小编Mak*_*kko的帖子

Android布局标题栏不可见

我创建了xml布局文件.当我把它作为内容提供给我的活动时,标题栏是不可见的.我怎样才能让它可见 我试着用setTitle("Title");

protected void onCreate(Bundle savedInstanceState) { 
getWindow().addFlags(WindowManager.LayoutParams.FLAG_FORCE_NOT_FULLSCREEN); 
getWindow().clearFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN); 
super.onCreate(savedInstanceState); 
Bundle b = getIntent().getExtras(); 
int layoutId = b.getInt("layout");
Log.d("====>>>", " " + layoutId);
setContentView(layoutId); 
setTitle("Title"); 
}
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onCreate()方法中的函数.我不工作.这是我的xml文件.

<ScrollView xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/ScrollView01"
android:layout_width="fill_parent"
android:layout_height="fill_parent" >

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent"
    android:layout_height="match_parent" android:paddingLeft="@dimen/activity_horizontal_margin"
    android:paddingRight="@dimen/activity_horizontal_margin"
    android:paddingTop="@dimen/activity_vertical_margin"
    android:paddingBottom="@dimen/activity_vertical_margin"
    tools:context="com.universityapp.enrollee.FacultyInformationActivity"
    android:scrollbars="vertical"
    >

     <TextView
        android:layout_width="fill_parent"
        android:layout_height="fill_parent"
        android:text="@string/text_faculty_information_agro"
        android:textSize="15dp"
        android:textAlignment="center"
    />
</RelativeLayout>
</ScrollView>
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我通过ListView启动活动:

 profListView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {

            switch (position){
                case 0:
                    facultyInfoIntent = new Intent(getBaseContext(), FacultyInformationActivity.class);
                    Bundle …
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xml layout android titlebar

3
推荐指数
2
解决办法
2万
查看次数

我的SQL SELECT查询有什么问题?

我试图从表中获取所有信息a,但得到错误:

ORA-00904:"A":无效的标识符.

这是我的查询:

SELECT a
FROM FORMS a,
     APPLICATIONS b
WHERE b.APPLICATION_ID = a.APPLICATION_ID
  AND a.APPLICATION_ID = 14980
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怎么了?

sql oracle

1
推荐指数
1
解决办法
71
查看次数

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