小编eca*_*ano的帖子

我试图模板化几个类(LinkedListNode和LinkedList),这样

template <class T>
class LinkedListNode{
    public:
        T data;
        LinkedListNode *next;
        LinkedListNode();
};

在我的LinkedList类中,我有私有变量:

private:
    LinkedListNode *head;
    //iterator for traversing the list
    LinkedListNode *current;

};

编译时,我遇到了奇怪的错误:

./LinkedList.h:38:3:错误:未知类型名称'LinkedListNode'; 你是说'LinkedList'吗？LinkedListNode*head; ^ ~~~~~~~~~~~~~ LinkedList ./LinkedList.h:13:7:注意:'LinkedList'在这里声明了LinkedList {^ ./LinkedList.h:40:3:错误:未知类型name'LinkedListNode'; 你是说'LinkedList'吗？LinkedListNode*current; ^ ~~~~~~~~~~~~~ LinkedList ./LinkedList.h:13:7:注意:'LinkedList'在这里声明类LinkedList {^ LinkedList.cpp:7:1:错误:'LinkedListNode'是不是类,命名空间或枚举LinkedListNode :: LinkedListNode(){^./ LinkedList.h:5:7:注意:'LinkedListNode'在这里声明类LinkedListNode {^

如果我的LinkedListNode也被声明,为什么我会收到这些错误？

我试图使用<<运算符来调用链表上的插入方法,例如:

a<<b
takes data b and inserts it into LinkedList a

这是我在.h和.cpp文件中的实现:

class LinkedList{
public:
    LinkedList();
    LinkedList(const LinkedList &l); //copy constructor
    ~LinkedList(); //destructor

    //read the list for items
    bool reset();
    bool next();
    int get();
    //insert an item in the list
    bool insert();
    bool insert(int &data);

    //delete an item in the list
    bool remove();

    //Should take data b and add it to the linked list a
    void operator<< (int data);
;
    //advances the internal iterator 1 node if not null
    void …