我在数据库安全中有一个收集消息.
为了显示集合结构,我使用此命令.
db.messages.findOne()
{
"_id" : ObjectId("4f16fc97d1e2d32371003f02"),
"body" : "COURTYARD\n\nMESQUITE\n2300 HWY 67\nMESQUITE, TX 75150\ntel: 972-681-3300\nfax: 972-681-3324\n\nHotel Information: http://courtyard.com/DALCM\n\n\nARRIVAL CONFIRMATION:\n Confirmation Number:84029698\nGuests in Room: 2\nNAME: MR ERIC BASS \nGuest Phone: 7138530977\nNumber of Rooms:1\nArrive: Oct 6 2001\nDepart: Oct 7 2001\nRoom Type: ROOM - QUALITY\nGuarantee Method:\n Credit card guarantee\nCANCELLATION PERMITTED-BEFORE 1800 DAY OF ARRIVAL\n\nRATE INFORMATION:\nRate(s) Quoted in: US DOLLAR\nArrival Date: Oct 6 2001\nRoom Rate: 62.10 per night. Plus tax when applicable\nRate Program: AAA AMERICAN AUTO ASSN\n\nSPECIAL REQUEST:\n NON-SMOKING ROOM, GUARANTEED\n \n\n\nPLEASE DO NOT …Run Code Online (Sandbox Code Playgroud) 我想检查用户是否通过 new_password 输入作为当前密码,我想用消息重定向:Your current password can't be with new password。我怎么能检查这个?我想做系统更改密码用户,但我想拒绝旧密码通过。我该怎么办?
if (!(Hash::check($request->old_password, Auth::user()->password))) {
return response()->json(['errors' => ['Your current password can't be with new password']], 400);
}
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代码不起作用。我需要将旧密码写入数据库吗?
After a week of coding and searching forums, it seems timely to ask...
I have a C# application which processes messages sent by RabbitMQ using EventingBasicConsumer. I want to process several messages concurrently, so I have instantiated a few channels (8 in this case) on the same connection, each with a single consumer. I have then attached an event-handler to each consumer's Received event. Based on all my readings so far, this setup should allow the event-handler to be triggered …
我正在尝试集成API,并在API集成说明中显示以下内容:
GET /offers.json or /offers.xml
Headers: API-KEY={your_key}, API-LOGIN={your_login}
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CURL示例:
curl https://api.thewebsite.com/v1/offers.json -H 'API-KEY:
1a2b3c4d5e6f7g8h9i' -H 'API-LOGIN: 1a2b3c4d5e6f7g8h9i'
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我尝试过使用下面的cURL代码但没有成功.至于GET方法,我不知道如何将API KEY和API LOGIN作为标题传递.
$header = array('Content-Type: application/xml', 'API-KEY=1a2b3c4d5e6f7g8h9i', 'API-LOGIN=1a2b3c4d5e6f7g8h9i');
$url = "https://api.thewebsite.com/v1/offers.xml";
$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, $url);
curl_setopt($curl, CURLOPT_HTTPHEADER, $header);
$xml = curl_exec($curl);
curl_close($curl);
print $xml;
Run Code Online (Sandbox Code Playgroud) 目前我正在将CFT从JSON转换为Yaml.一切正常,直到Userdata部分.我很难在userdata部分使用任何函数,如!Ref或!FindInMap.
用户数据:
Fn::Base64: !Sub |
#!/bin/bash -v
/command {Fn::FindInMap: [ "url", Ref: AWS::Region, Ref: EnvironmentType ] }
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这将是非常有帮助的,如果任何人都可以共享任何代码片段.
如何从刀片模板调用控制器的方法并接收该方法返回的数据.例如:
MeetingRoomController
class MeetingRoomController extends \BaseController
{
public function index()
{
//get all the meeting room
$meetingRoomCountry = MeetingRoom::select('country')->distinct()->orderBy('country')->get();
return View::make('index')->with('meetingroom', $meetingRoomCountry);
}
public function findLocationForNavBar( $country )
{
$meetingRoomLocation = MeetingRoom::select('location')
->distinct()
->where('country', '$country')
->orderBy('country')
->get();
return View::make('index')- >with('meetingroomLocation', $meetingRoomLocation);
}
}
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查看 - index.blade.php
<div id="dropdown-lvl1" class="panel-collapse collapse">
<div class="panel-body">
<ul class="nav navbar-nav">
@foreach($meetingroom as $key => $value)
<li class="panel panel-default" id="dropdown">
<a data-toggle="collapse" href="#dropdown-lvl2">
<span class="glyphicon glyphicon-off"></span> {{$country = $value->country}} <span class="caret"></span>
</a>
<div id="dropdown-lvl2" class="panel-collapse …Run Code Online (Sandbox Code Playgroud) php ×3
laravel ×2
api ×1
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