我收到此错误:
ImportError: Could not find the GEOS library (tried ""geos_c"", ""libgeos_c-1"").
Try setting GEOS_LIBRARY_PATH in your settings
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当我跑步时:
from django.contrib.gis.geos import *
pnt=GEOSGeometry('POINT(23 5)')
print(pnt)
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我加入GEOS_LIBRARY_PATH = 'C:/Python34/Lib/site-packages/osgeo/geos_c.dll'
了C:\Python34\Lib\site-packages\django\conf\project_template\project_name\settings.py
但我仍然遇到相同的错误。如何解决呢?
我想上传csv文件并存储在数据库中.当我单击提交按钮时,我收到以下错误
Environment:
Request Method: POST
Request URL: http://localhost:8000/csv
Django Version: 1.9
Python Version: 3.4.3
Installed Applications:
['django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
'django.contrib.gis',
'django.contrib.admindocs',
'world',
'pft',
'wms',
'djgeojson',
'html5',
'geoexplorer']
Installed Middleware:
['django.middleware.security.SecurityMiddleware',
'django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.common.CommonMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.auth.middleware.SessionAuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
'django.middleware.clickjacking.XFrameOptionsMiddleware']
Traceback:
File "C:\Python34\lib\site-packages\django\core\handlers\base.py" in get_response
149. response = self.process_exception_by_middleware(e, request)
File "C:\Python34\lib\site-packages\django\core\handlers\base.py" in get_response
147. response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "C:\Python34\lib\site-packages\django\contrib\auth\decorators.py" in _wrapped_view
23. return view_func(request, *args, **kwargs)
File "C:\Python34\Lib\site-packages\django\bin\geodjango\pft\views.py" in add_multiple_accounts
95. csv_result, rows_error = utils.handle_uploaded_file(file, utils.account_valid_fields, utils.create_account_in_db)
File …Run Code Online (Sandbox Code Playgroud) 我有以下代码用于显示具有属性和数据表中的值的对象数组.但是这里的列标题是硬编码的,如下面的html代码所示.如何根据输入数据集使其动态化?
var dataSet = [{
"Latitude": 18.00,
"Longitude": 23.00,
"Name": "Pune"
}, {
"Latitude": 14.00,
"Longitude": 24.00,
"Name": "Mumbai"
}, {
"Latitude": 34.004654,
"Longitude": -4.005465,
"Name": "Delhi"
},{
"Latitude": 23.004564,
"Longitude": 23.007897,
"Name": "Jaipur"
}];
$(document).ready(function() {
$('#example').DataTable( {
data: dataSet,
"columns": [
{ "data": "Name" ,"title":"Custom Name"},
{ "data": "Latitude" },
{ "data": "Longitude" },
]
} );
} );
<table id="example" class="display" cellspacing="0" width="100%">
<thead>
<tr>
<th>Name</th>
<th>Latitude</th>
<th>Longitude</th>
</tr>
</thead>
</table>
Run Code Online (Sandbox Code Playgroud) 在我的 Web 应用程序中,我使用的是传单,我想使用层切换将传单层更改为卫星视图和其他地图视图。我该如何执行此操作。请帮忙!
我想在每个之后展示一个空间*.我的代码是:
def stars(n):
for x in reversed(range(n+1)):
print x * '*'
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我得到的输出是:
*****
****
***
**
*
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但我想要:
* * * * *
* * * *
* * *
* *
*
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另外,我想从右侧打印
* *
*
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是否有任何方法可以从最后一个位置打印?
django ×2
python ×2
csv ×1
datatables ×1
geos ×1
jquery ×1
leaflet ×1
python-2.7 ×1
python-3.x ×1