我不想将docker secrets与swarm一起使用，我发现这样做是可行的。基本上，docker只是将/ run / secrets挂载到docker容器中，但是当我进入新建的docker容器并echo $POSTGRES_PASSWORD_FILE获取我的秘密文件的路径时。

root@94a0f092eeb1:/# echo $POSTGRES_PASSWORD_FILE
/run/secrets/db_password

这是我的docker-compose.yml档案

version: '3.1'
services:
    postgres:
        image: postgres:9.4
        container_name: postgres
        environment:
            POSTGRES_USER: "db_user"
            POSTGRES_PASSWORD_FILE: /run/secrets/db_password
            POSTGRES_DB: "my_db"
        secrets:
          - db_password
        volumes:
            - ./postgres:/var/lib/postgresql/data
        expose:
            - 5432
secrets:
   db_password:
     file: ./POSTGRES_PASSWORD.txt

我的密码设置正确/文件有问题吗？

我正在尝试将项目经理分配给员工.

• 每个员工都可以成为项目经理.

• 项目经理可以拥有多名员工.

• 员工只能拥有1名项目经理.

但是,当我这样做 Employee.objects.get(name='HereHere').get_xxx()

我有 AttributeError: 'ManyToManyField' object has no attribute '_m2m_reverse_name_cache'

class Employee(models.Model):
    name = models.CharField(max_length=20, unique=True)
    pm = models.ManyToManyField('self', symmetrical=False, through='PM', related_name='related_to', )

    def add_pm(self, employee, ):
        pm, created = PM.objects.get_or_create(from_employee=self, to_employee__in=employee,)
        return pm

    def remove_pm(self, employee, ):
        PM.objects.filter(
            from_employee=self,
            to_employee=employee,
        ).delete()
        return

    def get_relationships(self, ):
        return self.pm.filter(
            to_employee__from_employee=self)   #<----- AttributeError: 'ManyToManyField' object has no attribute '_m2m_reverse_name_cache'

    def get_related_to(self,):
        return self.related_to.filter(
            from_employee__to_employee=self)    #<----- AttributeError: 'ManyToManyField' object has no attribute '_m2m_reverse_name_cache'


    def __str__(self):
        return '%s' % self.name …

views.py

from forms.py import PersonCreateForm

class PersonCreateView(CreateView):
    model = Person
    form_class = PersonCreateForm
    template_name = "my_app/create_person.html"

    def form_valid(self, form):
        self.object = form.save()
        return redirect('/homepage/')


class PeopleListView(ListView):
        [...]
        context.update({
            'task_form': TaskCreateForm(),

        return context

在我的模板中,我只需添加处理PersonCreateView的动作URL.

<form action="{% url 'people_create' %}" method="post">{% csrf_token %}

当Form有效时,所有数据都保存没有问题,并将其重定向到'/ homepage /.但是当我的表单无效时,它会将我重定向到{% url 'people_create' %}并在/ homepage/people_create /中显示错误

我怎么能避免这种情况？我希望所有错误显示在同一页面而不重定向.

[datetime.datetime(2015, 6, 23, 0, 0), datetime.datetime(2015, 6, 24, 0, 0)]

到

[datetime.datetime(2015, 6, 23, 0, 0).date(), datetime.datetime(2015, 6, 24, 0, 0).date()]

所以我可以这样：

[datetime.date(2015, 6, 23), datetime.date(2015, 6, 24)]