我有一个字符串是:
!"#$%&'()*+,-./0123456789:;?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[]\^_`abcdefghijklmnopqrstuvwxyz{|}~¡¢£¤¥¦§¨©ª« ®¯°±²³´µ¶•¸¹º»¼½¾¿ÀÁÂÃÄÅàáâäèçéêëìíîïôö÷òóõùúý
我将其发布到服务并使用Htmlencode,然后我得到一个结果:
!#$%&'()* ,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[]^_`abcdefghijklmnopqrstuvwxyz{|}~??????????? ?????????•????????????????????????????????????
这不是我需要的结果,我怎么得到原始字符串?谢谢!
我一直认为SQL编译器会破坏,但显然nesing几乎可以无限.这个代码是立即被破坏还是有一些希望,这样的东西可以起作用?
这个查询并不属于我,所以我不能发布它...但是,让我们假装它是这个:
[SELECT /*+ NOPARALLEL bypass_recursive_check */
SP_ALIAS_190,
((CASE SP_ALIAS_191
WHEN 1
THEN 'PROVIDER::ALL_PROV::'
WHEN 0]
Run Code Online (Sandbox Code Playgroud) 我many_to_many在ImageShells和用户之间有关系.我需要找到所有没有用户的ImageShells.
我有一个查找它的查询,但我如何把它放入named_scope?
SELECT * FROM image_shells INNER JOIN image_shells_users ON (image_shells_users.image_shell_id!=image_shells.id)
class ImageShell < ActiveRecord::Base
has_and_belongs_to_many :riders, :class_name => "User"
end
class User < ActiveRecord::Base
has_and_belongs_to_many :image_shells
end
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我可以使用find by sql但这很麻烦.
img_shells_with_out_users = ImageShell.find_by_sql 'SELECT * FROM image_shells INNER JOIN image_shells_users ON (image_shells_users.image_shell_id!=image_shells.id)'
Run Code Online (Sandbox Code Playgroud) char buffer[256];
for(int x = 0; x<256; x+=4)
{
char one = buffer[x];
char two = buffer[x+1];
char three = buffer[x+2];
char four = buffer[x+3];
buffer[x] = four;
buffer[x+1]=three;
buffer[x+2]= two;
buffer[x+3]=one;
}
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我究竟如何优化这个?
我收到错误关键字'Order'附近的语法错误.
protected void btnSubmit_Click(object sender, EventArgs e)
{
SqlCommand cmd = new SqlCommand("Insert INTO Order (Cust_Num, Sale_Num) VALUES (@cust_num, @sale_num))", conn);
cmd.CommandType = CommandType.Text;
cmd.Parameters.AddWithValue("@cust_num", txtBxCustNum.Text);
cmd.Parameters.AddWithValue("@sale_num", txtBxSaleNum.Text);
conn.Open();
cmd.ExecuteNonQuery();
conn.Close();
}
Run Code Online (Sandbox Code Playgroud) 嗨,我正在尝试将xml保存到文件,并在文件的开头不断添加不同的字符.
我的代码是
string strCXML2;
strCXML2 = "<input type=" + "\"" + "hidden" + "\"" + " name=" + "\"" + "cxml-urlencoded" + "\"" + " value=" + "\"";
strCXML2 = strCXML2 + "<!DOCTYPE cXML SYSTEM " + "\"" + "http://xml.cxml.org/schemas/cXML/1.2.023/cXML.dtd" + "\"" + ">";
//<snip>
BinaryWriter bw5 = new BinaryWriter(File.Open(Server.MapPath("~/data/test/test19.xml"), FileMode.OpenOrCreate))
bw5.Write(strCXML2);
bw5.Close();
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每次在某个其他垃圾角色时,它会在xml"}"中返回以下文件
}<input type="hidden" name="cxml-urlencoded" value="<!DOCTYPE cXML SYSTEM "http://xml.cxml.org/schemas/cXML/1.2.023/cXML.dtd">
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任何想法为什么这样做?
我有一个字典,看起来像这样:
Dictionary<String, String> dictionary = new Dictionary<string, string>{
{ "dog", "DOG" },
{ "cat", "CAT" },
...continued
};
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我想从具有匹配值的列表中提取Id值,如下所示:
List<Animal> records = new List<Animal>{
{ Id: "1", Name: "DOG" },
{ Id: "2", Name: "CAT" }
...continued
}
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我需要输出一个如下所示的字典:
Dictionary<String, String> newDictionary = new Dictionary<string, string>
{ "dog": "1" },
{ "cat": "2 }
...continued
}
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有一个简单的LINQ解决方案吗?
tl;dr:我有一个应该是的列,NVARCHAR(MAX)但是用脚手架进行迁移Add-Migration给了我一个最大长度为 4000 in 的列Up()。我必须做什么才能做到这一点MAX?
考虑以下模型:
public class Foo
{
public int Id { get; set; }
[Required]
[StringLength(100)]
public string Name { get; set; }
[Required]
[DataType(DataType.MultilineText)]
public string Memo { get; set; }
[Required]
[DataType(DataType.EmailAddress)]
public string Email { get; set; }
}
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我在以下地方建立了两个约定Context.OnModelCreating:
将任何未配置的字符串属性的默认 maxLength 设置为 1024 的约定,其中包含以下行:
Properties<string>().Configure(c => c.HasMaxLength(1024));
Run Code Online (Sandbox Code Playgroud)基于属性的约定,读取DataTypeAttribute并相应地设置一些属性,即列类型和长度:
switch (attribute.DataType)
{
case DataType.MultilineText:
configuration.HasColumnType("nvarchar").IsMaxLength();
break;
case DataType.EmailAddress:
configuration.HasColumnType("nvarchar").HasMaxLength(255);
break;
}
Run Code Online (Sandbox Code Playgroud)我在设置迁移之前测试了这一切,它工作得很好,给了我下表 - …
当我编译这段代码时,我收到一条"可能错误的空语句"警告:
class Lab6
{
static void Main(string[] args)
{
Program fileOperation = new Program();
Console.WriteLine("Enter a name for the file:");
string fileName = Console.ReadLine();
if (File.Exists(fileName))
{
Console.WriteLine("The file name exists. Do you want to continue appendng ? (Y/N)");
string persmission = Console.ReadLine();
if (persmission.Equals("Y") || persmission.Equals("y"))
{
fileOperation.appendFile(fileName);
}
}
else
{
using (StreamWriter sw = new StreamWriter(fileName)) ;
fileOperation.appendFile(fileName);
}
}
public void appendFile(String fileName)
{
Console.WriteLine("Please enter new content for the file - type Done and press …Run Code Online (Sandbox Code Playgroud) c# ×3
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.net ×1
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