,让我有这样的事情.
public enum CarEnum { BWM, LadaKalina };
class Program
{
static void Main(string[] args)
{
var carEnum = CarEnum.LadaKalina;
GetMessage(carEnum);
}
public static void GetMessage(CarEnum carEnum)
{
switch (carEnum)
{
case CarEnum.BWM:
Console.WriteLine("BWM");
break;
case CarEnum.LadaKalina:
Console.WriteLine("LadaKalina");
break;
default:
Console.WriteLine("default");
break;
}
}
}
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我想在函数GetMessage中调用默认情况.通过论证更好的是什么?
是)我有的:
1. 25686-47362-04822-08149-48999-28161-15124-63556
2. 25686-47362-04822-08149-48999-28161-15124-6355654534
3. 54354325686-47362-04822-08149-48999-28161-15124-63556
4. 25686-47362-04822-08149-48999-28161-15124-6355654534fds
5. fdsfds54354325686-47362-04822-08149-48999-28161-15124-63556
6. 25686-47362-04822-08149-48999-28161-15124-63556-63556
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我希望得到什么
1. 25686-47362-04822-08149-48999-28161-15124-63556
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我尝试了最近的东西 ([0-9]{5,5}){8}
我试图避免2,3,4,5,6.
我在面试任务中找到了这段代码.结果取决于调试.为什么Value改变调试模式?请解释它是如何工作的.
static IEnumerable<int> Square(IEnumerable<int> a)
{
foreach (var r in a)
{
Console.WriteLine(r * r);
yield return r * r;
}
}
class Wrap
{
private static int init = 0;
public int Value1
{
get { return ++init; }
}
}
static void Main(string[] args)
{
var w = new Wrap();
var wraps = new Wrap[3];
for (int i = 0; i < wraps.Length; i++)
{
wraps[i] = w;
}
var values = wraps.Select(x => x.Value1);
var …Run Code Online (Sandbox Code Playgroud) 为什么要List<Component> l = second.ToList();导致
System.NullReferenceException'发生在ConsoleApplication1.exe中
在 select new { id = b.id, Name = b.Name };
如何解决这个问题?
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
List<Component> firstlist = new List<Component>();
List<Component> secondlist = new List<Component>();
List<Component> thirdlist = new List<Component>();
firstlist.Add(new Component { id = 1, Name = "Jhon" });
secondlist.Add(new Component { id = 2, Name = "Jhon" });
thirdlist.Add(new Component { id = 3, Name = "Jhon" });
var first = from d …Run Code Online (Sandbox Code Playgroud) 我是C++领域的新手,面对双指针.问题是如何设置x=5功能test?
#include <iostream>
using namespace std;
typedef struct _DoublePointer
{
int x;
int y;
} DoublePointer;
void test(_DoublePointer** pointer)
{
}
void main()
{
_DoublePointer* pointer = new _DoublePointer;
_DoublePointer** doublePointer = &pointer;
test(doublePointer);
}
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