小编Bob*_*obo的帖子

错误信息:找不到带有URI的HTTP请求的映射[/TestSpringWebApp/hello.htm]

任何帮助将不胜感激!

我正在使用注释将请求映射到控制器.控制器代码:

@Controller
@RequestMapping("/hello.htm")
public class HelloController  {    
    protected final Log logger = LogFactory.getLog(getClass());

    public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response)    
            throws ServletException, IOException {
        String now = (new Date()).toString();

        logger.info("Returning hello view with " + now);

        return new ModelAndView("hello", "now", now);    
    }    
}

Dispatcher-servlet.xml如下:

<?xml version="1.0" encoding="UTF-8"?>
<beans ...>

    <bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>

    <!--
    Most controllers will use the ControllerClassNameHandlerMapping above, but
    for the index controller we are using ParameterizableViewController, so we must
    define an explicit mapping for it.
    -->
    <bean …

我在ios dev世界里很新鲜.只是想知道我应该总是在viewDidLoad方法中做到吗？总是在viewDidUnload中释放它也是一个好主意吗？谢谢.

<script type='text/javascript'>

    function cool()
    {
        var innerHtml = "<script></script>";//simply for demostration
        $("body").append(innerHtml);
    }
 </script>

以上将混淆浏览器,甚至在调用cool函数之前无法正确呈现.为什么？

我想实现这样的事情:定义一个抽象方法

public abstract void registerError(*any subclass of an ErrorVO or ErrorVO e);

并在实际实现方法的子类中:

public void registerError(ASubclassOfErrorVO e);

非常感谢你的帮助!