小编Sam*_*ram的帖子

迦太基构建失败 Xcode 12 12A7209 构建

迦太基文件内容:

github "SwiftyJSON/SwiftyJSON"
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错误:

Build Failed
Task failed with exit code 1:
/usr/bin/xcrun lipo -create /Users/samrezikram/Library/Caches/org.carthage.CarthageKit/DerivedData/12.0_12A7209/SwiftyJSON/5.0.0/Build/Intermediates.noindex/ArchiveIntermediates/SwiftyJSON\ tvOS/IntermediateBuildFilesPath/UninstalledProducts/appletvos/SwiftyJSON.framework/SwiftyJSON /Users/samrezikram/Library/Caches/org.carthage.CarthageKit/DerivedData/12.0_12A7209/SwiftyJSON/5.0.0/Build/Products/Release-appletvsimulator/SwiftyJSON.framework/SwiftyJSON -output /Users/samrezikram/Downloads/CarthageApp/Carthage/Build/tvOS/SwiftyJSON.framework/SwiftyJSON

This usually indicates that project itself failed to compile. Please check the xcodebuild log for more details: /var/folders/px/jx4gljpj47j06qr7blw6b4w80000gn/T/carthage-xcodebuild.1NVy7o.log
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ios react-native swift5 xcode12

10
推荐指数
2
解决办法
5438
查看次数

检查FaceID是否正确?

对不起,iPhone-X不可用.

在推出iPhone-X之后,每个人都希望他们的应用程序应该与iOS11和touchID兼容,但问题是开发人员测试触摸ID太昂贵了.

我没有iPhone来检查我的代码,但我可以在iOS模拟器中检查相同吗?

let context = LAContext()
if ( context.biometryType == .typeFaceID ) {
      // Face ID
}
if ( context.biometryType == .typeTouchID) {
     // Touch ID
} else {
    // Stone Age
}
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ios touch-id swift iphone-x face-id

5
推荐指数
1
解决办法
3676
查看次数

错误:请求中的额外参数我使用Swift 4.为什么我必须传递[String:Any]类型的参数?

Alamofire.request(APPURL.GetAccounts, method: .post, 
                      parameters: transactionData,
                      encoding: JSONEncoding.default,
                      headers: nil).responseJSON { responseData in }
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我的问题是限制我只能传递类型字典[String:Any]的原因是什么?

完整代码:

class func getAccounts( transactionData: [String:Any]?, withCompletionHandler: @escaping (_ response:AnyObject?)->(Void) ) {

    Alamofire.request(APPURL.GetAccounts, method: .post, 
                      parameters: transactionData,
                      encoding: JSONEncoding.default,
                      headers: nil).responseJSON { responseData in

        if((responseData.result.value) != nil) {
            let swiftyJsonVar = JSON(responseData.result.value!)
            if let resData = swiftyJsonVar["Accounts"].arrayObject {
                let resultData = resData as! [[String:AnyObject]]
                withCompletionHandler(resultData as AnyObject)
            }else{
                withCompletionHandler(nil)
            }
        }else{
            withCompletionHandler(nil)
        }
    }
}
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closures objective-c-blocks swift alamofire swift4

5
推荐指数
0
解决办法
57
查看次数

我们如何为WKInterfaceController移植addGestureRecognizer(识别器)

下面的代码是使用viewController实现的,我可以为Apple Watch做同样的事情并添加动画吗?

let filteredSubviews = self.view.subviews.filter({ $0.isKindOfClass(UIImageView) })// 2
    for view in filteredSubviews  {
        // 3
        let recognizer = UITapGestureRecognizer(target: self, action:Selector("handleTap:"))
        recognizer.numberOfTapsRequired=1
        // 4
        recognizer.delegate = self
        view.addGestureRecognizer(recognizer)
        returnedAray=tempArray
        //TODO: Add a custom gesture recognizer too
    }
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我只需要知道WatchKit的addGestureRecognizer(识别器)的替代方案.

animation apple-watch watchkit wkinterfacetable

2
推荐指数
1
解决办法
563
查看次数