小编El *_*uso的帖子

我想根据这个答案更改sudo会话超时.我可以编辑普通文件:

lineinfile:
  path: /etc/sudoers
  regexp: ^Defaults  env_reset
  line: Defaults  env_reset,timestamp_timeout=60

但在我/etc/sudoers写的第一行:# This file MUST be edited with the 'visudo' command as root.如何处理它？
PS
虽然简短的答案是肯定的,但必须阅读康斯坦丁·苏沃罗夫关于正确方法的回答,lineinfile以及非常有趣的技术回答关于这种方式可能存在的陷阱

如何找出事件循环中有多少活动任务？在文档中我只找到asyncio.Task.all_tasks()但它是简单的增量计数器:

import asyncio


async def coro():
    await asyncio.sleep(1)


async def main():
    tasks = []
    print('Tasks count: ', len(asyncio.Task.all_tasks()))
    for idx in range(3):
        task = asyncio.ensure_future(coro())
        tasks.append(task)
        print('Tasks count: ', len(asyncio.Task.all_tasks()))
    await asyncio.gather(*tasks)
    print('Tasks count: ', len(asyncio.Task.all_tasks()))


loop = asyncio.get_event_loop()
loop.run_until_complete(main())

输出:

Tasks count:  1
Tasks count:  2
Tasks count:  3
Tasks count:  4
Tasks count:  4

预期产量:

Tasks count:  1
Tasks count:  2
Tasks count:  3
Tasks count:  4
Tasks count:  1

docker-composeservice_1 |在每一行输出的开头插入前缀。我使用这个容器进行测试，这种改进（在其他情况下非常有用）弄乱了我的调试日志，我想为此服务删除它。文档没有关于这个问题的信息。有任何想法吗？
我的docker-compose.yml：

version: '3'
services:
  rds:
    image: postgres:9.4
    ports:
      - ${POSTGRES_PORT}:5432
    environment:
      POSTGRES_USER: ${POSTGRES_USER}
      POSTGRES_PASSWORD: ${POSTGRES_PASSWORD}
  dynamo:
    image: iarruss/dynamo-local-admin:latest
    ports:
      - ${DYNAMODB_PORT}:8000
  python:
    container_name: python
    image: iarruss/docker-python2:latest
    depends_on:
      - rds
      - dynamo
    environment:
      POSTGRES_HOST: rds
      POSTGRES_USER: ${POSTGRES_USER}
      POSTGRES_PASSWORD: ${POSTGRES_PASSWORD}
      DYNAMODB_HOST: dynamo

编辑：澄清预期结果

电流输出：

python             |
python             | collected 511 items
python             |
python             | tests/test_access.py
python             |

预期输出：

collected 511 items

test_access.py                                                     

from PIL import Image


image = Image.open("image.jpg")

file_path = io.BytesIO();

image.save(file_path,'JPEG');


image2 = Image.open(file_path.getvalue());

我在运行程序TypeError: embedded NUL character的最后一条语句中收到此错误Image.open

从流中打开文件的正确方法是什么？

我正在以这种方式使用多处理:

import multiprocessing as mp

def worker(thread_id, tasks, results):
    tmp_dir = 'temp_for_{}'.format(thread_id)
    os.makedirs(tmp_dir)
    try:
        while not tasks.empty():
            data = tasks.get()
            response = process_pdf(data, tmp_dir)
            results.put(response)
    except (KeyboardInterrupt, SystemExit):
        log.info('Interrupt signal received in thread %s.', thread_id)
    except Queue.Empty:
        pass
    except Exception:
        log.error("Unexpected error in %s", thread_id, exc_info=True)
    finally:
        shutil.rmtree(tmp_dir)
        log.info("Thread %s exit", thread_id)

if __name__ == "__main__":
    tasks, results = mp.Queue(), mp.Queue()
    for record in cursor.select(query):
        tasks.put(record)
    manager = mp.Manager()
    workers = [mp.Process(target=worker, args=(i, tasks, results)) for i in xrange(8)]
    for …

如何scrapy shell在 PyCharm IPython 控制台中运行仿真？我想保留通过 Alt+Shift+E 从编辑器运行代码片段的能力

我们有一种方法来设置线程名称：thread = threading.Thread(name='Very important thread', target=foo)然后%(thread)s:在格式化程序中获取该名称以用于记录目的。可以用这样的方法做asyncio.Task吗？