from tkinter import filedialog, Label, Button, Entry, StringVar
from tkinter.filedialog import askopenfile
import pandas as pd
root = tk.Tk()
Label(root, text='File Path').grid(row=0, column=0)
v = StringVar()
entry = Entry(root, textvariable=v).grid(row=0, column=1)
Button(root, text='Browse Data Set',command=lambda: v.set(askopenfile())).grid(row=1, column=0)
Button(root, text='Close',command=root.quit()).grid(row=1, column=1)
root.file = v.get()
df = pd.read_csv(root.file)
root.mainloop()
我想通过单击按钮打开数据集（CSV 文件）并使用 pd.read_csv()函数读取它，但我收到一些错误
Traceback (most recent call last):
File "/home/abishek/PycharmProjects/untitled1/temp.py", line 21, in <module>
df = pd.read_csv(root.file)
File "/usr/lib/python3/dist-packages/pandas/io/parsers.py", line 498, in parser_f
return _read(filepath_or_buffer, kwds)
File "/usr/lib/python3/dist-packages/pandas/io/parsers.py", line 275, in _read …