小编ban*_*nah的帖子

我是bash脚本的新手,我正在努力让这个工作:

扫描IP范围以查找打开端口80的设备...我认为它必须如下所示:

#!/bin/bash
echo -----------------------------------
for ip in 192.168.0.{1,.255}; do
nmap -p80 192.168.0.1
      if #open; then
            echo "{ip} has the port 80 open"
      else
            #do nothing
fi
done
echo -----------------------------------
exit 0

我也想看到这样的结果:

-----------------------------------
192.168.0.1 has the port 80 open
192.168.0.10 has the port 80 open
192.168.0.13 has the port 80 open
192.168.0.15 has the port 80 open
-----------------------------------

(所以没有错误或nmap正常输出..)

有人可以帮助我吗？