我有一个divHTML,里面写着一些文字.
将div通过设置它的创建X,Y坐标和height和width.
我想绘制一个三角形叠加,div这样我的内容就不会丢失.
我不能改变的X,Y坐标为我其他div的定位是基于此div.
使用多重div方法生成三角形似乎也不可行,因为我不确定div我将在哪个文本中写下......
有人可以建议我如何做到这一点..?
我是WPF新手,而且我的窗口不再可点击了.
我无法单击一个按钮,我无法编辑文本框.
我正在使用Visual Studio 2015(也是新的).
可能是什么原因?
这里有一些代码:
<Window x:Class="Mxx.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:local="clr-namespace:Mxx"
mc:Ignorable="d"
Title="MainWindow" Height="350" Width="525">
<Grid>
<Grid.RowDefinitions>
<RowDefinition Height="Auto"/>
<RowDefinition Height="26*"/>
</Grid.RowDefinitions>
<Menu>
<MenuItem Header="Log out" Click="MenuItem_Click1"/>
<MenuItem Header="Option 2">
<MenuItem Header="Load new control" Click="MenuItem_Click2a"/>
<MenuItem Header="Open new window" Click="MenuItem_Click2b"/>
</MenuItem>
</Menu>
<Border x:Name="Stage" Grid.Row="1"/>
<Grid x:Name="LoginLayer" Background="#FFFFFFFF" Grid.RowSpan="2">
<Grid HorizontalAlignment="Center" VerticalAlignment="Center" Background="LightBlue">
<Grid.ColumnDefinitions>
<ColumnDefinition/>
<ColumnDefinition/>
</Grid.ColumnDefinitions>
<Grid.RowDefinitions>
<RowDefinition/>
<RowDefinition/>
<RowDefinition/>
<RowDefinition/>
</Grid.RowDefinitions>
<TextBlock Text="Mxx" Grid.ColumnSpan="2" FontWeight="Bold" HorizontalAlignment="Center" Margin="5" FontSize="20"/>
<TextBlock Text="Name" Grid.Row="1" Margin="3"/>
<TextBox x:Name="txtName" Grid.Row="1" …Run Code Online (Sandbox Code Playgroud) 我从搜索中找不到任何有类似问题的人:
我正在尝试使用HttpClient从服务器获取XML,但我的UI在"task.Wait()"行奇怪地冻结.这是代码:
public void register() {
String data = "register=" + (accountName) + "&email0=" +
(email) + "&email1=" + (otherEmail);
var task = MakeRequest(data);
task.Wait(); //freezes here
var response = task.Result;
String resultstring = response.Content.ReadAsStringAsync().Result;
}
private static async Task<System.Net.Http.HttpResponseMessage> MakeRequest(String data)
{
var content = new StringContent(data, Encoding.UTF8, "application/x-www-form-urlencoded");
var httpClient = new System.Net.Http.HttpClient();
System.Net.Http.HttpResponseMessage responseMessage=null;
try
{
responseMessage = await httpClient.PostAsync(server, content);
}
catch(Exception ex)
{
responseMessage.ReasonPhrase = string.Format("RestHttpClient.SendRequest failed: {0}", ex);
}
return responseMessage;
}
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任何帮助是极大的赞赏!
我有这个样本:
代码HTML:
<div class="dropzone dz-clickable" id="myDrop">
<div class="dz-default dz-message" data-dz-message="">
<span>Upload or drag patient photo here</span>
</div>
</div>
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代码JS:
Dropzone.autoDiscover = false;
var myDropzone = new Dropzone("div#myDrop", {
addRemoveLinks: true,
url: "#",
maxFiles: 1,
init: function() {
this.on("maxfilesexceeded", function(file) {
alert("You are not allowed to chose more than 1 file!");
this.removeFile(file);
});
this.on("addedfile", function(file) {
myDropzone.options.removefile.call(myDropzone, mockFile);
// I want to delete an existing element
});
}
});
var fileName = $('#profilePicture').val();
var mockFile = {
name: fileName,
size: …Run Code Online (Sandbox Code Playgroud) 我想了解为什么当属性是原型时,knockout的行为会有所不同,尤其重要的是,如何避免它,同时仍然使用原型.
我想要覆盖一些方法,因为我有一个我们要继承的基本视图模型
以下是我的意思
JSFIDDLE WITH PROTOTYPE [尝试输入第一个输入框,它将出现在另一个输入框中]
var viewModel = function(params) {
this.params = params;
};
viewModel.prototype.text = ko.observable(this.params && this.params.initialText || '');
ko.components.register('message-editor', {
viewModel: viewModel,
template: 'Message: <input data-bind="value: text" /> '
+ '(length: <span data-bind="text: text().length"></span>)'
});
ko.applyBindings();Run Code Online (Sandbox Code Playgroud)
<!-- ko component: "message-editor" -->
<!-- /ko -->
<br />
<!-- ko component: "message-editor" -->
<!-- /ko -->
<script src="https://cdnjs.cloudflare.com/ajax/libs/knockout/3.4.2/knockout-min.js"></script>Run Code Online (Sandbox Code Playgroud)
没有PROTOTYPE的JSFIDDLE [尝试输入第一个输入框,它不会出现在另一个输入框中]
var viewModel = function(params) {
this.params = params;
this.text = ko.observable(this.params && this.params.initialText || '');
};
ko.components.register('message-editor', …Run Code Online (Sandbox Code Playgroud)