让我说我有阵列:
a = array((1,2,3,4,5))
indices = array((1,1,1,1))
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我执行操作:
a[indices] += 1
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结果是
array([1, 3, 3, 4, 5])
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换句话说,重复的内容indices被忽略
如果我希望重复项不被忽略,导致:
array([1, 6, 3, 4, 5])
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我该怎么办呢?
上面的例子有点微不足道,接下来正是我想要做的事情:
def inflate(self,pressure):
faceforces = pressure * cross(self.verts[self.faces[:,1]]-self.verts[self.faces[:,0]], self.verts[self.faces[:,2]]-self.verts[self.faces[:,0]])
self.verts[self.faces[:,0]] += faceforces
self.verts[self.faces[:,1]] += faceforces
self.verts[self.faces[:,2]] += faceforces
def constrain_lengths(self):
vectors = self.verts[self.constraints[:,1]] - self.verts[self.constraints[:,0]]
lengths = sqrt(sum(square(vectors), axis=1))
correction = 0.5 * (vectors.T * (1 - (self.restlengths / lengths))).T
self.verts[self.constraints[:,0]] += correction
self.verts[self.constraints[:,1]] -= correction
def compute_normals(self):
facenormals = cross(self.verts[self.faces[:,1]]-self.verts[self.faces[:,0]], self.verts[self.faces[:,2]]-self.verts[self.faces[:,0]])
self.normals.fill(0) …Run Code Online (Sandbox Code Playgroud) 我试图找出如何在numpy中进行一种标量矩阵乘法.
我有
a = array(((1,2,3),(4,5,6)))
b = array((11,12))
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而且我想做
a op b
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以导致
array(((1*11,2*11,3*11),(4*12,5*12,6*12))
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现在我使用以下表达式
c = a*array((b,b,b)).transpose()
似乎必须有一种更有效的方法来做到这一点