小编nov*_*int的帖子

我在比较MySQL数据库的写性能方面比较了node.js和PHP.我使用Apache的基准,Linux Mint的虚拟机,最新的MySQL服务器(43年5月5日)和驱动程序为MySQL与node.js的从这里开始.我用的代码是

server.js

var http = require('http');
var mysql = require('mysql');
var server = http.createServer(function (req, res) {

var connection = mysql.createConnection({
    host     : 'localhost',
    user     : 'root',
    password : 'root',
    database : 'testDB'
});

connection.connect();
connection.query("INSERT INTO Persons (LastName, FirstName, Address, City) VALUES ('Futterkiste', 'Alfreds', 'Obere Str. 57', 'Berlin')", function(err, rows, fields) {
    if (!err)
        console.log('The solution is: ', rows);
    else
        console.log('Error while performing Query.');
});

connection.end();

res.writeHead(200, {'Content-Type': 'text/plain'});
res.end('Hello World');
});

server.listen(1337, '127.0.0.1');
console.log('Server running …

我是新来的代码文档,并试图用grunt-ngdocs记录我的角度应用程序.

我从以下网址克隆了一个工作示例:https://github.com/m7r/grunt-ngdocs-example

给定的示例缺少文档控制器,因此我使用以下代码添加了自己的文档控制器:

 /**
  * @ngdoc controller
  * @name rfx.controller:testCtrl
  * @description 
  * Description of controller.
  */
 .controller('testCtrl', function() {
 });

当我尝试通过从命令行运行grunt来构建文档时,我收到以下错误消息:

Warning: Don't know how to format @ngdoc: controller Use --force to continue.

我该如何解决？我阅读了本指南http://www.shristitechlabs.com/adding-automatic-documentation-for-angularjs-apps/,如果我尝试记录控制器,我无法弄清楚为什么我会不断收到错误消息:(谢谢任何帮助!

我正在编写angularjs应用程序,它依赖于从MySQL数据库返回的数据.

Angularjs代码发出HTTP请求并将返回的数据记录到控制台:

$http({method: 'POST', url: 'php/return_something.php', headers: {'Content-Type': 'application/json'}})
    .success(function(data, status, headers, config) {
    //The API call to the back-end was successful (i.e. a valid session)
        console.log(data);
    })
    .error(function(data, status, headers, config) {
        console.log("Error.");
    });

return_something.php

try
{
    $conn = new PDO("mysql:host=".DB_HOST."; dbname=".DB_DATABASE, DB_USER, DB_PASSWORD);
    // set the PDO error mode to exception
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    $sql = $conn->prepare("SELECT count(id_table_x) from table_x; SELECT count(id_table_y) from table_y;");
    $sql->execute();

    // set the resulting array to associative
    $results = $sql->fetchAll(PDO::FETCH_ASSOC);
    echo json_encode($results);
}

catch(PDOException …