我想通过JavaScript将SVG转换为位图图像(如JPEG,PNG等).
我在SVG工作,只是阅读压缩文件'SVGZ'格式.由于它使我们的文件大小更小,我非常热衷于在我们的Web应用程序中使用它,但浏览器似乎不支持该格式.任何人都可以指向有关如何在在线文档/应用程序中使用SVGZ文件而不是SVG的任何文档.
我正在使用SVG和JS开发Web应用程序.事情进展顺利,但我对数据处理有点困惑.
用户创建的对象的数据会动态附加到SVG根目录.存储此SVG数据的位置和方式,以及如何访问它？我想要阅读它的原因是我想将这个SVG数据转换为HTML5画布(使用Google的canvg),最后将其转换为png图像以存储在我们的数据库中以供参考.
任何指导都将非常感谢.
我想在将图像上传到服务器之前预览图像.我为它编写了一些代码,但由于某些安全原因,它只是在Internet Explorer中预览,而不是在Safari,Chrome,Firefox等其他浏览器中预览.有没有解决方案在这些浏览器中预览图像？
<body>
<form name="Upload" enctype="multipart/form-data" method="post">
Filename: <INPUT type="file" id="submit">
<INPUT type="button" id="send" value="Upload">
</form>
<div
id="div"
align="center"
style="height: 200px;width: 500px;border-style: ridge;border-color: red">
</div>
</body>
<script type="text/javascript">
var img_id=0
var image = new Array()
document.getElementById('send').onclick=function()
{
img_id++
var id="imgid"+img_id
image = document.getElementById('submit').value;
document.getElementById('div').innerHTML="<img id='"+id+"' src='"+image+"' width=500px height=200px>"
}
</script>
</html>
任何人都可以帮助......如何通过Javascript将图像转换为矢量(SVG).......!任何帮助都会很棒....!
我在画布上放了一个图像,当用户将鼠标移到图像上时,我希望获得该图像像素的RGB值.这是我写的代码:
<canvas id="myCanvas" width="200" height="200" style="border: red;border-style: dotted">
Your browser does not support the canvas element.
</canvas>
<script>
var canvas = document.getElementById("myCanvas");
var context = canvas.getContext("2d");
var destX = 0;
var destY = 0;
var imageObj = new Image();
imageObj.onload = function()
{
context.drawImage(imageObj, destX, destY);
};
imageObj.src = "zain.jpg";
canvas.onclick = function(e) {
var x = e.pageX;
var y = e.pageY;
var canvasColor = context.getImageData(x, y, 1,1); // rgba e [0,255]
var pixels = canvasColor.data;
var r = pixels[0]; …我有一个关于JavaScript验证的问题.我确认<input type="file">无论何时我的脚本运行,它都会验证,但也会调用操作页面.我想停止操作页面,直到验证完成.这是我的代码,任何帮助都会很棒.问候
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Image Uploading</title>
</head>
<body>
<form name="xx" action="server.php" method="post" enctype="multipart/form-data" onsubmit="Checkfiles(this)">
<input type="file" name="file_uploading" id="filename">
<input type="submit" value="Submit" name="uploadfile">
</form>
<form name="view" method="post">
<a href="view_server.php">View your uploaded Images</a>
</form>
</body>
</html>
<script type="text/javascript">
function Checkfiles()
{
var fup = document.getElementById('filename');
var fileName = fup.value;
var ext = fileName.substring(fileName.lastIndexOf('.') + 1);
if(ext =="GIF" || ext=="gif")
{
return true;
}
else
{
alert("Upload Gif Images only"); …我想实施
-moz-transition: text-shadow 0.25s ease-in-out,font-size 0.25s ease-in-out;
通过JavaScript的属性.那是什么语法？
嗨我在我的项目中使用Qtip,我需要一些帮助,我已经放置了一个条件,复选框布尔为真,qtip是活动的,现在我想要的是这个我想隐藏qtip当复选框布尔是是的,我怎么能这样做,任何帮助都会很棒.Thnxs提前!
每当我通过Junit进行黄瓜测试时,我都会遇到错误.以下是以下例外情况.任何帮助都会很棒
注意:
项目中没有错误
java.lang.NoClassDefFoundError: cucumber/io/ResourceLoader
at java.lang.Class.getDeclaredConstructors0(Native Method)
at java.lang.Class.privateGetDeclaredConstructors(Class.java:2398)
at java.lang.Class.getConstructor0(Class.java:2708)
at java.lang.Class.getConstructor(Class.java:1659)
at cucumber.runtime.Reflections.hasConstructor(Reflections.java:53)
at cucumber.runtime.Reflections.instantiateSubclasses(Reflections.java:29)
at cucumber.runtime.Runtime.loadBackends(Runtime.java:96)
at cucumber.runtime.Runtime.<init>(Runtime.java:63)
at cucumber.api.junit.Cucumber.createRuntime(Cucumber.java:74)
at cucumber.api.junit.Cucumber.<init>(Cucumber.java:61)
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27)
at java.lang.reflect.Constructor.newInstance(Constructor.java:513)
at org.junit.internal.builders.AnnotatedBuilder.buildRunner(AnnotatedBuilder.java:29)
at org.junit.internal.builders.AnnotatedBuilder.runnerForClass(AnnotatedBuilder.java:21)
at org.junit.runners.model.RunnerBuilder.safeRunnerForClass(RunnerBuilder.java:59)
at org.junit.internal.builders.AllDefaultPossibilitiesBuilder.runnerForClass(AllDefaultPossibilitiesBuilder.java:26)
at org.junit.runners.model.RunnerBuilder.safeRunnerForClass(RunnerBuilder.java:59)
at org.junit.internal.requests.ClassRequest.getRunner(ClassRequest.java:26)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.<init>(JUnit4TestReference.java:33)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestClassReference.<init>(JUnit4TestClassReference.java:25)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestLoader.createTest(JUnit4TestLoader.java:48)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestLoader.loadTests(JUnit4TestLoader.java:38)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:452)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)
Caused by: java.lang.ClassNotFoundException: cucumber.io.ResourceLoader
at java.net.URLClassLoader$1.run(URLClassLoader.java:202)
at java.security.AccessController.doPrivileged(Native Method)
at java.net.URLClassLoader.findClass(URLClassLoader.java:190)
at java.lang.ClassLoader.loadClass(ClassLoader.java:306)
at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301)
at java.lang.ClassLoader.loadClass(ClassLoader.java:247) …<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JSP Page</title>
</head>
<body>
<object id="oo" data="Dynamic_grouping.svg" style="position:fixed;width: 900px;height:750px;bottom: -220px;right: 180px;">
</object>
</body>
<script type="text/javascript">
var far=document.getElementById("oo")
far.addEventListener("load", function (){
var svgDoc=far.contentDocument;
var svgRoot=svgDoc.documentElement;
document.getElementById("bar").onclick=function(){
var g = svgDoc.createElementNS("http://www.w3.org/2000/svg", "g");
g.setAttribute('id', 'group');
g.setAttribute('shape-rendering', 'inherit');
g.setAttribute('pointer-events', 'all');
var use = svgDoc.createElementNS("http://www.w3.org/2000/svg", "use")
use.setAttributeNS("http://www.w3.org/1999/xlink", "xlink:href", "#g1")
use.setAttributeNS(null,"id", "u")
svgRoot.appendChild(use)
var create_bar=svgDoc.createElementNS("http://www.w3.org/2000/svg", "rect")
create_bar.setAttribute("id", "r_bar")
create_bar.setAttribute("fill", "cream")
create_bar.setAttribute("x", "300px")
create_bar.setAttribute("y", "50px")
create_bar.setAttribute("width", "100px")
create_bar.setAttribute("height", "30px")
create_bar.setAttribute("pointer-events", "inherit")
g.appendChild(create_bar)
var cir = svgDoc.createElementNS("http://www.w3.org/2000/svg", "circle");
cir.setAttribute( "id","cir")
cir.setAttribute( "cx","320px") …任何人都可以解释为什么60.61.62.63/26不是有效的主机IP地址？非常感谢你.
javascript ×8
svg ×5
canvas ×2
html5 ×2
css ×1
cucumber ×1
cucumber-jvm ×1
dom ×1
html5-canvas ×1
ip ×1
ip-address ×1
java ×1
jquery ×1
junit ×1
svgz ×1