假设我有一个文件中的字符串列表(例如Python脚本),如下所示:
my_list_of_numbers = ["one two",
"three four",
"five six",
"seven eight",
"nine ten",
"eleven twelve"]
Run Code Online (Sandbox Code Playgroud)
如果我对这个文本进行了直观的选择,我可以gq用来包装文本来获得:
my_list_of_numbers = ["one two", "three four", "five six", "seven eight", "nine
ten", "eleven twelve"]
Run Code Online (Sandbox Code Playgroud)
但是,该元素"nine ten"现在被分成两行.
如何在避免在开放引号内输入换行符时包装文本?我想要的结果如下:
my_list_of_numbers = ["one two", "three four", "five six", "seven eight",
"nine ten", "eleven twelve"]
Run Code Online (Sandbox Code Playgroud) 我试图了解R如何确定线性模型中相互作用的参考组.考虑以下:
df <- structure(list(id = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L,
2L, 2L, 2L, 2L, 3L, 3L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 4L, 4L, 4L,
5L, 5L, 5L, 5L, 5L, 5L), .Label = c("1", "2", "3", "4", "5"), class = "factor"),
year = structure(c(1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L,
1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L, 2L, 1L,
2L, 1L, 2L, 1L, 2L), .Label = c("1", …Run Code Online (Sandbox Code Playgroud)