小编Sel*_*ier的帖子

我在/ res/raw /文件夹(/res/raw/textfile.txt)中有一个资源文件,我试图从我的Android应用程序中读取进行处理.

public static void main(String[] args) {

    File file = new File("res/raw/textfile.txt");

    FileInputStream fis = null;
    BufferedInputStream bis = null;
    DataInputStream dis = null;

    try {
      fis = new FileInputStream(file);
      bis = new BufferedInputStream(fis);
      dis = new DataInputStream(bis);

      while (dis.available() != 0) {
              // Do something with file
          Log.d("GAME", dis.readLine()); 
      }

      fis.close();
      bis.close();
      dis.close();

    } catch (FileNotFoundException e) {
      e.printStackTrace();
    } catch (IOException e) {
      e.printStackTrace();
    }
  }

我尝试了不同的路径语法但总是得到java.io.FileNotFoundException错误.如何访问/res/raw/textfile.txt进行处理？是File file = new File("res/raw/textfile.txt"); Android中的错误方法？

*答案: …

我想创建一个目录结构表，如本问题所述，其中：

Directory =“主键”id 字段，通常是整数
Directory_Parent =“外键”id 字段，它指向同一个表中另一个目录的 id
Value =包含

给定Tree/Fruit/Apples/ 的目录/文件夹名称的字符串

Directory | Directory_Parent | Value
0           null               Root
1           0                  Tree
2           1                  Fruit
3           2                  Apples

 FileID  Path
      1  videos/gopro/father/mov001.mp4
      2  videos/gopro/father/mov002.mp4
      3  pictures/family/father/Oldman.jpg
      4  pictures/family/father/Oldman2.jpg
      5  documents/legal/father/estate/will.doc
      6  documents/legal/father/estate/will2.doc
      7  documents/legal/father/estate/newyork/albany/will.doc
      8  video/gopro/father/newyork/albany/holiday/christmas/2002/mov001.mp4
      9  pictures/family/father/newyork/albany/holiday/christmas/2002/july/Oldman.jpg
      10 pictures/family/father/newyork/albany/holiday/christmas/2002/june/Oldman2.jpg