我试图用一个自定义视图控件创建一个自定义演示者，将视频播放到表面视图中，并在第一次绑定后收到此错误消息。有什么问题？我没有设置任何布尔值来冻结裁员或类似的信息。
整个项目可以在这里找到
java.lang.IllegalStateException: Do not setLayoutFrozen in layout or scroll
at android.support.v7.widget.RecyclerView.assertNotInLayoutOrScroll(RecyclerView.java:2164)
at android.support.v7.widget.RecyclerView.setLayoutFrozen(RecyclerView.java:1750)
at android.support.v17.leanback.app.BaseRowFragment.onTransitionStart(BaseRowFragment.java:199)
at android.support.v17.leanback.app.RowsFragment.onExpandTransitionStart(RowsFragment.java:483)
at android.support.v17.leanback.app.BrowseFragment.startHeadersTransitionInternal(BrowseFragment.java:435)
at android.support.v17.leanback.app.BrowseFragment.access$200(BrowseFragment.java:77)
at android.support.v17.leanback.app.BrowseFragment$3.onRequestChildFocus(BrowseFragment.java:546)
at android.support.v17.leanback.widget.BrowseFrameLayout.requestChildFocus(BrowseFrameLayout.java:124)
at android.view.ViewGroup.requestChildFocus(ViewGroup.java:740)
at android.view.ViewGroup.requestChildFocus(ViewGroup.java:740)
at android.view.ViewGroup.requestChildFocus(ViewGroup.java:740)
at android.support.v7.widget.RecyclerView.requestChildFocus(RecyclerView.java:2081)
at android.view.ViewGroup.requestChildFocus(ViewGroup.java:740)
at android.view.ViewGroup.requestChildFocus(ViewGroup.java:740)
at android.view.ViewGroup.requestChildFocus(ViewGroup.java:740)
at android.support.v7.widget.RecyclerView.requestChildFocus(RecyclerView.java:2081)
at android.view.ViewGroup.addViewInner(ViewGroup.java:4341)
at android.view.ViewGroup.addView(ViewGroup.java:4145)
at android.view.ViewGroup.addView(ViewGroup.java:4086)
at android.support.v7.widget.RecyclerView$5.addView(RecyclerView.java:591)
at android.support.v7.widget.ChildHelper.addView(ChildHelper.java:107)
at android.support.v7.widget.RecyclerView$LayoutManager.addViewInt(RecyclerView.java:6708)
at android.support.v7.widget.RecyclerView$LayoutManager.addView(RecyclerView.java:6666)
at android.support.v7.widget.RecyclerView$LayoutManager.addView(RecyclerView.java:6654)
at android.support.v17.leanback.widget.GridLayoutManager$2.cre ateItem(GridLayoutManager.java:1473)
at android.support.v17.leanback.widget.SingleRow.appendVisibleItems(SingleRow.java:111)
at android.support.v17.leanback.widget.Grid.appendOneColumnVisibleItems(Grid.java:364)
at android.support.v17.leanback.widget.GridLayoutManager.appendOneColumnVisibleItems(GridLayoutManager.java:1696)
at android.support.v17.leanback.widget.GridLayoutManager.onLayoutChildren(GridLayoutManager.java:1881)
at android.support.v7.widget.RecyclerView.disp atchLayoutStep2(RecyclerView.java:3026)
at android.support.v7.widget.RecyclerView.disp atchLayout(RecyclerView.java:2903)
at android.support.v7.widget.RecyclerView.onLayout(RecyclerView.java:3277)
at …我需要发送带有重复键的动态键。
这就是我需要的：
https://myApi.com/pepole?name=yoni&name=albert&brand=nike
所有的关键都是动态（名称，品牌）。
所以要动态地做到这一点，我用于@Querymap示例：
Map<String, String> parms = new HashMap<>();
parms.put(dynamicKey, dynamicValue);
parms.put(anotherDynamicKey,anotherDynamicValue);
这是我的界面：
@Get("pepole")
Call<List> searchPepole(
@Querymap Map<String, String> options);
并且工作正常，但是当我有重复的密钥时，我的问题就开始了。
那么如何使用带有重复键的动态键进行呼叫？
我创建了一个对象来向firebase发送一些数据.作为示例,我使用firebase用户示例:
public class User {
public String username;
public String email;
public User() {
// Default constructor required for calls to DataSnapshot.getValue(User.class)
}
public User(String username, String email) {
this.username = username;
this.email = email;
}
}
我想编码发送到firebase的属性名称.目前,密钥是使用变量名称发送的.我想编码键类似Useraname,并Email像Gson在做什么.我不想更改变量名称.
@SerializateName("Username")
public String username;
@SerializateName("Username")
public String email;
我用过@SerializateName(),但没用.与@PropertyNameFirebse使用的相同,不起作用.我可以使用什么来序列化自定义键？
更新1
public class Pojo {
@PropertyName("Guid")
public String guid;
@PropertyName("Name")
public String name;
public String getPojoGuid() {
return guid;
}
public void setPojoGuid(String …根据这样的教程一个：在Dagger2我们能够提供使用自定义范围本地单一对象。
我已经有一个全局 appComponent，我的目标是创建一个活动范围，允许子组件拥有本地单例提供程序。
我的问题是当我创建一个自定义范围并两次注入我的活动时，我看到提供的对象不是同一个，即使我用自定义范围标记了它。对于使用 @Singleton 注释的 appComponent 来说，它虽然工作正常。让我们来看看我是如何做到的：
这是自定义活动范围：
@Scope
@Retention(RetentionPolicy.RUNTIME)
public @interface ActivityScope {
}
这是我定义子组件的方式：
@ActivityScope
@Subcomponent(modules = {PresenterModule.class, UseCaseModule.class})
public interface ActivitySubComponent {
void inject(LoginActivity target);
void inject(LoginPresenter target);
void inject(UCGetFireBaseAccount target);
}
请注意，我已经使用上面自定义的 @ActivityScope 注释标记了这个子组件。现在让我们看看 appComponent，它是父组件和全局组件：
@Singleton
@Component(modules = {AppModule.class, NetworkModule.class, RepositoryModule.class})
public interface AppComponent {
void inject(myappCloudRepo target);
void inject (FireBaseCloudRepo target);
ActivitySubComponent plus(PresenterModule presenterModule, UseCaseModule useCaseModule);
}
注意 ActivitySubComponent 在这里被定义为一个子组件。
最后让我们看一下 PresenterModule 类，看看我想作为单例提供什么：
@Module
public class PresenterModule {
@Provides
@ActivityScope
LoginPresenter provideLoginPresenter(Context …我在这里写了一段代码：
public class Wizard1 extends GuidedStepFragment implements Callback {
private boolean sendPhoneNumber(String userPhoneNumber) {
OkHttpClient client = new OkHttpClient();
RequestBody requestBody = new MultipartBody.Builder()
.setType(MultipartBody.FORM)
.addFormDataPart("request_magic_code", Urls.REQUEST_MAGIC_CODE)
.build();
Request request = new Request.Builder()
.url(Urls.HOST + Urls.SEND_PHONE_NUMBER)
.post(requestBody)
.build();
client.newCall(request).enqueue(this);
return success;
}
@Override
public void onFailure(@NonNull Call call, @NonNull IOException e) {
e.printStackTrace();
}
@Override
public void onResponse(@NonNull Call call, @NonNull Response response) throws IOException {
ResponseBody myResponse = response.body();
Log.d("SS", response.body().string());
Log.d("SS", response.body().string());
if (myResponse != null) {
success …我需要执行2 firebase calls以从数据库中检索特定数据。Once these promises resolve，我想用检索到的数据调用另一个函数。我怎样才能做到这一点？..东西Promise.All?
代码如下：
app.post('/testtwilio', function(req, res) {
//save request variables
var to_UID = req.body.to;
var from_UID = req.body.from;
var experience_id = req.body.exp_id;
//Query firebase and save 'zone_id' which we need later
firebase.database().ref('experiences').child(experience_id).once('value').then((snap) => {
zone_id = snap.val().ZoneID;
});
//Query firebase and save 'from_name' which we need later
firebase.database().ref('users').child(from_UID).once('value').then((snap) => {
from_name = snap.val().Name;
});
//Once we have the two variables returned and saved
//Call a final firebase query and a twilio …