小编use*_*023的帖子

我有一种情况,我想在两个视图之间返回连接.那是很多专栏.在sql server中很容易.但是在PostgreSQL中我加入时.我收到错误"需要列定义列表".

有什么方法可以绕过这个,我不想提供返回列的定义.

CREATE OR REPLACE FUNCTION functionA(username character varying DEFAULT ''::character varying, databaseobject character varying DEFAULT ''::character varying)
  RETURNS SETOF ???? AS
$BODY$
Declare 
SqlString varchar(4000) = '';
BEGIN
IF(UserName = '*') THEN
   Begin
   SqlString  := 'select * from view1 left join ' + databaseobject  + ' as view2 on view1.id = view2.id';
   End;
ELSE
    Begin
    SqlString := 'select * from view3 left join ' + databaseobject  + ' as view2 on view3.id = view2.id';
    End;
END IF; 
execute …