小编use*_*ser的帖子

在infusionsoft中添加订单商品的问题

我在infusionsoft api中添加了一个orderitem ..但是我收到语法错误但我无法找到.

 require_once($_SERVER['DOCUMENT_ROOT']."/infusionsoftAPI/src/isdk.php");
 $app = new iSDK;

 $_REQUEST['contactId'] = 4;

 if(!empty($_REQUEST['contactId']))
 {
    if ($app->cfgCon("aaaa", 'eeeeeeeeeeeeeeeeeeeeeeeeeeeeeee')) {
        echo "Infusionsoft Connection Successfulls";
    } else {
        echo "Infusionsoft Connection Failed";
        exit;
    }
} else {
    echo '<p>No contact id selected.</p>';
    exit();
}
some code
some code
$invoiceId = $app->blankOrder($contactId,"Video Report Subscription - Extra", $oDate,0,0);
$extra_price = $extraemail * $result['price_after_expire'];

$ordresult = $app->addOrderItem($invoiceId, 4, 9, $extra_price, 1, "helloo", "aaaaaa");
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我收到这个错误

错误:-1 - 没有匹配参数的方法:java.lang.String,java.lang.Integer,java.lang.Integer,java.lang.Integer,java.lang.Integer,java.lang.Integer,java.lang. String,java.lang.String

但是当我写作时

  $ordresult = $app->addOrderItem($invoiceId, 4, 9, 22.00, 1, "helloo", …
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php infusionsoft

5
推荐指数
1
解决办法
340
查看次数

单个索引多个数组到一个数组

我有很多数组:

Array ( [0] => A-I-only )
Array ( [0] => B-III-only )
Array ( [0] => C-I-and-II-only )
Array ( [0] => D-II-and-III-only )
Array ( [0] => E-I,-II,-III ) 
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我想将每个数组的第一行放在一个数组中,如下所示:

Array( [0] => A-I-only [1] =>B-III-only [2] => C-I-and-II-only [3] => D-II-and-III-only [4] => E-I,-II,-III )
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有办法吗?

php arrays

1
推荐指数
1
解决办法
57
查看次数

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php ×2

arrays ×1

infusionsoft ×1