小编ind*_*kar的帖子

MainActivity.java

public class MainActivity extends AppCompatActivity {
LinearLayout llStats;
TextView txtPlayCount, txtEarned;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    llStats = (LinearLayout) findViewById(R.id.llStats);
    txtPlayCount = (TextView) findViewById(R.id.txtNowPlaying);
    txtEarned = (TextView) findViewById(R.id.txtEarned);

    // layout background transparent
    llStats.getBackground().setAlpha(150);
    llStats.setVisibility(View.VISIBLE);

    Intent i = getIntent();
    String now_playing = i.getStringExtra("now_playing");
    String earned = i.getStringExtra("earned");

    // Diplaying the text
    txtPlayCount.setText(now_playing);
    txtEarned.setText(earned);

    }
}

SplashScreen.Java

public class SplashScreen extends Activity {
String now_playing, earned;
//Splash screen Timeout
private static int SPLASH_TIME_OUT = 3000;

@Override
protected void …

实际上我想要一个随机的数字和我使用的Integer值的浮点值

${Impressions_Int}=             Evaluate    random.randint(0,19999)
Log                             ${Impressions_Int}

我不知道我们应该为随机浮点值使用什么

我正在尝试将Dictionary转换为String for Regex模式匹配但是为此我们需要字符串或stringbuffer任何想法如何做到这一点？