每当Android Market Licensing ping服务器返回GRANT_ACCESS pong时,我都会缓存用户的身份验证.
有没有人看到这个策略有任何漏洞?我相信它非常强大,因为我混淆了一把钥匙,而且不混淆的唯一方法就是知道盐.现在,有人可以想象打开apk并寻找盐,但这并不是真正的破解程度,我认为太重要了,不用担心.
如您所见,设备特定信息正被添加到混淆技术中.
// Try to use more data here. ANDROID_ID is a single point of attack.
String deviceId = Secure.getString(getContentResolver(), Secure.ANDROID_ID);
obfuscator = new AESObfuscator(SALT, getPackageName(), deviceId);
mChecker = new LicenseChecker(this, new ServerManagedPolicy(this, obfuscator), BASE64_PUBLIC_KEY );
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接下来创建持久化数据:
public void allow() {
SharedPreferences settings = getSharedPreferences(PREFERENCES_EULA, 0);
SharedPreferences.Editor editor = settings.edit();
String uid = UUID.randomUUID().toString();
if(!settings.contains(ACCESS_KEY)) {
editor.putString(ACCESS_KEY,uid);
editor.commit();
}
if(!settings.contains(OBFU_ACCESS_KEY)) {
String obfu = obfuscator.obfuscate(uid);
editor.putString(OBFU_ACCESS_KEY,obfu);
editor.commit();
}
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然后,我使用另一种方法来检查缓存内容的状态:
boolean isCachedLicense() {
SharedPreferences settings = …Run Code Online (Sandbox Code Playgroud) 在进入下一个Activity之前,我有一个AsyncTask.在这个AsyncTask中,我有一个MediaPlayer.
protected void onPause() {
stopProgress();
Log.i(TAG, "onPAUSE");
try {
} finally {
// If we allocated a player, then cleanup after it
if (player != null) {
player.reset();
player.release();
player = null;
Log.d(TAG,"end of player cleanup");
}
}
super.onPause();
}
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使用场景:
这是一款名为Traffic Jam的 Android游戏
我写了一个递归求解器:
import copy,sys
sys.setrecursionlimit(10000)
def lookup_car(car_string,ingrid):
car=[]
i=0
for row in ingrid:
j=0
for cell in row:
if cell == car_string:
car.append([i,j])
j+=1
i+=1
return car
#True if up/down False if side to side
def isDirectionUp(car):
init_row=car[0][0]
for node in car:
if node[0] != init_row:
return True
return False
def space_up(car,grid):
top_node=car[0]
m_space_up = (top_node[0]-1,top_node[1])
if top_node[0] == 0:
return -1
elif grid[m_space_up[0]][m_space_up[1]] != " ":
return -1
else:
return m_space_up
def space_down(car,grid):
bottom_node = car[-1] …Run Code Online (Sandbox Code Playgroud) 我有一个具有嵌套性质的Bundle,我想保留,我怎样才能最容易地保留整个Bundle?SharedPreferences缺乏捆绑功能.
图像通常需要特殊的HTTP标头,如:
Content-disposition: attachment; filename="file2.jpeg"
Content-type: image/jpeg
Content-Transfer-Encoding: binary
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我使用以下方法构建我的POST:
List<NameValuePair> formparams = new ArrayList<NameValuePair>();
UrlEncodedFormEntity urlEncodedFormEntity = new UrlEncodedFormEntity(formparams);
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urlEncodedFormEntity允许setContentType,但我不知道如何混合图像和文本?
我已关闭每个窗口,重新启动计算机.但Eclipse告诉我:"C:\ Program Files\android-sdk\tools正在被访问....我甚至删除了目录,但我仍然得到:如何解决?
无法将目录C:\ Program Files\Android\android-sdk\platform-tools重命名为C:\ Program Files\Android\android-sdk\temp\PlatformToolPackage.old01.
为什么当只有一部手机连接到我的机器时,eclipse SOMETIMES会提示我启动我的应用程序的设备?有时候,它会持续数月......如何解决?
它说我的目标手机是2.3.4并且旁边有一个小的黄色感叹号警告.
let lessons = Lessons(definition: "testo", photo: url)
SaveUtil.saveLessons(lessons: lessons!)
let x = SaveUtil.loadLessons()
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所以一切都编译并运行,但 x 为零......我试图使这个 ios12/swift 4.2 兼容,但不知道缺少什么。谢谢!
class SaveUtil {
static func saveLessons(lessons: Lessons) {
let data = try! NSKeyedArchiver.archivedData(withRootObject: lessons, requiringSecureCoding: false)
UserDefaults.standard.set(data, forKey: "lessons")
}
static func loadLessons() -> [Lessons]? {
let data = UserDefaults.standard.data(forKey: "lessons")
return try! NSKeyedUnarchiver.unarchiveTopLevelObjectWithData(data!) as? [Lessons]
}
}
Run Code Online (Sandbox Code Playgroud) 我的 appcheck 在我真实的 ios 设备上的相同代码库上运行良好,
但在模拟器上,我看到:
await kFirebaseFuncs.httpsCallable('doIt')
和
PlatformException (PlatformException(failed-precondition, The function must be called
from an App Check verified app., {message: The function must be called from an App
Check verified app., code: failed-precondition}, null))
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我需要做些什么才能使 appcheck 在 ios 模拟器上工作吗?
我有很多类的活动层次结构.我刚刚安装了v4兼容包.以一种方式获取我所有活动的最简单方法是什么?我可以在一个带有TabHost的Fragment中使用它们?
代码行:
mTabsAdapter.addTab(mTabHost.newTabSpec("feed").setIndicator("Feed"), FActivity.class, null);
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第165行:
@Override
public Fragment getItem(int position) {
TabInfo info = mTabs.get(position);
return Fragment.instantiate(mContext, info.clss.getName(), info.args);
}
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具体来说,我想避免像以下错误:
07-19 01:33:24.940: ERROR/AndroidRuntime(17581): java.lang.ClassCastException: com.c.FActivity
07-19 01:33:24.940: ERROR/AndroidRuntime(17581): at android.support.v4.app.Fragment.instantiate(Fragment.java:378)
07-19 01:33:24.940: ERROR/AndroidRuntime(17581): at com.c.Main$TabsAdapter.getItem(Main.java:165)
07-19 01:33:24.940: ERROR/AndroidRuntime(17581): at android.support.v4.app.FragmentPagerAdapter.instantiateItem(FragmentPagerAdapter.java:62)
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