在Basic Operators一节中,Swift编程语言指南指出++是一个有效的运算符:
"更复杂的例子包括逻辑AND运算符&&(如在输入DoorCode &&传递瑞典扫描中)和增量运算符++ i,它是将i的值增加1的快捷方式."摘录自:Apple Inc."Swift编程语言."iBooks. https://itun.es/gb/jEUH0.l
但是,在游乐场尝试时:
class Levels {
var data = [
[
"nodesNum" : 20,
"lastLevel" : false
],
[
"nodesNum" : 16,
"lastLevel" : false
],
[
"nodesNum" : 13,
"lastLevel" : false
],
[
"nodesNum" : 10,
"lastLevel" : false
],
[
"nodesNum" : 8,
"lastLevel" : true
]
]
}
var levels: Levels!
var availableNodesNum: Int!
var currentLevelData: NSDictionary!
var levelNum:Int = 2
levels = Levels()
currentLevelData = levels.data[levelNum]
availableNodesNum = Int(currentLevelData["nodesNum"]! as! …Run Code Online (Sandbox Code Playgroud) 当大于 时,我尝试font-size使用 JavaScript更改 my ,但更改对我不起作用。scroll-y20font-size
谁能告诉我我做错了什么?我不明白我做错了什么......
<!doctype html>
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<head>
<meta name="viewport" content="width=device-width, initial-scale=1.0, maximum-scale=1.0, user-scalable=no">
<meta charset="UTF-8" />
<title>Reken op je toekomst!</title>
<style>
body {
width:100%;
margin:0px;
background-color:white;
font-family:'normal';
font-size:24px;
text-align:center;
}
/* LETTERTYPE LETTERTYPE LETTERTYPE LETTERTYPE LETTERTYPE LETTERTYPE LETTERTYPE LETTERTYPE LETTERTYPE */
@font-face {
font-family: 'special';
src: url(Fonts/FFF_Tusj.ttf);
}
@font-face {
font-family: …Run Code Online (Sandbox Code Playgroud)