小编C4C*_*Exe的帖子

我在本地计算机上生成证书时遇到以下错误.

C:\Users\abc>keytool -genkey -alias tomcat -keyalg RSA
Enter keystore password:
keytool error: java.io.IOException: Keystore was tampered with, or password was incorrect

我认为在jdk版本中存在一些问题.我在我的同事机器上运行了相同的命令,它运行正常.

请分享您的意见.

我想从事多线程,但我目前的项目没有这样的机会.有人请指导我应该从哪里开始.我需要实时场景,以便我可以直接跳转到编码.我也是并排阅读.

你可以参考一些网站进行练习吗？

我有一个已安装的窗口服务.我在Intelli J.中打开了应用程序的源代码.

我将配置IntelliJ如下所示

我检查了它正在使用的服务和端口的PID.

在Intelli J中运行远程配置时会出现以下错误

4:09:18 PM Error running Remote: Unable to open debugger port : java.net.ConnectException "Connection refused: connect"

有人可以说明如何在IntelliJ中调试窗口服务.这是一份工作计划申请.

installService.cmd如下

set HOME_DIR=%~dp0
set SERVICE="Service_Name"
SET JAVA_OPTIONS=-Xms256m -Xmx256m
@echo Service name is Service_Name
"pathname\Service_Name.exe" -install %SERVICE% %JVM% %JAVA_OPTIONS% -Djava.class.path="pathname\Service_Name.jar" -Dorg.quartz.properties="pathname/Service_NameScheduler.properties" -start com.org.st.Service_Name -stop com.org.st.Service_Name -out "D:/core_log\Service_Name_service_out.log" -err "D:/core_log\Service_Name_service_error.log" -current "pathname\apps"
set JVM="C:/Program Files/Java/jdk1.6.0_29/jre/bin/server/jvm.dll"

我遇到了java.util.zip的奇怪行为.*

我有一个zip文件,在解压缩后会发生这种情况

ZipFile zipfile = new ZipFile(file, ZipFile.OPEN_READ);

这是exaxt错误消息

java.util.zip.ZipException: error in opening zip file
at java.util.zip.ZipFile.open(Native Method)
at java.util.zip.ZipFile.<init>(ZipFile.java:127)
at java.util.zip.ZipFile.<init>(ZipFile.java:143)
at com.basware.ExtractZip.unpack(ExtractZip.java:27)
at com.basware.ExtractZip.main(ExtractZip.java:17)

但是,如果我使用以下代码,它可以打开存档而不会出现任何错误

try {
     BufferedOutputStream dest = null;       
     File file = new File("File_Path");        
     FileInputStream fis = new FileInputStream(file);
     ZipInputStream zis = new ZipInputStream(new BufferedInputStream(fis));
     ZipEntry entry;
     while((entry = zis.getNextEntry()) != null) {
        System.out.println("Extracting: " +entry);
        int count;
        byte data[] = new byte[BUFFER];
        // write the files to the disk
        FileOutputStream fos = …

我正在解压缩 Zip 档案。因为有两种类型的档案 - Zip 和 GZip。

我正在使用以下

ZipFile zipFile = new ZipFile(file, ZipFile.OPEN_READ);

但是对于 GZip 类型的档案，它给出了以下错误

java.util.zip.ZipException: error in opening zip file
at java.util.zip.ZipFile.open(Native Method)

此代码适用于 Zip 压缩类型的档案，不适用于 GZip

有没有办法使用上面的代码，因为我在各种功能中都有使用 ZipFile 的现有功能。如果我将 ZipFile 接口更改为 ZipInputStream 或 GZipInputStream，那么我需要更改多项内容。

编辑：如果传入的档案是 Zip 和 GZip 类型，我是否需要根据@Joachim Sauer 的评论进行不同的实现

在Visual Studio for Web Api 2项目的ASP.NET身份验证生成的模板项目中,我添加了一个类ApplicationUserStore(这就是我的自定义用户)

public class ApplicationUserStore : IUserStore<ApplicationUser>
{
    private readonly ApplicationDbContext _context;

    public ApplicationUserStore(ApplicationDbContext context)
    {
        _context = context;
    }

    public async Task<ApplicationUser> FindByIdAsync(string userName)
    {
        return await _context.Users.Include(x => x.FMBP_Company).FirstOrDefaultAsync(n => n.UserName == userName);
    }

    public Task CreateAsync(ApplicationUser user)
    {
        throw new NotImplementedException();
    }

    public Task DeleteAsync(ApplicationUser user)
    {
        throw new NotImplementedException();
    }

    public Task<ApplicationUser> FindByNameAsync(string userName)
    {
        return _context.Users.Include(x => x.FMBP_Company).FirstOrDefaultAsync(n => n.UserName == userName);
    }

    public Task UpdateAsync(ApplicationUser user)
    {
        throw new NotImplementedException(); …

如果我在.xhtml文件中进行更改,则更改不会反映在浏览器的屏幕上.为了使它工作,我必须每次都重新启动服务器.这对我来说似乎很笨拙.

我在我的添加了以下上下文参数web.xml:

<context-param>
    <param-name>javax.faces.PROJECT_STAGE</param-name>
    <param-value>Development</param-value>
</context-param>
<context-param>
    <param-name>javax.faces.FACELETS_REFRESH_PERIOD</param-name>
    <param-value>1</param-value>
</context-param>

但是,它们没有任何效果.

我的技术堆栈如下:

• SWF 2.3.0
• Primefaces 2.2.1
• JSF 2
• Spring Security 3
• 春季3.1.0M1I
• 的Ehcache
• Apache Tomcat 6.0
• STS 2.5.1.

我正在集成SWF 2.2.1,Primefaces 2.2.1,JSF 2,Spring Security 3,Spring 3.1.0M1.我能够点击Spring web-flow xml中提到的第一页,但是出现了以下错误.

com.sun.faces.application.view.FaceletViewHandlingStrategy handleRenderException
SEVERE: Error Rendering View[/WEB-INF/flows/AccSrch/searchAccIns.xhtml]
java.lang.UnsupportedOperationException
at javax.faces.context.FacesContext.isReleased(FacesContext.java:609)
at com.sun.faces.context.PartialViewContextImpl.updateFacesContext(PartialViewContextImpl.java:468)
at com.sun.faces.context.PartialViewContextImpl.isAjaxRequest(PartialViewContextImpl.java:108)
at javax.faces.context.PartialViewContextWrapper.isAjaxRequest(PartialViewContextWrapper.java:117)
at javax.faces.component.UIViewRoot.getRendersChildren(UIViewRoot.java:1020)
at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1755)
at com.sun.faces.application.view.FaceletViewHandlingStrategy.renderView(FaceletViewHandlingStrategy.java:401)
at com.sun.faces.application.view.MultiViewHandler.renderView(MultiViewHandler.java:131)
at org.springframework.faces.webflow.FlowViewHandler.renderView(FlowViewHandler.java:99)
at com.sun.faces.lifecycle.RenderResponsePhase.execute(RenderResponsePhase.java:121)
at com.sun.faces.lifecycle.Phase.doPhase(Phase.java:101)
at com.sun.faces.lifecycle.LifecycleImpl.render(LifecycleImpl.java:139)
at org.springframework.faces.webflow.FlowLifecycle.render(FlowLifecycle.java:80)
at org.springframework.faces.webflow.JsfView.render(JsfView.java:90)

令我惊讶的是,我的.xhtml中只有最少的代码

<ui:composition xmlns="http://www.w3.org/1999/xhtml"
   xmlns:ui="http://java.sun.com/jsf/facelets"
   xmlns:h="http://java.sun.com/jsf/html"
   xmlns:f="http://java.sun.com/jsf/core"
   xmlns:p="http://primefaces.prime.com.tr/ui">
   <ui:define name="content">
      <f:view>
         <h:form id="expire" prependId="false">
            <h:outputText value="HEllo" />
         </h:form>
      </f:view>
   </ui:define>
</ui:composition>

请参阅此帖子以获取上下文 链接

我无法渲染primefaces 的面包屑控件.我正在使用ui:repeat动态构建面包屑.我把它包装在p:breadCrumb标签内的那一刻,我无法在页面上看到控件

以下代码我在我的.xhtml中使用

        <p:breadCrumb>
        <ui:repeat value="#{conversationScope.trail}" var="bcrumb">
            <h:outputLink value="#{bcrumb.url}">
                <h:outputText value="#{bcrumb.label}" />
                <h:outputText value=">" />
            </h:outputLink>
            <p:menuitem value="#{bcrumb.label}" url="#{bcrumb.url}" />
        </ui:repeat>
    </p:breadCrumb>

请建议有没有其他选择？

我集成了SWF 2.2.1,Primefaces 2.2.1,JSF 2,Spring Security 3,Spring 3.1.0M1I和EhCache以及AspectJ和Castor.

我在app-config.xml中为castor定义了bean

<bean id="oXMapper" class="com.abc.xyz.util.OXMapper">
    <property name="unmarshaller" ref="unmarshaller" />
    <property name="marshaller" ref="marshaller" />
    <property name="acordRequest" ref="acordRequest" />
    <property name="acordResponse" ref="acordResponse" />
</bean>

<bean id="unmarshaller" class="org.springframework.oxm.castor.CastorMarshaller">
    <property name="mappingLocation"
        value="classpath:/templates/mapping/ACORD_Response_Mapping.xml" />
</bean>

<bean id="marshaller" class="org.springframework.oxm.castor.CastorMarshaller">
    <property name="mappingLocation"
        value="classpath:/templates/mapping/ACORD_Request_Mapping.xml" />
</bean>

<bean id="acordRequest" class="com.abc.xyz.cate.domain.ACORD">
    <property name="insuranceSvcRq" ref="insuranceSvcRq" />
    <property name="signonRq" ref="CltSearch_signonRq" />
</bean>

我有一个搜索页面,我在这里建立参数,如

<h:panelGrid>
    <h:selectOneRadio id="#{msg.srchType}" value="#{acordRequest.insuranceSvcRq.com_csc_ClientSearchRq.com_csc_SearchInfo.com_csc_SearchCriteria.com_csc_ClientSearch.com_csc_SearchNameByType}">
        <f:selectItem itemLabel="#{msg.exact}" itemValue="E" id="#{msg.exact}" />
    <f:selectItem itemLabel="#{msg.phonetic}" itemValue="S" id="#{msg.phonetic}" />
    <f:selectItem itemLabel="#{msg.truncated}" itemValue="P" id="#{msg.truncated}" />
        </h:selectOneRadio>
</h:panelGrid>

使用Spring Webflow,我调用OXMapper函数并将ACORD(用于构建xml的分层结构)对象传递给它.此OXMapper类分别负责对象和xml的编组和解组. …

我有两个xmls.There字段可以包含像54.2,54.23,54.234,54.234567这样的值.

有人请告诉我如何确保输出xml中至少会出现两位小数.当前54.2转换为54,2,但我希望它是54,20

我在集成SWF,Primefaces 2.2.1,JSF 2,Spring Security 3,Spring 3.1.0时遇到了奇怪的错误

INFO: Unsanitized stacktrace from failed start...
com.sun.faces.config.ConfigurationException: 
  Source Document: jar:file:/E:/30May2011/.metadata/.plugins/org.eclipse.wst.server.core/tmp0/wtpwebapps/simpleWeb/WEB-INF/lib/primefaces-2.2.1.jar!/META-INF/faces-config.xml
  Cause: Class 'org.primefaces.component.autocomplete.AutoCompleteRenderer' is missing a runtime dependency: java.lang.NoClassDefFoundError: javax/faces/component/behavior/ClientBehaviorHolder
    at com.sun.faces.config.processor.AbstractConfigProcessor.createInstance(AbstractConfigProcessor.java:253)
    at com.sun.faces.config.processor.RenderKitConfigProcessor.addRenderers(RenderKitConfigProcessor.java:251)
    at com.sun.faces.config.processor.RenderKitConfigProcessor.process(RenderKitConfigProcessor.java:152)
    at com.sun.faces.config.processor.AbstractConfigProcessor.invokeNext(AbstractConfigProcessor.java:108)
    at com.sun.faces.config.processor.ManagedBeanConfigProcessor.process(ManagedBeanConfigProcessor.java:265)
    at com.sun.faces.config.processor.AbstractConfigProcessor.invokeNext(AbstractConfigProcessor.java:108)
    at com.sun.faces.config.processor.ValidatorConfigProcessor.process(ValidatorConfigProcessor.java:107)
    at com.sun.faces.config.processor.AbstractConfigProcessor.invokeNext(AbstractConfigProcessor.java:108)
    at com.sun.faces.config.processor.ConverterConfigProcessor.process(ConverterConfigProcessor.java:117)
    at com.sun.faces.config.processor.AbstractConfigProcessor.invokeNext(AbstractConfigProcessor.java:108)
    at com.sun.faces.config.processor.ComponentConfigProcessor.process(ComponentConfigProcessor.java:108)
    at com.sun.faces.config.processor.AbstractConfigProcessor.invokeNext(AbstractConfigProcessor.java:108)
    at com.sun.faces.config.processor.ApplicationConfigProcessor.process(ApplicationConfigProcessor.java:312)
    at com.sun.faces.config.processor.AbstractConfigProcessor.invokeNext(AbstractConfigProcessor.java:108)
    at com.sun.faces.config.processor.LifecycleConfigProcessor.process(LifecycleConfigProcessor.java:114)
    at com.sun.faces.config.processor.AbstractConfigProcessor.invokeNext(AbstractConfigProcessor.java:108)
    at com.sun.faces.config.processor.FactoryConfigProcessor.process(FactoryConfigProcessor.java:183)
    at com.sun.faces.config.ConfigManager.initialize(ConfigManager.java:301)
    at com.sun.faces.config.ConfigureListener.contextInitialized(ConfigureListener.java:205)
    at org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:3972)
    at org.apache.catalina.core.StandardContext.start(StandardContext.java:4467)
    at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045)
    at org.apache.catalina.core.StandardHost.start(StandardHost.java:722)
    at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045)
    at org.apache.catalina.core.StandardEngine.start(StandardEngine.java:443)
    at org.apache.catalina.core.StandardService.start(StandardService.java:516)
    at org.apache.catalina.core.StandardServer.start(StandardServer.java:710) …