小编Vik*_*yap的帖子

我迁移到Android studio 3.0.因此,项目无法编译名为":animator"的模块,它会显示以下错误:

 Error:Unable to resolve dependency for
 ':app@dexOptions/compileClasspath': Could not resolve project
 :animators. <a
 href="openFile:/home/mobilepowered/MobilePowered/MyInnovalee/trunk17-10-2017/app/build.gradle">Open
 File</a><br><a href="Unable to resolve dependency for
 &#39;:app@dexOptions/compileClasspath&#39;: Could not resolve project
 :animators.">Show Details</a>

并显示详细信息提供此日志:

 Unable to resolve dependency for ':app@dexOptions/compileClasspath':
 Could not resolve project :animators.

 Could not resolve project :animators. Required by:
     project :app
 Unable to find a matching configuration of project :animators:
      - Configuration 'debugApiElements':
          - Required com.android.build.api.attributes.BuildTypeAttr 'dexOptions' and found incompatible value 'debug'.
          - Required com.android.build.gradle.internal.dependency.AndroidTypeAttr 'Aar' and
 found compatible value 'Aar'. …

不确定这是否是Spring 5.0.3的一个错误或一个新功能来解决我的问题.

升级后,我收到此错误.有趣的是,此错误仅在我的本地计算机上.使用HTTPS协议的测试环境上的相同代码工作正常.

继续...

我收到此错误的原因是因为我加载生成的JSP页面的URL是/location/thisPage.jsp.评估代码request.getRequestURI()给了我结果/WEB-INF/somelocation//location/thisPage.jsp.如果我将JSP页面的URL修复为此location/thisPage.jsp,则工作正常.

所以我的问题是,我应该/从JSP代码中的路径中删除,因为这是未来需要的.或者Spring引入了一个错误,因为我的机器和测试环境之间的唯一区别是协议HTTP与HTTPS.

org.springframework.security.web.firewall.RequestRejectedException:请求被拒绝,因为URL未规范化.org.springframework.security.web.firewall.StrictHttpFirewall.getFirewalledRequest(StrictHttpFirewall.java:123)org.springframework.security.web.FilterChainProxy.doFilterInternal(FilterChainProxy.java:194)org.springframework.security.web.FilterChainProxy .doFilter(FilterChainProxy.java:186)org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:357)org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:270)

我想知道,如果它是用在InnoDB中可能MySQL有一个table与外键引用在不同的另一个表database？

如果是这样,如何做到这一点？

我正在尝试使用HashSet来存储我创建的类的对象,但显然相同的对象似乎有两个不同的哈希值,这就是为什么contains方法没有意识到该对象已经在HashSet中.这导致我的程序耗尽堆内存.

我不认为我做错了什么,但无论如何我想要第二意见.我做过类似的操作,之前一切正常,这使得这特别烦人.我很感激任何帮助.

这是我的代码

move1 = new Move(t,s);
if(move1.hashCode()==new Move(t,s).hashCode())
    System.out.println("match");
move2 = new Move(s,t);
moves.add(move1); 
moves.add(move2);
if(moves.contains(new Move(t,s)))
    System.out.println("match found");

这是Move类:

public class Move {
    private int move1;
    private int move2;

    Move(int m1, int m2)
    {
        move1 = m1;
        move2 = m2;
    }

    public String toString()
    {
         return String.valueOf(move1)+" "+String.valueOf(move2);
    }
}

这是我得到的输出

Exception in thread "main" java.lang.OutOfMemoryError: Java heap space
    at java.util.HashMap.addEntry(HashMap.java:797)
    at java.util.HashMap.put(HashMap.java:431)
    at java.util.HashSet.add(HashSet.java:194)
    at makeMove.<init>(makeMove.java:33)

有没有办法使用javax.validation验证一个名为color的字符串类型的变量,需要使用注释只有这些值(红色,蓝色,绿色,粉红色)？

我所看到的 @size(min=1, max=25)和@notnull,但有没有这样的事情@In(red, blue, green, pink)

或多或少类似于In-keyword用于mysql

我有一个关于Java继承的问题.

我有两个班A,并B和B类,继承自答:

public class A {
     public A() {
         System.out.println("Hi!");
     }
}


public class B extends A {
     public B() {
         System.out.println("Bye!");
     }

     public static void main(String[] args) {
         B b = new B();
     }
}

当我运行程序B时,输出是:

Hi!
Bye!

问:为什么构造函数的class A调用,当我创建和对象的class B？

我知道B继承了A - 所有实例或类变量以及所有方法的所有内容,在这个意义上,B的对象具有A的所有特征以及B中定义的一些其他特征.但是,我不知道并且没有'我想象当我创建一个B类型的对象时,也会调用A的构造函数.所以写下这个:

B b = new B();

创建两个对象 - 一个是B类,另一个是A类.

这很有趣,

有人可以解释为什么会发生这种情况吗？

我是春季启动的新手,当我尝试启动服务器时,我得到以下异常.我知道这与依赖冲突有关,但仍无法解决.我正在使用maven来管理我的依赖项.请帮助

 Exception in thread "main" java.lang.IllegalArgumentException:
 LoggerFactory is not a Logback LoggerContext but Logback is on the
 classpath. Either remove Logback or the competing implementation
 (class org.slf4j.impl.Log4jLoggerFactory) Object of class
 [org.slf4j.impl.Log4jLoggerFactory] must be an instance of class
 ch.qos.logback.classic.LoggerContext   at
 org.springframework.util.Assert.isInstanceOf(Assert.java:339)  at
 org.springframework.boot.logging.logback.LogbackLoggingSystem.initialize(LogbackLoggingSystem.java:93)
        at
org.springframework.boot.logging.AbstractLoggingSystem.initializeWithSensibleDefaults(AbstractLoggingSystem.java:62)
        at

 org.springframework.boot.logging.AbstractLoggingSystem.beforeInitialize(AbstractLoggingSystem.java:45)
    at

org.springframework.boot.logging.logback.LogbackLoggingSystem.beforeInitialize(LogbackLoggingSystem.java:69)
    at

 org.springframework.boot.logging.LoggingApplicationListener.onApplicationEvent(LoggingApplicationListener.java:135)
    at

 org.springframework.context.event.SimpleApplicationEventMulticaster.multicastEvent(SimpleApplicationEventMulticaster.java:98)
    at

 org.springframework.boot.context.event.EventPublishingRunListener.publishEvent(EventPublishingRunListener.java:100)
    at

 org.springframework.boot.context.event.EventPublishingRunListener.started(EventPublishingRunListener.java:54)
    at

 org.springframework.boot.SpringApplication.run(SpringApplication.java:276)
    at

 org.springframework.boot.SpringApplication.run(SpringApplication.java:952)
    at

 org.springframework.boot.SpringApplication.run(SpringApplication.java:941)
    at org.magnum.mobilecloud.video.Application.main(Application.java:30)

已解决:将以下内容添加到POM.xml中

    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-web</artifactId>
        <exclusions>
            <exclusion>
                <groupId>org.springframework.boot</groupId>
                <artifactId>spring-boot-starter-tomcat</artifactId>
            </exclusion>
            <exclusion>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-logging</artifactId>
            </exclusion>
    </exclusions>
    </dependency>
    <dependency> …

关于camera2人脸识别机制的信息不足.我使用了Google的Camera2示例: android-Camera2Basic

我将人脸识别模式设置为FULL.

mPreviewRequestBuilder.set(CaptureRequest.STATISTICS_FACE_DETECT_MODE,
                                    CameraMetadata.STATISTICS_FACE_DETECT_MODE_FULL);

我也查了一下

STATISTICS_INFO_MAX_FACE_COUNT并且STATISTICS_INFO_AVAILABLE_FACE_DETECT_MODES:

int max_count = characteristics.get(
CameraCharacteristics.STATISTICS_INFO_MAX_FACE_COUNT);
int modes [] = characteristics.get(
CameraCharacteristics.STATISTICS_INFO_AVAILABLE_FACE_DETECT_MODES);

输出:maxCount:5,模式:[0,2]

我的CaptureCallback:

 private CameraCaptureSession.CaptureCallback mCaptureCallback
 = new CameraCaptureSession.CaptureCallback() {

    private void process(CaptureResult result) {
                Integer mode = result.get(CaptureResult.STATISTICS_FACE_DETECT_MODE);
                Face [] faces = result.get(CaptureResult.STATISTICS_FACES);
                if(faces != null && mode != null)
                    Log.e("tag", "faces : " + faces.length + " , mode : " + mode ); 
    }

    @Override
    public void onCaptureProgressed(CameraCaptureSession session, CaptureRequest request,
                                    CaptureResult partialResult) {
        process(partialResult); …

我尝试使用Amazon-SDK(Java)示例代码S3TransferProgressSample.java将大文件上传到Amazon-S3存储(也在AWS docs上发布).

但是,当我尝试上传11 GB文件时,上传卡在不同的位置,并显示错误消息:

Unable to upload file to Amazon S3: Unable to upload part: Unable toexecute HTTP request: Unbuffered entity enclosing request can not be repeated " (attached screenshot). 

看起来在IOException发生后,SDK无法重试请求(见下文).

有没有人遇到这个？解决此问题的最佳做法是什么？任何代码表示赞赏.

 INFO: Received successful response: 200, AWS Request ID:
 2B66E7669E24DA75<br> Jan 15, 2011 6:44:46 AM
 com.amazonaws.http.HttpClient execute<br> INFO: Sending Request: PUT
 s3.amazonaws.com /test_file_upload/autogenerated.txt Parameters:
 (uploadId:
     m9MqxzD484Ys1nifnX._IzJBGbCFIoT_zBg0xdd6kkZ4TAtmcG0lXQOE.LeiSEuqn6NjcosIQLXJeKzSnKllmw--, partNumber: 1494, )<br> Jan 15, 2011 6:45:10 AM
     org.apache.commons.httpclient.HttpMethodDirector executeWithRetry<br>
     **INFO: I/O exception (java.net.SocketException) caught when processing request: Connection …

我正在读一个字符串

Is Mississippi a State where there are many systems.

我想用"t"或"T"替换每个单词中的第一个"s"或"S"(即保持相同的情况)...以便输出为:

It Mitsissippi a Ttate where there are many tystems.

我试过了

s= s.replaceFirst("(?i)S", "t"); [which of course didn't work]

并且已经尝试尝试使用字符串[]分割字符串.split(Pattern.quote("\\s")),然后试图找出如何replaceFirst()的每一个元素array,然后返回值回string[ 但不能想出这样做的正确的方式.

我认为\\G可能有助于重新开始下一个单词,但没有在哪里.任何使用这3种方法的帮助表示赞赏.