我有以下代码片段:
@interface Foo: UIViewController {
...
UIButton *myButton;
...
}
@implementation Foo
- (void) viewDidLoad {
...
myButton.highlighted = YES;
...
}
当我运行应用程序时,该按钮以蓝色突出显示(默认行为).它按我的预期工作.
但按下按钮一次后,该按钮不再突出显示.
然后,我创建了一个IBAction highlightButton处理Touch Up Inside我明确调用的事件myButton.highlighted = Yes;.不幸的是,按钮突出显示仍然不会停留.
如果按下后如何将其突出显示为蓝色？
我有一个选择元素有几个项目.我想改变它的第一个项目的颜色.但似乎只有在您单击选择下拉列表时才会显示颜色.我想要的是在加载页面时更改颜色(如颜色灰色),以便用户可以看到第一个选项颜色已更改.
看这里的例子...... http://jsbin.com/acucan/4/
谢谢你的回答!这是我第一次在这里发帖提问.抱歉我的英文.我希望我明白这个问题.
谢谢
我正在为iOS制作一个GTalk客户端,需要一个XMPP库来完成繁重的工作.谁知道这样的？
我正在使用设计
sign_in和sign_up网址正在工作
但是,当我尝试网址时: http://localhost:3000/users/sign_out
它会产生路由错误
No route matches [GET] "/users/sign_out"
我怎样才能解决这个问题？
rake routes
new_user_session GET /users/sign_in(.:format) {:action=>"new", :controller=>"devise/sessions"}
user_session POST /users/sign_in(.:format) {:action=>"create", :controller=>"devise/sessions"}
destroy_user_session DELETE /users/sign_out(.:format) {:action=>"destroy", :controller=>"devise/sessions"}
user_password POST /users/password(.:format) {:action=>"create", :controller=>"devise/passwords"}
new_user_password GET /users/password/new(.:format) {:action=>"new", :controller=>"devise/passwords"}
edit_user_password GET /users/password/edit(.:format) {:action=>"edit", :controller=>"devise/passwords"}
PUT /users/password(.:format) {:action=>"update", :controller=>"devise/passwords"}
cancel_user_registration GET /users/cancel(.:format) {:action=>"cancel", :controller=>"devise/registrations"}
user_registration POST /users(.:format) {:action=>"create", :controller=>"devise/registrations"}
new_user_registration GET /users/sign_up(.:format) {:action=>"new", :controller=>"devise/registrations"}
edit_user_registration GET /users/edit(.:format) {:action=>"edit", :controller=>"devise/registrations"}
PUT /users(.:format) {:action=>"update", :controller=>"devise/registrations"}
DELETE /users(.:format) {:action=>"destroy", :controller=>"devise/registrations"}
status_message_index …我正在尝试为新的 Rails 项目设置一个带有 Github 操作的持续集成工作流程。这是错误：
2022-05-21T17:07:01.1242737Z Your bundle only supports platforms ["x86_64-darwin-19", "x86_64-darwin-21"] but
2022-05-21T17:07:01.1243516Z your local platform is x86_64-linux. Add the current platform to the lockfile
2022-05-21T17:07:01.1244782Z with `bundle lock --add-platform x86_64-linux` and try again.
2022-05-21T17:07:01.1294935Z Took 1.38 seconds
2022-05-21T17:07:01.1295823Z ##[endgroup]
2022-05-21T17:07:01.1347744Z ##[error]Error: The process '/opt/hostedtoolcache/Ruby/3.1.2/x64/bin/bundle' failed with exit code 16
at ExecState._setResult (/home/runner/work/_actions/ruby/setup-ruby/v1/dist/index.js:4918:25)
at ExecState.CheckComplete (/home/runner/work/_actions/ruby/setup-ruby/v1/dist/index.js:4901:18)
at ChildProcess.<anonymous> (/home/runner/work/_actions/ruby/setup-ruby/v1/dist/index.js:4795:27)
at ChildProcess.emit (node:events:390:28)
at maybeClose (node:internal/child_process:1064:16)
at Process.ChildProcess._handle.onexit (node:internal/child_process:301:5)
以及配置文件：
name: My workflow
on: [push, pull_request]
jobs:
test:
runs-on: …在编译资产时打开资源放大后,我的Rails应用程序无效.我转换Angular控制器使用括号表示法,并得到以下错误,有没有办法调试这个？
编译application.js https://gist.github.com/jianbo/6665161
JS错误
Error: Unknown provider: tProvider <- t
at Error (<anonymous>)
at me:3001/assets/application-4f6cd4e170fc6ce5d181d869af318557.js:817:21665
at Object.i [as get] (me:3001/assets/application-4f6cd4e170fc6ce5d181d869af318557.js:817:20671)
at me:3001/assets/application-4f6cd4e170fc6ce5d181d869af318557.js:817:21753
at i (localme:3001/assets/application-4f6cd4e170fc6ce5d181d869af318557.js:817:20671)
at n (me:3001/assets/application-4f6cd4e170fc6ce5d181d869af318557.js:817:20805)
at Object.r [as instantiate] (me:3001/assets/application-4f6cd4e170fc6ce5d181d869af318557.js:817:21447)
at me:3001/assets/application-4f6cd4e170fc6ce5d181d869af318557.js:818:604
at me:3001/assets/application-4f6cd4e170fc6ce5d181d869af318557.js:817:28889
at r (me:3001/assets/application-4f6cd4e170fc6ce5d181d869af318557.js:817:8277) application-4f6cd4e170fc6ce5d181d869af318557.js:818
(anonymous function) application-4f6cd4e170fc6ce5d181d869af318557.js:818
(anonymous function) application-4f6cd4e170fc6ce5d181d869af318557.js:818
r.$broadcast application-4f6cd4e170fc6ce5d181d869af318557.js:818
(anonymous function) application-4f6cd4e170fc6ce5d181d869af318557.js:818
l application-4f6cd4e170fc6ce5d181d869af318557.js:818
l application-4f6cd4e170fc6ce5d181d869af318557.js:818
(anonymous function) application-4f6cd4e170fc6ce5d181d869af318557.js:818
r.$eval application-4f6cd4e170fc6ce5d181d869af318557.js:818
r.$digest application-4f6cd4e170fc6ce5d181d869af318557.js:818
r.$apply application-4f6cd4e170fc6ce5d181d869af318557.js:818
r application-4f6cd4e170fc6ce5d181d869af318557.js:818
m application-4f6cd4e170fc6ce5d181d869af318557.js:818
v.onreadystatechange application-4f6cd4e170fc6ce5d181d869af318557.js:818
只是想知道是否有人能够在Ruby on Rails中对getter setter的基础知识进行一些了解,并提供强类型视图.我对rails上的ruby非常新,并且主要对.NET非常了解.
例如,我们假设我们有一个名为Person的.net类
class Person
{
public string Firstname{get;set;}
public string Lastname{get;set;}
public Address HomeAddress{get;set;}
}
class Address
{
public string AddressLine1{get;set;}
public string City{get;set;}
public string Country{get;set;}
}
在Ruby中,我会写这个
class Person
attr_accessor :FirstName
attr_accessor :LastName
attr_accessor :HomeAddress
end
class Address
attr_accessor :AddressLine1
attr_accessor :City
attr_accessor :Country
end
查看Person类的Ruby版本如何指定访问器方法FirstName,LastName和HomeAddress的类型？如果我要使用这个类,我可以将任何类型提供给HomeAddress,但我希望这个访问器方法只接受TYPE地址.
有什么建议 ？
谢谢
我想将两个数组"压缩"成哈希.
从:
['BO','BR']
['BOLIVIA','BRAZIL']
至:
{BO: 'BOLIVIA', BR:'BRAZIL'}
我该怎么做？
我已经创建了我的应用程序的临时版本,并希望其他人安装它.我在配置文件中有他们的设备ID(实际上是两个).我的证书与临时和应用商店配置相同.证书在钥匙串中有效.我在Xcode中为此构建选择了ad hoc配置文件,该配置链接到分发证书.
我向用户发送配置文件和.app文件.他们将两者都放入iTunes并同步,然后在两台设备上都出现此错误:
The application "myapp" was not installed on the iPhone "user's iPhone" because the signer is not valid.
我从我的iPhone中删除了所有配置文件,将上述两个文件放入iTunes,同步并成功安装了应用程序.我不能让它为我重复.我需要在本地重新解决这个问题以找出问题所在.有什么想法可以做到吗？
在Eclipse我收到警告Resource leak: 'ps' is not closed at this location,我不明白.
在我的Java代码中,我将"ps"声明为Prepared Statement,并且我多次使用(并关闭)它.然后我有以下顺序:
try {
if(condition) {
ps = c.prepareStatement("UPDATE 1 ...");
} else {
ps = c.prepareStatement("UPDATE 2 ...");
}
ps.executeUpdate();
} catch (SQLException e) {
// exception handling
} finally {
if (null != ps)
try {
ps.close();
} catch (SQLException e) {
// exception handling
};
}
"资源泄漏" - 警告来自其他部分的"更新" - 声明.如果我ps = null在启动try块之前设置,则没有警告.
如果第二个UPDATE-Statement被注释掉,则不会显示警告.
这是理解还是java/eclipse的问题？