小编Ell*_*t C的帖子

鉴于这种多对多的关系:

tagmap = db.Table('tagmap', db.Model.metadata,
    db.Column('post_id', db.Integer, db.ForeignKey('posts.id'),
    db.Column('tag_id', db.Integer, db.ForeignKey('tags.id'),)

class Post(db.Model):
    __tablename__ = 'posts'
    id    = db.Column(db.Integer, primary_key=True)
    text  = db.Column(db.Text)
    tags  = db.relationship('Tag', secondary=tagmap, backref='posts')

class Tag(db.Model):
    __tablename__ = 'tags'
    id    = db.Column(db.Integer, primary_key=True)
    name  = db.Column(db.String)

您将如何构造查询以选择所有帖子,包括可关联的Tag对象的可迭代列表？

期望的查询结果结构:

[ <Post 1, "Blah",      [<Tag "Goober">, <Tag "Mexico">]>,
  <Post 2, "Daft Punk", [<Tag "French">]>,
  <Post 3, "Slurpee",   [<Tag "Diabetes">, <Tag "Tasty">, <Tag "Sugary">]>,
  <Post 4, "Lasers",    []> ]

Jinja模板中所需的结果使用示例:

{% for post in posts %}
    {{ post.text }} …

如http://html5boilerplate.com/中的代码所示(ctrl + f"？v = 1")是什么？v = 1完全正确吗？它被添加到外部css和js urls.