我正在玩UI事件处理,我发现了一些我无法从Android Dev中找到解释的东西:我有一个ImageView和一个TextView,每当我触摸ImageView时,TextView都会显示一条消息.但以下代码不起作用:
public class ShowSomething extends Activity {
private LinearLayout ll;
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
LinearLayout ll = (LinearLayout)findViewById(R.id.linearLayout);
final TextView textview = (TextView)findViewById(R.id.textview);
MyImageView image = new MyImageView(this, textview);
image.setImageResource(R.drawable.icon);
ll.addView(image, 48, 48);
}
}
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和MyImageView.java
public class MyImageView extends ImageView implements OnTouchListener{
private TextView textview;
public MyImageView(Context context,TextView textview) {
super(context);
this.textview = textview;
}
@Override
public boolean onTouch(View v, MotionEvent event) {
textview.setText("Event captured !");
return true;
}
}
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main.xml中
<?xml version="1.0" …Run Code Online (Sandbox Code Playgroud) 我正在开发的启动,我现在用的应用小部件的工作,我跟着从这里教程: AppWigetHost tutrial -莱昂纳多菲舍尔 一切顺利,直到我试图在AppWidgetHostView加入onLongCick监听器
private void createAppWidget(Intent data) {
Bundle extras = data.getExtras();
final int appWidgetId = extras.getInt(AppWidgetManager.EXTRA_APPWIDGET_ID);
AppWidgetProviderInfo appWidgetInfo = mAppWidgetManager.getAppWidgetInfo(appWidgetId);
AppWidgetHostView hostView = mAppWidgetHost.createView(getApplicationContext(), appWidgetId, appWidgetInfo);
hostView.setAppWidget(appWidgetId, appWidgetInfo);
LinearLayout.LayoutParams params = createLayoutParams(appWidgetInfo);
rootLayout.addView(hostView, params);
hostView.setOnLongClickListener(new OnLongClickListener() {
@Override
public boolean onLongClick(View v) {
Toast.makeText(getApplicationContext(), "Long click " + appWidgetId, Toast.LENGTH_LONG).show();
return true;
}
});
}
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当我在主机上添加一个小部件(默认的谷歌模拟时钟) - 并试图长时间点击它,它只是不起作用!长按后,它只会打开时钟应用程序(单击的默认操作).
谁能告诉我如何解决它?这是我的完整代码:http: //pastebin.com/61TkuLvx
添加
我刚刚再次检查:
----如果我长时间点击Clock小部件的边界,则会触发longClick事件!
----我添加了我的自定义appwidget(没有onclick处理程序):所以longclick事件总是被正确触发.
所以我想,它必须与touchevent处理程序/调度程序有关.
添加 我刚刚尝试在主机视图的所有子项上设置onLongClick,如下所示:
private void createAppWidget(Intent data) {
...
...
setChildrenViewLongClick(hostView, …Run Code Online (Sandbox Code Playgroud) 我正在开发一个Android应用程序 - 它从服务器请求一些数据,服务器以JSON格式返回数据.除了API之外,一切正常.调试后,我发现了这个异常:
org.json.JSONException: Unterminated array at character 152 of
{
"total": "2",
"result": [
{
"id": "15",
"ename": "Horror movies based on true stories",
"vname": "Nh?ng phim kinh d? d?a trên chuy?n có th?t",
"movies": "16"
}{
"id": "14",
"ename": "IMDB Top 250",
"vname": "250 b? phim hay nh?t m?i th?i ??i",
"movies": "127"
}{
"id": "13",
"ename": "10 good movies for women",
"vname": "10 b? phim hay dành cho phái ??p",
"movies": "10"
}{
"id": "12",
"ename": "The …Run Code Online (Sandbox Code Playgroud) 我有以下问题,并搜索了一段时间,但没有从网上得到任何解决方案:
我有一个自定义列表视图,每个项目都有以下布局(我只发帖必备):
<LinearLayout>
<ImageView android:id="@+id/friendlist_iv_avatar" />
<TextView andorid:id="@+id/friendlist_tv_nick_name" />
<ImageView android:id="@+id/friendlist_iv_status_icon" />
</LinearLayout>
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我有一个类FriendRowItem,它从上面的布局中膨胀:
public class FriendRowItem extends LinearLayout{
private ImageView ivAvatar;
private ImageView ivStatusIcon;
private TextView tvNickName;
public FriendRowItem(Context context) {
super(context);
RelativeLayout friendRow = (RelativeLayout) Helpers.inflate(context, R.layout.friendlist_row);
this.addView(friendRow);
ivAvatar = (ImageView)findViewById(R.id.friendlist_iv_avatar);
ivStatusIcon = (ImageView)findViewById(R.id.friendlist_iv_status_icon);
tvNickName = (TextView)findViewById(R.id.friendlist_tv_nick_name);
}
public void setPropeties(Friend friend) {
//Avatar
ivAvatar.setImageResource(friend.getAvatar().getDrawableResourceId());
//Status
Status.Type status = friend.getStatusType();
if ( status == Type.ONLINE) {
ivStatusIcon.setImageResource(R.drawable.online_icon);
} else {
ivStatusIcon.setImageResource(R.drawable.offline_icon);
}
//Nickname
String name = friend.getChatID();
if …Run Code Online (Sandbox Code Playgroud)