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使用 awk 进行 if 语句和拆分

我有一个看起来像的 system.log 文件。

[2019-12-20 09:06:40] main.INFO: Update Product Attributes [] []
[2019-12-20 09:18:56] main.INFO: Customer Id: . Param: {"store":101,"search":"soap"} [] []
[2019-12-20 09:19:32] main.INFO: Update Product Attributes [] []
[2019-12-20 09:20:34] main.INFO: Customer Id: . Param: {"store":101,"search":"ea"} [] []
[2019-12-20 09:23:29] main.INFO: Customer Id: . Param: {"store":101,"search":"C2"} [] []
[2019-12-20 09:23:31] main.INFO: Update Product Attributes [] []
[2019-12-20 09:23:43] main.INFO: Customer Id: . Param: {"store":101,"search":"spaghetti"} [] []
[2019-12-20 09:24:06] main.INFO: Customer Id: . Param: {"store":101,"search":"Ea"} [] []
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现在我想像这样拆分以获取日志中搜索的日期和值。 …

regex linux awk

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