我在Ec2上使用基础amazon ami linux-我已经安装了jenkins但是当我从github拉回购时我发出以下错误:
Building in workspace /var/lib/jenkins/workspace/build social
Checkout:build social / /var/lib/jenkins/workspace/build social - hudson.remoting.LocalChannel@5c7b21b
Using strategy: Default
Cloning the remote Git repository
Cloning repository origin
ERROR: Error cloning remote repo 'origin' : Could not clone git@github.com:adulion/.git
hudson.plugins.git.GitException: Could not clone git@github.com:adulion/.git
at hudson.plugins.git.GitAPI.clone(GitAPI.java:245)
at hudson.plugins.git.GitSCM$2.invoke(GitSCM.java:1117)
at hudson.plugins.git.GitSCM$2.invoke(GitSCM.java:1059)
at hudson.FilePath.act(FilePath.java:832)
at hudson.FilePath.act(FilePath.java:814)
at hudson.plugins.git.GitSCM.checkout(GitSCM.java:1059)
at hudson.model.AbstractProject.checkout(AbstractProject.java:1218)
at hudson.model.AbstractBuild$AbstractRunner.checkout(AbstractBuild.java:581)
at hudson.model.AbstractBuild$AbstractRunner.run(AbstractBuild.java:470)
at hudson.model.Run.run(Run.java:1421)
at hudson.model.FreeStyleBuild.run(FreeStyleBuild.java:46)
at hudson.model.ResourceController.execute(ResourceController.java:88)
at hudson.model.Executor.run(Executor.java:238)
Caused by: hudson.plugins.git.GitException: Command "git clone --progress -o origin git@github.com:adulion/.git /var/lib/jenkins/workspace/build social" …我一直在尝试使用一些ajax来保存我的应用程序中的场所位置,并在堆栈溢出时偶然发现以下代码
function getLatLong(address)
{
var geocoder = new google.maps.Geocoder();
var result = "";
geocoder.geocode( { 'address': address, 'region': 'uk' }, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
result[lat] = results[0].geometry.location.Pa;
result[lng] = results[0].geometry.location.Qa;
} else {
result = "Unable to find address: " + status;
}
});
return result;
}
我的问题是当我调用函数时它什么也没有返回,当我调试并在chrome中设置断点时,它会在返回结果之前先破坏结果[lat] = results [0] .geometry.location.Pa;
我知道数组应该声明为类型数组,但即使我刚刚返回结果[0] .geometry.location对象也没有被返回
我该怎么做才能返回lat/long的位置,以便我可以存储在我的数据库中？
我在chrome和firefox中尝试了pjax示例,我拿了示例代码并将其放入我自己的应用程序中,但它仍然会进行整页重新加载.发生AJAX请求然后页面继续运行而不更新#main div
<html>
<head>
<script src="http://cdnjs.cloudflare.com/ajax/libs/jquery/1.8.0/jquery-1.8.0.min.js"></script>
<script src="http://localhost:8888/jul/js/jquery.pjax.js"></script>
<script type="text/javascript">
// $(document).ready(function(){
// $('a[data-pjax]').pjax();
// })
// $(document).ready(function(){
// $('a').pjax({
// container: '#main'
// })
$('document').ready(function(){
$('ul a').pjax('#main')
});
</script>
</head>
<body>
11:59:36 <div id="main">
<div class='loader' style='display:none'><img src='http://localhost:8888/jul/imgs/spinner.gif'></div><ul>
<li><a data-pjax='#main' href="/jul/stats/pjax_stats/index/">Index</a></li>
<li><a data-pjax='#main' href="/jul/stats/pjax_stats/total_posts/">total_posts</a></li>
<li><a data-pjax='#main' href="http://localhost:8888/jul/stats/pjax_stats/index">Index</a></li>
<li><a data-pjax='#main' href="http://localhost:8888/jul/stats/pjax_stats/total_posts">total_posts</a></li>
<li><a href="http://localhost:8888/jul/stats/pjax_stats/total_graph">total_graph</a></li>
<li><a href="http://localhost:8888/jul/stats/pjax_stats/twitter_graph">twitter_graph</a></li>
<li><a href="http://localhost:8888/jul/stats/pjax_stats/facebook_graph">facebook_graph</a></li>
</ul>index files
</div>
</body>
</html>
我已经尝试了多种方法来调用pjax,也许其他人可以指出我哪里出错了？Ajax/GET似乎在firebug控制台中恢复正常 - 这是我的php产生pjax响应的一个例子
public function total_posts(){
// print_r($_SERVER);
if (!isset($_SERVER["X_PJAX"])) {
$this->load->view('stats/pjax_stats/header');
$this->load->view('stats/pjax_stats/links');
}else{
echo "pjax";//add in for …是否可以在数据库事务中刷新物化视图？
我正在 Laravel 中为复杂查询编写测试用例，它使用事务在测试运行后回滚。
当我添加数据并刷新视图时 - 当我执行 select 语句时不会出现任何记录
我现在想不清楚,我想通过station_id返回计数,输出的例子是:
station 1有3个fb帖子,6个linkedin帖子,5个邮件帖子站2个有3个fb帖子,6个linkedin帖子,5个邮件帖子
所以我需要按站ID分组,我的表结构是
CREATE TABLE IF NOT EXISTS `posts` (
`post_id` bigint(11) NOT NULL auto_increment,
`station_id` varchar(25) NOT NULL,
`user_id` varchar(25) NOT NULL,
`dated` datetime NOT NULL,
`type` enum('fb','linkedin','email') NOT NULL,
PRIMARY KEY (`post_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=x ;
到目前为止我的查询是返回0站,当它有一个时有2个帖子(db tho中有2个)
SELECT Station_id, (select count(*) FROM posts WHERE type = 'linkedin') AS linkedin_count, (select count(*) FROM posts WHERE type = 'fb') AS fb_count, (select count(*) FROM posts WHERE type = 'email') AS email_count FROM `posts` GROUP BY station_id;
我努力去除导航列表的最后一项上的"管道"边界 - 我的代码 -
<div id="header">
<ul id="menu">
<li><a href="">Home</a></li>
<li><a href="">Stories</a></li>
<li><a href="">Tell your story</a></li>
<li><a href="">Prizes</a></li>
<li><a href="">How to tips</a></li>
</li>
</div>
而我的CSS
#menu li{
float:left;
list-style-type: none;
display:inline;
padding:0 .9em;
border-right:1px solid #d2d2d2;;
}
#menu li.last{
border-right:none;
}
我使用以下代码访问链接(对于phpunit/selenium):
//td[normalize-space() ='Test title 2']/following-sibling::td[3]/a[.='delete']
在FireFox中使用XPath检查器它会返回7个元素(因为有7个链接匹配"test title 2"),但是当我[1]在最后添加时:
//td[normalize-space() ='Test title 2']/following-sibling::td[3]/a[.='delete'][1]
它仍然返回7个链接.我在这做错了什么？